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Self Studies

Knowing our Numbers Test - 16

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Knowing our Numbers Test - 16
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  • Question 1
    1 / -0
    Write $$14$$ in numeral form.
    Solution
    In Roman numeral form, 
    $$10 = X$$
    $$4 = IV$$

    $$\Rightarrow 14 = XIV$$
  • Question 2
    1 / -0
    In Roman Numeral $$C$$ has value of
    Solution
    In Roman numeral form, 
    $$100 = C$$
    $$50 = L$$
    $$1000 = M$$
    $$500 = D$$
  • Question 3
    1 / -0
    Find the greatest three-digit number using the digits $$7, 6, 3$$
    Solution
    The descending order of the given numbers $$7,6,3$$ is:

    $$7>6>3$$ 

    We observe that the smallest digit is $$3$$ and the largest digit is $$7$$, so the number should start with $$7$$ and end with $$3$$.
     
    Thus, the largest number formed is $$763$$.

    Hence, the greatest three digit number formed is $$763$$.
  • Question 4
    1 / -0
    Round off the following number to the nearest $$10$$ and $$100$$:
    $$1634$$
    Solution
    Rounding off $$1634$$ to nearest $$10$$ and $$100$$ we check if $$3$$ is less than $$5$$ or not,
    As $$3 < 5$$, we round it off to $$0$$

    $$\therefore 1634$$ to nearest $$10$$ equals $$1630$$ and nearest $$100$$ equals $$1600$$
  • Question 5
    1 / -0
    Milli starts from A and travels $$2$$ km and then come back for $$280$$ m. Then, the distance between point A and Milli is ?
    Solution
    Let us take the point of start A and point at a distant $$2$$km be B.
    $$AB=2$$km=$$2000$$m
    As she come back 280m , we assume that point be C.
    We have to find out the distance AC
    $$AC=AB-BC \therefore AC= 2000m - 280m = 1720m = 1 $$ km   $$720$$ m 
  • Question 6
    1 / -0
    Find a smallest three digit number using the digits $$4,7,9$$
    Solution
    Smallest three digit number which can be formed is if we arrange them in ascending order, i.e. $$479$$

    Hence $$479$$ is the smallest three digit number.
  • Question 7
    1 / -0
    Estimate $$5679-422$$ by rounding off each number to its greatest place.
    Solution
    $$\Rightarrow$$  The given two numbers are $$5679$$ and $$422$$.
    $$\Rightarrow$$  In number $$5679$$, its tens digit is $$7$$, which is greater than $$5$$. 
    $$\Rightarrow$$  So, we increase the digits at hundreds place by $$1$$ and replace each one of the digits at tens and ones place by $$0$$ to round off the given number to its greatest place.
    $$\therefore$$   Round off 5679 to its greatest place is $$5700$$
    $$\Rightarrow$$  In number $$422$$, its Itens digit is 2, which is less than 5. 
    $$\Rightarrow$$ So, we replace each of the tens and ones digits by 0 and keep the other digits as they are to round off the given number to its greatest.
    $$\therefore$$  Round off 422 to its greatest place is $$400$$
    $$\therefore$$   Required number = $$5700-400=5300$$
  • Question 8
    1 / -0
    By referring the given figure, identify the distance between $$A$$ and $$B$$.

    Solution
    For calculating the distance between $$A$$ and $$B$$, we need the sum of the distances between the points.
    $$AB=1+2+1+3+1+2=10$$ 

  • Question 9
    1 / -0
    Convert the following into grams :
    $$24\ kg$$
    Solution
    We know that

    $$1$$  $$kg =1000$$  $$grams$$

    $$1$$  $$gm =\dfrac1{1000}$$  $$kg$$

    Given That, we have to convert $$24$$  $$kg$$  to   $$gm$$

    $$24$$  $$kg =24 \times 1000$$  $$gm$$

                       $$=24,000$$  $$gm$$

    So, option $$B$$ is correct

  • Question 10
    1 / -0
    Convert $$6045\ m$$ into kilometres and metres.
    Solution
    We know that

    $$1$$  $$kilo meter =1000$$  $$m$$

    $$1$$  $$m =\dfrac1{1000}$$  $$km$$

    Given That, we have to convert $$6045$$  $$m$$  to   $$kilometer$$

    $$6045$$  $$m =\dfrac1{1000} \times 6045$$  $$km$$

                    $$=\dfrac{6045}{1000}   $$  $$km$$

                     $$= 6.045$$  $$kilo meter$$

    or    $$= 6$$  $$km$$  $$45 $$ $$m$$

    So, Option $$A$$ is correct
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