Fractions Test

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Fractions Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

........... + $$\displaystyle \frac {4}{7}\, =\, 1$$

A
$$\displaystyle \frac {4}{7}$$

B
$$1$$

C
$$\displaystyle \frac {3}{7}$$

D
$$\displaystyle \frac {7}{4}$$

Solution

$$1\, -\, \displaystyle \frac {4}{7}\, =\, \displaystyle \frac {7-1}{7}\, =\, \displaystyle \frac {3}{7}$$
Question 2
1 / -0

Out of the rational numbers $$\displaystyle {\frac{-5}{11},\, \frac{-5}{12},\, \frac{-5}{17}}$$, which is greater ?

A
$$\displaystyle \frac{-5}{11}$$

B
$$\displaystyle \frac{5}{-12}$$

C
$$\displaystyle \frac{-5}{17}$$

D
None of these

Solution

$$\displaystyle {\frac{-5}{11},\, \frac{-5}{12},\, \frac{-5}{17}}$$
$$\because$$ All have same numerator. Sothe rational number having theleast denominator is the greatest.But here all have negative sign.So, the number having greatestdenominator is greater. Hence, $$\displaystyle \frac{-5}{17}$$ is greater
Question 3
1 / -0

The sum of $$\displaystyle \frac {8}{15}$$ and $$\displaystyle \frac {7}{15}$$ is ..........

A
$$1$$

B
$$\displaystyle \frac {1}{15}$$

C
$$\displaystyle \frac {1}{30}$$

D
None

Solution

$$\displaystyle \frac {8}{15}\, +\, \displaystyle \frac {7}{15}\, =\, \displaystyle \frac {8+7}{15}\, =\, \displaystyle \frac {15}{15}\, =\, 1$$
Question 4
1 / -0

Which number should come in place of $$\square$$ ?
$$\displaystyle \frac {1}{7}\, +\, \displaystyle \frac {2}{7}\, +\, \displaystyle \frac {\square }{7}\, =\, 1\displaystyle \frac {3}{7}$$

A
1

B
2

C
3

D
7

Solution

$$\displaystyle \frac {10}{7}\, -\, \displaystyle \frac {1}{7}\, -\, \displaystyle \frac {2}{7}\, =\, \displaystyle \frac {10-1-2}{7}\, =\, \displaystyle \frac {7}{7}$$
Question 5
1 / -0

$$2\, -\, \displaystyle {\frac{11}{39}\, +\, \frac{5}{26}}$$ = ............

A
$$\displaystyle \frac{149}{39}$$

B
$$1\, +\, \displaystyle \frac{71}{78}$$

C
$$\displaystyle \frac{149}{76}$$

D
$$\displaystyle \frac{149}{98}$$

Solution

Given: $$\displaystyle {\frac{2}{1}\, -\, \frac{11}{39}\, +\, \frac{5}{26}}$$

Factors of $$39=3\times 13$$
Factors of $$26=2\times 13$$

$$LCM(39,26)=2\times 3\times 13=78$$

$$\displaystyle {\frac{2}{1}\, -\, \frac{11}{39}\, +\, \frac{5}{26}}$$ $$=\, \displaystyle {\frac{2\times 78\, -\, 11\times 2\, +\, 5\times 3}{78}\, }$$

$$=\, \displaystyle {\frac{156\, -\, 22\, +\, 15}{78}\, =\, \frac{149}{78}}$$

$$=\, 1\displaystyle {\frac{71}{78}\, =\, 1\, +\, \frac{71}{78}}$$
Question 6
1 / -0

In Krishna's flower garden, $$\dfrac{1}{7}$$ are white roses, $$\dfrac{4}{7}$$ are red roses and the rest are yellow roses. What fraction of the roses are yellow?

A
$$\displaystyle \frac {1}{7}$$

B
$$\displaystyle \frac {2}{7}$$

C
$$\displaystyle \frac {3}{7}$$

D
$$\displaystyle \frac {4}{7}$$

Solution

Let the total number of yellow roses be $$x$$

Hence, $$\dfrac{1}{7} + \dfrac{4}{7} + x = 1$$
$$\Rightarrow \dfrac{(1 + 4 + 7x) }{7} = 1$$
$$\Rightarrow \dfrac{(5 + 7x) }{ 7} = 1$$
$$\Rightarrow 5 + 7x = 7$$ [ by cross multiplication]
$$\Rightarrow 7x = 7 - 5$$
$$\Rightarrow 7x = 2$$
$$\Rightarrow x = \dfrac{2}{7}$$
$$\therefore $$ The fraction of yellow roses are $$\dfrac{2}{7}$$
Question 7
1 / -0

Which of the following is not a proper fraction ?

