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Exponents and Powers Test - 15

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Exponents and Powers Test - 15
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  • Question 1
    1 / -0
    Write $$4.5\times 10^5$$ in decimal form
    Solution
    $$4.5\times 10^5=450000$$
    Ans-Option $$A$$.
  • Question 2
    1 / -0
    In $$10^{2}$$, the exponent is
    Solution
    In the expression $$a^b$$, $$a$$ is known as base and $$b$$ is known as exponent so, in $$10^2$$, $$2$$ is the exponent.
  • Question 3
    1 / -0
    Write in scientific notation: $$(400000)^4$$
    Solution
    $$(400000)^4=4^4\times 10^{20}$$
    $$\Rightarrow (400000)^4=256\times 10^{20}=2.56\times 10^{22}$$
    Ans-Option $$C$$.
  • Question 4
    1 / -0
    Write the following in scientific notation: $$(200)^3$$
    Solution
    $$(200)^3=2^3\times 10^6$$
    $$\Rightarrow (200)^3=8\times 10^6$$
    Ans-Option $$B$$.
  • Question 5
    1 / -0
    Write $$1000000+200000+70000$$ in scientific notation.
    Solution
    $$1000000+200000+70000=1270000$$
    $$\therefore 12700000=1.27\times 10^6$$
    Ans-Option $$B$$.
  • Question 6
    1 / -0
    Simplify :
    $$\dfrac {x^{30}}{x^{10}}$$ 
    Solution
    Using law of exponent $$\dfrac {a^m}{a^n}=(a)^{m-n}$$ Where, $$a$$ is non-zero integer
    Therefore, $$\dfrac {(x)^{30}}{(x)^{10}}=(x)^{30-10}=(x)^{20}$$
  • Question 7
    1 / -0
    Simplify the following using law of exponents.
    $$2^{10}\times 2^4$$
    Solution
    we know that,

    $$\because a^m \times a^n=a^{m+n}$$

    so,
    $$2^{10}\times 2^4$$

    $$=2^{10+4}$$

    $$=2^{14}$$
  • Question 8
    1 / -0
    Simplify the following using law of exponents.
    $$(3^2)\times (3^2)^4$$
    Solution
    we know that,

    $$\because a^m*a^n=a^{m+n}$$

    and

    $$\because (a^m)^n=a^{mn}$$

    so,

    $$(3^2)*(3^2)^4=(3^2)(3^8)$$

    $$=3^{10}$$
  • Question 9
    1 / -0
    Simplify the following using law of exponents.
    $$\dfrac{5^7}{5^2}$$
    Solution
    we know,

    $$\dfrac{a^{m}}{a^{n}}=a^{m-n}$$

    so,

    $$\dfrac{5^{7}}{5^{2}}=5^{7-2}$$

    $$=5^{5}$$






  • Question 10
    1 / -0
    Evaluate $$2^0+3^0$$
    Solution

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