Perimeter and Area Test

Result

Perimeter and Area Test - 35

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Weekly Quiz Competition

Question 1
1 / -0

The area of triangle with base $$4\ cm$$ and height is $$3\ cm$$

A
$$6\ cm^2$$

B
$$12\ cm^2$$

C
$$24\ cm^2$$

D
$$3\ cm^2$$

Solution

The area of triangle is
$$=\dfrac 12\times height \times base \\=\dfrac 12\times 3\times 4=3\times 2=6\ cm^2$$
Question 2
1 / -0

If the area of a circle is $$154{ cm }^{ 2 }$$, then the perimeter is

A
11 cm

B
22 cm

C
44 cm

D
55 cm

Solution
Question 3
1 / -0

The radius of two concentric circles is $$4\ cm$$ and $$3\ cm.$$ The area of the bounded region will be:-

A
$$22\ cm^{2}$$

B
$$12\ cm^{2}$$

C
$$32\ cm^{2}$$

D
$$18\ cm^{2}$$

Solution

Given:-
$$R=4\ cm$$
$$r=3\ cm$$

Hence, the area of the bounded region will be,
$$A=\pi (R^2-r^2)$$

$$=\dfrac {22}7(16-9)$$

$$=\dfrac {22}7\times 7\ cm^2$$
Question 4
1 / -0

If The side and altitude of a parallelogram are 9 cm and 6 cm respectively, then its area is

A
$$27 cm ^{2}$$

B
$$236cm ^{2}$$

C
$$54 cm ^{2}$$

D
$$45 cm ^{2}$$

Solution

the area of a parallelogram is the product of a side and height or altitude.
here Side =$$9 cm$$, Altitude=$$6cm$$
so, area= $$9\times6$$sq. cm=$$54 $$sq. cm
Question 5
1 / -0

By converting the 80.2km into the hectare, the answer will be

A
0.08020ha

B
8020ha

C
802ha

D
0.802ha

Solution
Question 6
1 / -0

By converting the 4.8mm into the cm, the answer will be

A
0.048cm

B
0.48cm

C
48cm

D
480cm

Solution
Question 7
1 / -0

Ram has a plate in circular form which has design in $$7$$ meter radius .Find the area of design in $$cm^2$$

A
$$154cm^2$$

B
$$15400cm^2$$

C
$$1540000cm^2$$

D
$$.154cm^2$$

Solution

Radius of circular plate $$(r)=7\space\mathrm{m}$$
$$=7\times100\space\mathrm{cm}\quad[\because 1\space\mathrm{m}=100\space\mathrm{cm}]$$
$$=700\space\mathrm{cm}$$
Now, Area of design $$=\pi r^2$$
$$=\dfrac{22}{7}\times700^2$$
$$=1540000\space\mathrm{cm^2}$$
So, $$\text{C}$$ is the correct option.
Question 8
1 / -0

By converting the $$0.0287m^2$$ into the $$cm^2$$, the answer will be

A
$$28.7 \, cm^2$$

B
$$2870 \, cm^2$$

C
$$287 \, cm^2$$

D
None of these

Solution
Question 9
1 / -0

Area of parallelogram ABCD is not equal to.

A
$$DE \times DC $$

B
$$BE \times AD$$

C
$$BF \times DC $$

D
$$ BE \times DC$$

Solution

Option (a) is correct.
Area of parallelogram $$=$$ Base $$\times$$ corresponding height
Hence, area of parallelogram $$ABCD $$
$$AD \times BE =BC \times BE $$
$$\because [AD//BC] $$
Also,
$$BF\times CD =BF\times AB$$
$$\because[AB //CD]$$
Question 10
1 / -0

Ratio of areas of $$\Delta MNO, \Delta MOP $$ and $$ \Delta MPQ$$ in Fig. is

A
$$2: 1: 3 $$

B
$$1: 3:2 $$

C
$$2: 3: 1 $$

D
$$ 1:2:3$$

Solution

Option (a) is correct
Area of triangle $$MNO = \frac {1}{2} \times NO \times MO$$
$$=10\, cm^2$$
Area of triangle $$MOP= \frac{1}{2} \times PQ \times MQ $$
$$\frac {1}{2} \times 2 \times 5$$
$$= 5\, cm^2$$
Therefore, $$=105$$
Area of triangle $$MOP= \frac{1}{2} \times PQ \times MQ $$
$$\frac {1}{2} \times 6 \times 5$$
$$= 15\, cm^2$$
Therefore, required ratio $$ =10:5:15 =2:1:3$$