A
$$ \displaystyle \frac{2}{3} $$

B
$$ \displaystyle \frac{3}{4} $$

C
$$ \displaystyle \frac{5}{7} $$

D
$$ \displaystyle \frac{6}{5} $$

Solution

Proper fraction is a fraction that is less than one, with the numerator less than the denominator.
So, option $$D$$ is correct.
Question 8
1 / -0

Which of the following is not a proper fraction?

A
$$\cfrac {2}{3}$$

B
$$\cfrac {3}{4}$$

C
$$\cfrac {5}{7}$$

D
$$\cfrac {6}{5}$$

Solution

Fractions that are greater than $$0$$ but less than $$1$$ are called proper fractions.

In proper fractions, the numerator is less than the denominator.

When a fraction has a numerator that is greater than or equal to the denominator, then the fraction is an improper fraction.

An improper fraction is always $$1$$ or greater than $$1$$.

Now looking at options

$$\dfrac{2}{3}=.666 < 1$$

$$\dfrac{3}{4}= .75 < 1$$

$$\dfrac{5}{7}= .71 <1$$

$$\dfrac{6}{5}=1.2 > 1$$

So $$\dfrac{6}{5}$$ is Not a Proper fraction.

So option $$D$$ is correct.
Question 9
1 / -0

A quantity which expresses a part of the whole is called a/an:

A
fraction

B
prime number

C
integer

D
none of these

Solution

By definition fraction is a quantity which express the part of any whole number. So correct answer will be option A
Question 10
1 / -0

Which of the following is not an improper fraction?

A
$$ \displaystyle \frac{4}{3} $$

B
$$ \displaystyle \frac{3}{2} $$

C
$$ \displaystyle \frac{5}{3} $$

D
$$ \displaystyle \frac{7}{11} $$

Solution

Proper fraction is a fraction that is less than one, with the numerator less than the denominator.
Option $$D$$ is correct.

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Re-Attempt Weekly Quiz Competition

Fractions Test - 12

Result

Fractions Test - 12

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Question 1

$$\displaystyle \frac {4}{7}$$

$$1$$

$$\displaystyle \frac {3}{7}$$

$$\displaystyle \frac {7}{4}$$

Solution

Question 2

$$\displaystyle \frac{-5}{11}$$

$$\displaystyle \frac{5}{-12}$$

$$\displaystyle \frac{-5}{17}$$

None of these

Solution

Question 3

$$1$$

$$\displaystyle \frac {1}{15}$$

$$\displaystyle \frac {1}{30}$$

None

Solution

Question 4

1

2

3

7

Solution

Question 5

$$\displaystyle \frac{149}{39}$$

$$1\, +\, \displaystyle \frac{71}{78}$$

$$\displaystyle \frac{149}{76}$$

$$\displaystyle \frac{149}{98}$$

Solution

Question 6

$$\displaystyle \frac {1}{7}$$

$$\displaystyle \frac {2}{7}$$

$$\displaystyle \frac {3}{7}$$

$$\displaystyle \frac {4}{7}$$

Solution

Question 7

$$ \displaystyle \frac{2}{3} $$

$$ \displaystyle \frac{3}{4} $$

$$ \displaystyle \frac{5}{7} $$

$$ \displaystyle \frac{6}{5} $$

Solution

Question 8

$$\cfrac {2}{3}$$

$$\cfrac {3}{4}$$

$$\cfrac {5}{7}$$

$$\cfrac {6}{5}$$

Solution

Question 9

fraction

prime number

integer

none of these

Solution

Question 10

$$ \displaystyle \frac{4}{3} $$

$$ \displaystyle \frac{3}{2} $$

$$ \displaystyle \frac{5}{3} $$

$$ \displaystyle \frac{7}{11} $$

Solution

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