Self Studies

Comparing Quantities Test - 27

Result Self Studies

Comparing Quantities Test - 27
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    A hawker gains the selling price of $$4$$ gel pens on selling $$1$$ dozen pens. What is his gain percentage ?
    Solution
    S.P. of $$12$$ gel Pens-C.P. of $$12$$ gel pens= S.P. of $$4$$ gel pens
    $$\Rightarrow $$ C.P. of 12 gel pens=S.p. of 8 gel pens
    Let the S.P. of 1 gel pen = Rs. 1. then
    C.P. of 12 gel pesn= Rs. 8
    S.P. of 12 gel pesn= Rs. 12
    $$\therefore $$ Gian= Rs. 12- Rs. 8= Rs. 4
    Gain %=$$\left ( \dfrac {4}{8}\times 100 \right )$$ %=50%
  • Question 2
    1 / -0
    The cost of manufacturing an article is Rs. $$160$$. The manufacturer sells it to a dealer at a gain of $$45$$% and the dealer sells it to the customer for Rs. $$266.80$$. Find the dealer's percentage gain?
    Solution

    The cost of manufacturing an article is Rs. $$160$$. The manufacturer sells it to a dealer at a gain of $$45$$%

    Then selling price =$$\dfrac{160\times 145}{100}=232$$Rs

    Dealer sell it Rs $$266.80$$ to the customer 

    Profit =$$266.80-232=34.80$$ RS

    % of profit =$$\dfrac{34.80\times 100}{232}=15$$%

  • Question 3
    1 / -0
    The ratio between the sale price and cost price of an article is $$7: 5$$. What is the ratio between the profit and the cost price of that article ?
    Solution
    The ratio between the sale price and cost price of an article is $$7x: 5x.$$
    Then the profit becomes $$7x - 5x$$ which is $$2x$$.
    So, the ratio between profit and cost price is $$2x : 5x $$ or $$2 : 5$$.
  • Question 4
    1 / -0
    A man bought $$200 $$ pencils for Rs. $$60$$. He found that $$10$$ $$\%$$ of them were broken and sold the rest at $$36$$ paise each. His profit per cent is.
    Solution

    C.P of $$200$$ Pencil Rs. $$60$$.
    $$10\%$$ Pencil were broken, now Pencil left $$= 200 - 200 \times \dfrac{10}{100} = 180$$
    SP of pencils $$= 180 \times 0.36 = 64.8$$
    Profit $$=$$ SP $$-$$ CP
    Profit $$= 64.8 - 60 = 4.8$$
    Profit $$\%$$ $$ = \dfrac{4.8}{60} \times 100 = 8$$ $$\%$$

  • Question 5
    1 / -0
    A shopkeeper earns $$15$$% profit on a shirt even after allowing $$31$$% discount on the list price. If the list price is Rs. $$125$$, then what is the cost price of the shirt?
    Solution
    Discount on the shirt $$=31\%$$ of Rs. $$125$$
    $$=$$ Rs. $$\dfrac {31}{100}\times 125$$
    $$=$$ Rs. $$\dfrac {155}{4}$$
    Therefore, S.P. of the shirt $$=125-\dfrac {155}{4}$$
    $$=$$ Rs. $$\dfrac {345}{4}$$
    Therefore, C.P. of the shirt $$=\dfrac {345}{4}\times \dfrac {100}{115}$$
    $$=$$ Rs. $$75$$
    Thus, the cost price of the shirt is Rs. $$75$$.
  • Question 6
    1 / -0
    A shopkeeper sells two T.V. sets at the same price. There is a gain of $$20\%$$ on one TV. and loss of $$20\%$$ on the other. State which of the following statements is correct
    Solution

    Let the S.P. of both the T.V sets be Rs. $$x$$. 

