Parts and Whole Test 10

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Parts and Whole Test 10

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Weekly Quiz Competition

Question 1
1 / -0

Here is a collection of $$6$$ shapes. Of the $$6$$ shapes, $$5$$ are shaded. The fraction of the unshaded shapes is:

A
$$\displaystyle \frac{5}{6}$$

B
$$\displaystyle \frac{4}{6}$$

C
$$\displaystyle \frac{1}{6}$$

D
$$\displaystyle \frac{3}{6}$$

Solution

Total number of shapes $$=6$$
Total number of shaded shapes $$=5$$
Total number of unshaded shapes $$=1$$
So the fraction of unshaded shape is $$\frac{1}{6}$$..
Question 2
1 / -0

The model is shaded to show which fraction?

A
$$\displaystyle \frac{1}{4}$$

B
$$\displaystyle \frac{3}{4}$$

C
$$\displaystyle \frac{1}{3}$$

D
$$\displaystyle \frac{2}{3}$$

Solution

The given figure has $$4$$ equal parts in the shape of triangles.
Out of $$4$$, one part is shaded and $$3$$ parts are not shaded.
So, the fraction of shaded to the whole part is $$\dfrac{1}{4}$$.
Question 3
1 / -0

How many one-sevenths make one?

A
$$17$$

B
$$1$$

C
$$7$$

D
$$5$$

Solution

There are $$7$$ one seventh which make the one.
One seventh means $$\dfrac{1}{7}$$.
So, if add this one seventh seven times we will get the whole.
Hence, the answer is $$7$$.
Question 4
1 / -0

What fraction of the fruits (total $$8$$) on the plate are apples?

A
$$\displaystyle \frac{3}{8}$$

B
$$\displaystyle \frac{5}{8}$$

C
$$\displaystyle \frac{3}{5}$$

D
$$\displaystyle \frac{5}{3}$$

Solution

Total number of fruit is $$8$$.
The number of apple is $$3$$.
The fractional part of apple to the fruits is $$\dfrac{3}{8}$$.
Hence, the answer is $$\dfrac{3}{8}$$.
Question 5
1 / -0

Consider the shown figure represents the flag of a country. How much part of it is covered with stripes?

A
$$\dfrac{1}{4}$$

B
$$\dfrac{1}{3}$$

C
$$\dfrac{2}{3}$$

D
$$\dfrac{1}{2}$$

Solution

Total number of divisions in flag $$= 3$$
Striped divisions $$= 1$$

$$\Rightarrow$$ Part of flag covered with stripes $$=$$ Striped divisions $$\div$$ Total divisions $$= \dfrac{1}{3}$$
Question 6
1 / -0

Find the mean of the given fractions:
$$2\dfrac {1}{7}$$ and $$3\dfrac {1}{7}$$

A
$$\dfrac {37}{7}$$

B
$$\dfrac {19}{7}$$

C
$$\dfrac {37}{14}$$

D
$$2$$

Solution

The given fractions are
$$2\dfrac {1}{7}$$ and $$3\dfrac {1}{7}$$

$$Mean = \dfrac{\left (2\dfrac {1}{7}+3\dfrac {1}{7}\right )}{2} $$

$$= \dfrac{\left (\dfrac {15}{7} + \dfrac {22}{7}\right )}{2} $$

$$= \left (\dfrac {15 + 22}{7}\right ) \times \dfrac {1}{2}$$

$$ = \dfrac {37}{7}\times \dfrac {1}{2}$$

$$= \dfrac {37}{14}$$

Hence, the mean of the given fractions is $$ \dfrac {37}{14}$$ .
Question 7
1 / -0

A handkerchief is divided in four squares. Each part is to be embroidered with a flower. How much part has design of flower?

A
$$\dfrac{3}{4}$$

B
$$\dfrac{1}{4}$$

C
$$\dfrac{1}{2}$$

D
$$\dfrac{1}{3}$$

Solution

Total number of divisions in handkerchief $$= 4$$
Divisions with embroidery $$= 3$$

$$\Rightarrow$$ Parts with design $$=$$ Embroidered divisions $$\div$$ Total divisions $$= \dfrac{3}{4}$$
Question 8
1 / -0

What fraction is represented by all of these figures?

A
$$\dfrac{1}{2}$$

B
$$\dfrac{1}{3}$$

C
$$\dfrac{2}{3}$$

D
$$\dfrac{1}{4}$$

Solution

In the given first object, there are a total of $$2$$ rectangles and $$1$$ rectangle is shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

$$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 2 }$$

Now, consider the second object, there are a total of $$4$$ squares and $$2$$ squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

$$\dfrac {Shaded}{Total}=\dfrac {2 }{ 4 }=\dfrac {1}{2}$$

Now, in the third object, there are a total of $$6$$ rectangles and $$3$$ rectangles are shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

$$\dfrac {Shaded}{Total}=\dfrac { 3 }{ 6 }=\dfrac {1}{2}$$

Since the fraction of all of the three given objects is same that is $$\dfrac {1}{2}$$.

Hence, the fraction $$\dfrac {1}{2}$$ represented by all of the given figures.
Question 9
1 / -0

Write the equivalent fractions represented by the shaded portions of these figures.

A
$$\cfrac { 2 }{ 10 } =\cfrac { 3 }{ 5 } $$

B
$$\cfrac { 6 }{ 15 } =\cfrac { 2 }{ 5 } $$

C
$$\cfrac { 6 }{ 10 } =\cfrac { 2 }{ 5 } $$

D
$$\cfrac { 3 }{ 15 } =\cfrac { 1 }{ 5 } $$

Solution

Given: The shaded portion of the figures
Total boxes in the figure $$1=15$$
Shaded boxes in the figure $$1=6$$
Equivalent fraction $$=\dfrac{6}{15}$$ (figure 1)

Total boxes in the figure $$2=5$$
Shaded boxes in the figure $$2=2$$
Equivalent fraction $$=\dfrac{2}{5}$$ (figure 2)

$$\therefore$$ option B is correct.
Question 10
1 / -0

What fraction of the figure is shaded?

A
$$\displaystyle\frac{7}{16}$$

B
$$\displaystyle\frac{1}{2}$$

C
$$\displaystyle\frac{9}{16}$$

D
$$\displaystyle\frac{17}{32}$$

Solution

If we rearrange the figure then we can conclude that half of the square is shaded
$$\therefore$$ The total fraction of figure shaded is $$\dfrac{1}{2}$$
Hence the correct answer is option B.