Comparing Quantities Test

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Comparing Quantities Test - 26

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Question 1
1 / -0

A man buys pencils at the rate of $$6$$ for Rs. $$ 5$$ and sells them at $$5$$ for Rs. $$ 6$$. What is his profit $$\%$$?

A
$$30$$

B
$$35$$

C
$$40$$

D
$$44$$

Solution

C.P. of $$1$$ pencil $$=$$ Rs. $$\dfrac {5}{6}$$
S.P. of 1 pencil $$=$$ Rs. $$\dfrac {6}{5}$$
$$\therefore$$ Profit $$=$$ S.P. $$-$$ C.P.
$$=$$ Rs. $$\left ( \dfrac {6}{5}-\dfrac {5}{6} \right )=\dfrac {36-25}{30}=$$ Rs. $$\dfrac {11}{30}$$
$$\therefore $$ Profit $$\% =$$ $$\left (\dfrac {11/30}{5/6}\times 100 \right )$$ $$\%$$
$$=\left (\dfrac {11}{30}\times \dfrac {6}{5}\times 100 \right )$$ $$\%=44\%$$
Question 2
1 / -0

An item costing Rs. $$ 840$$ was sold by a shopkeeper at a gain of $$10 \%$$ and it was again sold by the new buyer at a loss of $$5 \%$$.The final selling price of the item is:

A
Rs. $$ 877.80$$

B
Rs. $$798$$

C
Rs. $$ 924$$

D
Rs. $$ 37.80$$

Solution

$$C.P.$$ $$=$$ Rs. $$840$$
$$Gain$$ $$=10\%$$

$$S.P.$$ $$=\dfrac{100+\text {gain percentage}}{100}\times$$ $$C.P$$

$$S.P.$$ $$=\dfrac{100+10}{100}\times 840$$

$$\Rightarrow \dfrac{110}{100}\times 840=$$ Rs. $$924$$

Selling price of the shopkeeper is the cost price of the new buyer.

Then $$C.P.$$ $$=$$ Rs. $$924$$

$$Loss$$ $$=5\%$$

$$S.P.$$ $$=\dfrac{100-\text {loss percentage}}{100}\times$$ $$C.P.$$

$$S.P$$ $$=\dfrac{100-5}{100}\times 924$$

$$\Rightarrow \dfrac{95}{100}\times 924=$$ Rs. $$877.80$$

Hence, final $$S.P. $$=Rs. $$877.80$$
Question 3
1 / -0

The profit earned after selling an article for Rs. $$625$$ is the same as loss incurred after selling the article for Rs. $$435$$. What is the cost price of the article?

A
Rs $$530$$

B
Rs $$520$$

C
Rs $$540$$

D
Rs $$550$$

Solution

Let the $$C.P.$$=Rs $$x$$
Then according to the question
$$625-x=x-435$$
$$2x=625+435$$
$$2x=1060$$
$$x=530$$
Hence $$C.P.$$ of the article =Rs.$$530$$
Question 4
1 / -0

A trader purchased an old bicycle for Rs. $$ 480$$. He spent $$20 \%$$ of the cost on its repair. If he wants to earn Rs. $$144$$ as net profit on it, find profit $$\%$$.

A
$$50\%$$

B
$$48\%$$

C
$$96\%$$

D
$$100\%$$

Solution

Cost price $$=$$ Rs. $$480$$
Repair cost $$= 20\%$$ of Rs. $$480$$ $$=\dfrac{20}{100}\times 480=$$ Rs. $$96 $$
$$\therefore $$Total cost $$=$$ C.P. $$+$$ Repair cost
$$\Rightarrow$$ Rs. $$480 +$$ Rs. $$ 96 =$$ Rs. $$576$$
Net profit $$=$$ Rs. $$144$$
$$\therefore $$ S.P. = Total cost + Net profit
$$\Rightarrow $$ Rs. $$576 +$$ Rs. $$ 144 =$$ Rs. $$ 720$$
Profit $$=$$ S.P. $$-$$ C.P.
$$=720-480=$$ Rs. $$240$$
Now profit $$\% =$$ $$=\dfrac {240}{480}\times $$ $$100 =50\%$$
Question 5
1 / -0

A car worth Rs. $$\ 1,50,000$$ was sold by $$X$$ to $$Y$$ at $$5 \%$$ profit. $$Y$$ sold the car back to $$X$$ at $$20 \%$$ loss. Therefore who gained in the entire transaction?

A
$$X$$ gained Rs. $$ 31500$$

B
$$X$$ lost Rs. $$ 43500$$

C
$$X$$ gained Rs. $$ 3150$$

D
$$X$$ lost Rs. $$ 315000$$

Solution

The cost price of car for $$X=$$ Rs. $$150000$$
Then selling price to $$X$$ at $$5\%$$ profit $$=$$ cost price of car to $$y$$ $$=$$ $$\dfrac{150000\times 105}{100}=$$ Rs. $$ 157500$$
But $$Y$$ sell car to $$X$$ at $$20\%$$ loss
Then selling price of car to $$Y$$ $$=$$ cost price of car $$x$$ back $$=$$ $$\dfrac{157500\times 80}{100}= $$ Rs. $$126000$$
Then Profit to $$X$$ in the entire transaction $$=157500-126000=$$ Rs. $$31500$$.
Question 6
1 / -0

The cost price of 19 chairs is equal to selling price of 16 chairs.The gain % is:

A
$$\displaystyle 3\frac{9}{17}$$%

B
$$\displaystyle 15\frac{15}{19}$$%

C
$$\displaystyle 18\frac{3}{4}$$%

D
$$\displaystyle 16\frac{1}{3}$$%

Solution

Let $$C.P.$$ of $$1$$ chair = Rs$$1$$

$$C.P.$$ of $$19$$ chairs = Rs. $$19$$

$$C.P.$$ of $$16$$ chairs = Rs. $$16$$

$$S.P.$$ of $$16$$ chairs =$$C.P.$$ of $$19$$ chairs = Rs. $$19$$

$$Profit$$ $$= SP-CP$$ = Rs.$$3$$

∴% $$Gain$$ =$$\dfrac{SP-CP}{CP}\times 100=\dfrac{3\times 100}{16}=18\dfrac{3}{4} $$%
Question 7
1 / -0

What is the profit percent if the cost price of $$50$$ oranges is equal to the selling price of $$40$$ oranges?