    Then, C.P. of the T.V set at a gain of $$20\%$$ $$=$$ Rs. $$ \dfrac {100\times x}{120}=$$ Rs. $$ \dfrac {5x}{6}$$

    C.P. of the T.V set at a loss of $$20\%$$ $$=$$ Rs. $$ \dfrac {100\times x}{80}=$$ Rs. $$ \dfrac {5x}{4}$$

    Total C.P. $$=$$ Rs. $$ \left (\dfrac {5x}{6}+\dfrac {5x}{4}\right )=$$ Rs. $$ \dfrac {10x+15x}{12}=$$ Rs. $$ \dfrac {25x}{12}$$

    Total S.P. $$=$$ Rs. $$2x$$

    Loss $$=$$ Rs. $$ \left (\dfrac {25x}{12}-2x\right )=$$Rs. $$ \dfrac {x}{12}$$

    Loss $$\%$$ $$=\dfrac {\dfrac{x}{12}}{\dfrac{25x}{12}}\times 100=4$$ $$\%$$

  • Question 7
    1 / -0
    If selling price of an article is $$\dfrac {4}{3}$$ of its cost price, the profit in the transaction is
    Solution

    Let C.P. $$= x$$
    Then S.P. $$= \dfrac{4x}{3}$$
    Gain $$= \left (\dfrac{4x}{3} - x\right) = \dfrac{x}{3}$$
    $$\therefore$$ Gain $$\%$$ $$=\left  (\dfrac{x}{3} \times \dfrac{1}{x} \times 100\right) = 33\dfrac{1}{3}$$ $$\%$$

  • Question 8
    1 / -0
    If a shopkeeper sells $$\dfrac {1}{3}$$rd of his goods at a profit of $$14\%$$, $$\dfrac {3}{5}$$th of the goods at a profit of $$17.5\%$$ and remaining at a profit of $$20\%$$, then his profit on the whole is equal to
    Solution

    Let total cost of all goods be Rs. $$100$$.
    He sold $$\dfrac{1}{3}$$ of his goods that is Rs. $$33.3$$ at a profit of $$14\%$$
    Then profit $$ = 33.3 \times \dfrac{14}{100} =$$ Rs. $$4.662$$
    Simillarly $$\dfrac{3}{5} = 60$$, Profit $$17.5\%$$
    Then profit $$ = 60 \times \dfrac{17.5}{100} = 0.60 \times 17.5 = 10.5$$
    Now $$ 100 - (33.3+60) = 100 - 93.3 =$$ Rs. $$6.7$$
    Profit on Rs. $$6.7  = \dfrac{6.7 \times 20}{100} = 1.34$$
    Total profit $$ = 4.662+10.5+1.34=$$ Rs. $$ 16.502 = 16.5\%$$

  • Question 9
    1 / -0
    A shopkeeper allows a discount of $$10 \%$$ on a watch whose marked price is Rs. $$3400$$ and in the process makes a gain of Rs. $$220$$. What is the cost price of the watch?
    Solution
    S.P. of the watch $$=\dfrac {3400\times (100-10)}{100}=$$ Rs. $$3060$$.
    Gain $$=$$ Rs. $$220$$
    Therefore, C.P. of the watch $$=$$ Rs. $$(3060-220)=2840$$.
    Hence. option C is the correct answer.
  • Question 10
    1 / -0
    A refrigerator and a camera were sold for Rs. $$12,000$$ each. The refrigerator was sold at a loss of $$20\%$$ of the cost and the camera at a gain of $$20\%$$ of the cost. The entire transaction results in which one of the following?
    Solution

    C.P. of the camera $$= \dfrac { 100\times \text{S.P.} }{ 100+\text{profit} } $$

    C.P. $$= \dfrac { 100\times 12000 }{ 100+20 } $$

    CP $$= \dfrac { 100\times 12000 }{ 120 } = 10000$$

    CP of the camera $$=$$ Rs. $$10000$$

    CP of the refrigerator $$= \dfrac { 100\times \text{S.P.} }{ 100-\text{ loss} } $$

    CP $$= \dfrac { 100\times 12000 }{ 100-20 } $$ 

    CP $$= \dfrac { 100\times 12000 }{ 80 } = 15000$$

    CP of the refrigerator $$=$$ Rs. $$15000$$

    Total cost $$=$$ Rs. $$25000$$

    Total SP $$=$$ Rs. $$24000$$

    Hence, in the entire transaction, there has been a loss of Rs. $$1000.$$

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now