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Knowing our Numbers Test - 16

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Knowing our Numbers Test - 16
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  • Question 1
    1 / -0
    Write 1414 in numeral form.
    Solution
    In Roman numeral form, 
    10=X10 = X
    4=IV4 = IV

    14=XIV\Rightarrow 14 = XIV
  • Question 2
    1 / -0
    In Roman Numeral CC has value of
    Solution
    In Roman numeral form, 
    100=C100 = C
    50=L50 = L
    1000=M1000 = M
    500=D500 = D
  • Question 3
    1 / -0
    Find the greatest three-digit number using the digits 7,6,37, 6, 3
    Solution
    The descending order of the given numbers 7,6,37,6,3 is:

    7>6>37>6>3 

    We observe that the smallest digit is 33 and the largest digit is 77, so the number should start with 77 and end with 33.
     
    Thus, the largest number formed is 763763.

    Hence, the greatest three digit number formed is 763763.
  • Question 4
    1 / -0
    Round off the following number to the nearest 1010 and 100100:
    16341634
    Solution
    Rounding off 16341634 to nearest 1010 and 100100 we check if 33 is less than 55 or not,
    As 3<53 < 5, we round it off to 00

    1634\therefore 1634 to nearest 1010 equals 16301630 and nearest 100100 equals 16001600
  • Question 5
    1 / -0
    Milli starts from A and travels 22 km and then come back for 280280 m. Then, the distance between point A and Milli is ?
    Solution
    Let us take the point of start A and point at a distant 22km be B.
    AB=2AB=2km=20002000m
    As she come back 280m , we assume that point be C.
    We have to find out the distance AC
    AC=ABBCAC=2000m280m=1720m=1AC=AB-BC \therefore AC= 2000m - 280m = 1720m = 1 km   720720
  • Question 6
    1 / -0
    Find a smallest three digit number using the digits 4,7,94,7,9
    Solution
    Smallest three digit number which can be formed is if we arrange them in ascending order, i.e. 479479

    Hence 479479 is the smallest three digit number.
  • Question 7
    1 / -0
    Estimate 56794225679-422 by rounding off each number to its greatest place.
    Solution
    \Rightarrow  The given two numbers are 56795679 and 422422.
    \Rightarrow  In number 56795679, its tens digit is 77, which is greater than 55
    \Rightarrow  So, we increase the digits at hundreds place by 11 and replace each one of the digits at tens and ones place by 00 to round off the given number to its greatest place.
    \therefore   Round off 5679 to its greatest place is 57005700
    \Rightarrow  In number 422422, its Itens digit is 2, which is less than 5. 
    \Rightarrow So, we replace each of the tens and ones digits by 0 and keep the other digits as they are to round off the given number to its greatest.
    \therefore  Round off 422 to its greatest place is 400400
    \therefore   Required number = 5700400=53005700-400=5300
  • Question 8
    1 / -0
    By referring the given figure, identify the distance between AA and BB.

    Solution
    For calculating the distance between AA and BB, we need the sum of the distances between the points.
    AB=1+2+1+3+1+2=10AB=1+2+1+3+1+2=10 

  • Question 9
    1 / -0
    Convert the following into grams :
    24 kg24\ kg
    Solution
    We know that

    11  kg=1000kg =1000  gramsgrams

    11  gm=11000gm =\dfrac1{1000}  kgkg

    Given That, we have to convert 2424  kgkg  to   gmgm

    2424  kg=24×1000kg =24 \times 1000  gmgm

                       =24,000=24,000  gmgm

    So, option BB is correct

  • Question 10
    1 / -0
    Convert 6045 m6045\ m into kilometres and metres.
    Solution
    We know that

    11  kilometer=1000kilo meter =1000  mm

    11  m=11000m =\dfrac1{1000}  kmkm

    Given That, we have to convert 60456045  mm  to   kilometerkilometer

    60456045  m=11000×6045m =\dfrac1{1000} \times 6045  kmkm

                    =60451000  =\dfrac{6045}{1000}     kmkm

                     =6.045= 6.045  kilometerkilo meter

    or    =6= 6  kmkm  4545 mm

    So, Option AA is correct
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