A
$$12.5\%$$

B
$$25\%$$

C
$$35\%$$

D
$$40\%$$

Solution

Let the S.P. of $$1$$ oranges $$=$$ Rs. $$1$$
Then, C.P. of $$50$$ oranges $$=$$ S.P. of $$40$$ oranges $$=$$ Rs. $$40$$
S.P. of $$50$$ oranges $$=$$ Rs. $$50$$
Profit $$=$$ Rs. $$50-$$ Rs. $$40=$$ Rs. $$10$$
Profit $$\%=$$ $$ \left ( \dfrac {10}{40}\times 100 \right )$$ $$\%=25 \%$$
Question 8
1 / -0

A man sold a watch for Rs. $$600$$ at a loss. Had he sold if for Rs. $$750$$, his gain would have been double the former loss. The cost price of the watch is.

A
Rs. $$800$$

B
Rs. $$700$$

C
Rs. $$670$$

D
Rs. $$650$$

Solution

Let the cost price of watch is Rs. $$x$$
Then loss $$=$$ Rs. $$x-600$$
If watch sold Rs. $$750$$, then profit $$=$$ Rs. $$750-x$$
Given gain has been double the loss
Then $$750-x=2(x-600)$$
$$\Rightarrow 750-x=2x-1200$$
$$\Rightarrow x=650$$
Therefore, the cost price of the watch is Rs. $$650$$.
Question 9
1 / -0

A man bought a second hand car for Rs. $$76000$$ and a TV, for Rs. $$27500$$. He sold the car at a gain of $$15\%$$ and the T.V. at a loss of $$12\%$$. Find the total amount gained or lost from the two transactions.

A
lost Rs. $$1800$$

B
gained Rs. $$1800$$

C
gained Rs. $$8100$$

D
lost Rs. $$8100$$

Solution

Total $$C.P.$$ of Car and TV $$ 76000 + 27500 = 103500$$
Car he sold on $$15\%$$ profit , so $$S.P.$$ of Car $$= 76000 + 76000 \times \dfrac{15}{100} = 76000+11400 = 87400$$
TV he sold on $$12\%$$ loss, $$S.P.$$ of TV $$= 27500 - 27500 \times \dfrac{12}{100} = 27500 - 3300 = 24200$$
Total Salling price $$= 87400 + 24200 = 111600$$
$$Gain = SP - CP$$
$$ = 111600 - 103500 = 8100$$
Question 10
1 / -0

A Shopkeeper purchased $$70$$ kg of potatoes for Rs $$420$$ and sold the whole lot at the rate of Rs $$6.50$$ per kg. What will be his gain percent?

A
$$2 \dfrac {1}{2}$$ %

B
$$6 \dfrac {3}{7}$$ %

C
$$7 \dfrac {1}{5}$$ %

D
$$8 \dfrac {1}{3}$$ %

Solution

C.P of $$1$$ kg potato $$=\dfrac{420}{70}=$$ Rs. $$6$$ per kg
S.P of $$1$$ kg potato $$=$$ Rs $$6.50$$ per kg

Gain $$=$$ S.P - C.P $$=6.50-6.00=0.50$$

Gain $$\% =\dfrac{0.50}{6}\times 100=8\dfrac{1}{3}\%$$

Hence, option D.

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Comparing Quantities Test - 26

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Comparing Quantities Test - 26

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SHARING IS CARING

Question 1

$$30$$

$$35$$

$$40$$

$$44$$

Solution

Question 2

Rs. $$ 877.80$$

Rs. $$798$$

Rs. $$ 924$$

Rs. $$ 37.80$$

Solution

Question 3

Rs $$530$$

Rs $$520$$

Rs $$540$$

Rs $$550$$

Solution

Question 4

$$50\%$$

$$48\%$$

$$96\%$$

$$100\%$$

Solution

Question 5

$$X$$ gained Rs. $$ 31500$$

$$X$$ lost Rs. $$ 43500$$

$$X$$ gained Rs. $$ 3150$$

$$X$$ lost Rs. $$ 315000$$

Solution

Question 6

$$\displaystyle 3\frac{9}{17}$$%

$$\displaystyle 15\frac{15}{19}$$%

$$\displaystyle 18\frac{3}{4}$$%

$$\displaystyle 16\frac{1}{3}$$%

Solution

Question 7

$$12.5\%$$

$$25\%$$

$$35\%$$

$$40\%$$

Solution

Question 8

Rs. $$800$$

Rs. $$700$$

Rs. $$670$$

Rs. $$650$$

Solution

Question 9

lost Rs. $$1800$$

gained Rs. $$1800$$

gained Rs. $$8100$$

lost Rs. $$8100$$

Solution

Question 10

$$2 \dfrac {1}{2}$$ %

$$6 \dfrac {3}{7}$$ %

$$7 \dfrac {1}{5}$$ %

$$8 \dfrac {1}{3}$$ %

Solution

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