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Knowing our Numbers Test - 17

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Knowing our Numbers Test - 17
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  • Question 1
    1 / -0
    Jessica walks $$2\ km$$ a day. How many meters does she walk in two days ?
    Solution
    given that 
    Jessica walks $$2 km$$ a day.
    Total distance travelled by Jessica in TWO days  is $$2 \times 2 =4km$$
    We know that
    $$1$$  $$kilometer =1000$$  $$m$$
    $$1$$  $$m =\dfrac1{1000}$$  $$km$$
    Given That, we have to convert $$4$$  $$km$$ into $$m$$
    $$4$$  $$km =4 \times 1000$$  $$m$$
                $$=4000$$  $$m$$
    So, Option $$C $$ is correct 
  • Question 2
    1 / -0
    Distance between two houses is $$40$$ m. If a new house with area $$4\times 4$$ is constructed in the middle of $$2$$ houses, then find the distance between middle house and one of the corner house.
    Solution
    The distance of middle point of middle house from the corner house is $$\dfrac { 40 }{ 2 } =20$$ and house to house distance will be $$\therefore 20-2=18$$
    The distance between he Middle house and Corner house will be $$18$$ m.

  • Question 3
    1 / -0
    By referring the given figure, identify the distance between $$A$$ and $$C$$.

    Solution
    For calculating the distance between $$A$$ and $$C$$, we need the sum of the distances between the points.
    $$AC=1+2+1+1.5=5.5$$ 
  • Question 4
    1 / -0
    Rosy measured a line for his art project. It is $$400$$ millimeters long. How many centimeters is the line?
    Solution
    The total length of the line is $$400$$ mm.
    We know that $$1$$  $$\text{centimeter} =10$$ $$\text{millimeters}$$
    $$1$$ mm $$=\dfrac1{10}$$ cm
    We have to convert the $$400$$ mm to cm.
    $$400$$ mm $$ =\dfrac1{10} \times 400$$ cm
    $$=\dfrac{400}{10}   $$ cm
    $$= 40  $$   $$\text{centimeter}$$
    The line is  $$40$$ cm long.
    So, option A is correct.
  • Question 5
    1 / -0
    Round-off $$4353$$ to nearest $$100$$.
    Solution
    $$\Rightarrow$$  The given number is $$4353$$
    $$\Rightarrow$$  In number 4353, its tens digit is 5, which is equal to 5. 
    $$\Rightarrow$$  So, we increase the digits at hundreds place by 1 and replace each one of the digits at tens and ones place by 0 to round off the given number to nearest to 100.
    $$\therefore$$   The number becomes $$4400$$
  • Question 6
    1 / -0
    Round-off $$3789$$ to nearest $$100$$
    Solution
    $$\Rightarrow$$  The given number is $$3789$$
    $$\Rightarrow$$  In number 3789, its tens digit is 8, which is greater than 5. 
    $$\Rightarrow$$  So, we increase the digits at hundreds place by 1 and replace each one of the digits at tens and ones place by 0 to round off the given number to nearest to 100.
    $$\therefore$$   The number becomes $$3800$$
  • Question 7
    1 / -0
    Round-off $$52,398$$ to nearest $$1000$$.
    Solution
    $$\Rightarrow$$  The given number is $$52,398$$
    $$\Rightarrow$$  In number $$52398$$, its hundred digit is $$3$$, which is less than $$5$$. 
    $$\Rightarrow$$  So, we replace each one of the digits at hundreds, tens and ones place by $$0$$ to round off the given number to nearest $$1000$$.
    $$\therefore$$   The number obtained is $$52,000$$
  • Question 8
    1 / -0
    Round-off $$76,890$$ to nearest $$10$$.
    Solution
    $$\Rightarrow$$   The given number is $$76,890$$.
    $$\Rightarrow$$   In number 76890, its unit digit is $$0$$, which is already nearest to 10.
    $$\Rightarrow$$  So, don't need to change anything.
    $$\therefore$$   $$76,890$$ is nearest to 10.
  • Question 9
    1 / -0
    Round-off $$47,897$$ to nearest $$1000$$.
    Solution
    $$\Rightarrow$$  The given number is $$47,897$$
    $$\Rightarrow$$  In number 47897, its hundred digit is 8, which is greater than 5. 
    $$\Rightarrow$$  So, we increase the digits at thousand place by 1 and replace each one of the digits at hundreds, tens and ones place by $$0$$ to round off the given number to nearest to 1000.
    $$\therefore$$   The number becomes $$48,000$$
  • Question 10
    1 / -0
    If Tina weighs $$\dfrac{2}{3}$$times than Reema and Reema weighs $$45$$ kg, then Tina's weight is
    Solution
    Weight of Reema $$=w=45\ \ Kg$$
    Weight of Tina $$=\dfrac{2}{3}w=\dfrac{2}{3}\times{45}=30\ \ Kg$$
    Option $$B$$ is correct.
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