Self Studies

Comparing Quantities Test - 33

Result Self Studies

Comparing Quantities Test - 33
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    A dishonest dealer uses a scale of $$90$$ cm instead of a meter scale and claims to sell at cost price. His profit is
    Solution
    Let the cost price of the cloth be Rs. $$100$$ per metre i.e. Rs. $$1$$ per cm
    Since the shopkeeper uses $$90$$ cm scale for $$100$$ cm scale.
    His gain $$=$$ Cost of $$10$$ cm $$=$$ Rs. $$10$$
    Gain $$\% =$$ $$\displaystyle \frac{10}{90}\times 100$$
    $$=\dfrac{100}{9}\%$$
    $$=11\dfrac{1}{9}\%$$
  • Question 2
    1 / -0
    The shopkeeper gives a discount of $$12\%$$ on the pair of shoes marked for Rs. $$1425$$, then S.P is:
    Solution
    Given M.P. $$=$$ Rs. $$1425$$ 
    Discount $$=12\%$$ of Rs. $$1425 =$$ $$\displaystyle\frac{12}{100}\,\times\, 1425$$
    $$=$$ Rs. $$171$$ 
    Selling price of shoes $$=$$ Rs. $$(1425 - 171) = $$ Rs. $$1254$$.
  • Question 3
    1 / -0
    By selling $$100$$ pencils a shopkeeper gains the S.P. of $$20$$ pencils. His gain percent is 
    Solution
    S.P. of $$100$$ pencils $$-$$ C.P. of $$100$$ pencils $$=$$ S.P. of $$20$$ pencils
    $$\displaystyle \Rightarrow$$ S.P. of $$80$$ pencils $$=$$ C.P. of $$100$$ pencils 
    Let C.P. of $$1$$ pencil $$=$$ Rs. $$1$$
    Then S.P. of $$80$$ pencils $$=$$ Rs. $$100$$ 
    $$\Rightarrow $$ C.P. of $$80$$ pencils $$=$$ Rs. $$80$$
    $$\displaystyle \therefore$$ Profit $$\%$$ $$\displaystyle =\frac{100-80}{80}\times 100=\frac{20}{80}\times 100=25\%$$
  • Question 4
    1 / -0
    On what sum of money lent out at 9% per annum for 6 years does the simple interest amounts to Rs. 810?
    Solution
    Simple Interest $$=\text{Rs.}\ 810$$
    $$R= 9\%$$
    $$ T = 6\ \text{years}$$
    $$P=?$$

    According to the formula of Simple Interest:
    Simple Intrest $$I\, =\, \displaystyle \frac {P\times T\times R}{100}$$

    $$P\, =\, \displaystyle \frac {100 \times I}{T\times R}$$

          $$ =\, \displaystyle \frac {100 \times 810}{6 \times 9}$$
          $$ =\, \text{Rs.}\, 1500$$
  • Question 5
    1 / -0
    $$A$$ started  a business with $$Rs. 21, 000$$ and is joined afterwards by $$B$$ with $$Rs. 36, 000$$. After how many months did B join if the profit at the end of the year are divided equally ?
    Solution
    Suppose B joined after x months
    then,
    $$21000\times12=36000\times (12-x)$$
    $$=> 36x = 180$$
    $$=> x = 5$$
  • Question 6
    1 / -0
    A tradesman sold an article at a loss of $$20\%$$. Had he sold it for $$Rs. 100$$ more, he should have gained $$5\%$$. The cost price of the article was
    Solution
    Let the cost price $$=Rs. x$$
    Loss $$= 20 \%$$
    Loss $$=\cfrac{20}{100} \times x$$ = $$\dfrac{x}{5}$$
    Now, $$SP = CP - Loss = x - \cfrac{x}{5} = \cfrac{4x}{5}$$
    If SP was Rs 100 more,
    New $$SP = \cfrac{4x}{5} + 100$$
    Profit $$= 5\%$$ of CP $$=\cfrac{5}{100} \times x = New \, SP - CP$$
    Profit $$=\cfrac{x}{20} = \cfrac{4x}{5} + 100 - x$$
    $$\cfrac{20x - 16x + x}{20} = 100$$
    $$5x = 2000$$
    $$x = Rs. 400$$
  • Question 7
    1 / -0
    By selling a pen for $$\text{Rs. } 15$$, a man loses one-sixteenth of what it costs him. Find the cost price of one pen.
    Solution
    Let's assume  the cost price of the pen is $$x$$
    According to the question, Loss $$=\cfrac { x }{ 16 } $$
    Cost Price$$ = $$ Selling Price $$ + $$ Loss
    Hence, 
    $$15+\dfrac { x }{ 16 } =x$$
    $$15=x-\dfrac { x }{ 16 } $$
    $$15=\dfrac { 15x }{ 16 } $$
    $$x=16$$
    Hence, the cost of $$1$$ pen is $$\text{Rs. } 16$$
  • Question 8
    1 / -0
    A shopkeeper sold sarees at $$\text{Rs. }266$$ each after giving a $$5 \%$$ discount on labeled price. Had he not given the discount, he would have earned a profit of $$12 \%$$ on the cost price. what was the cost price of each saree?
    Solution
    Let us assume that the labeled price is equal to $$x$$.

    $$\dfrac{95}{100}\times x=266$$
    $$\Rightarrow x = \text{Rs. } 280$$

    Now consider that the cost price of the saree is equal to $$y$$. Then,
    $$\text{Profit}\% =  12=\dfrac{ (280-y)\times 100 }{ y } $$
    $$\begin{array}{l}\Rightarrow12y = 28000 - 100y\\\Rightarrow112y = 28000\\\Rightarrow y =\text{Rs. } 250\end{array}$$

    Hence, option $$D$$ is the correct answer.
  • Question 9
    1 / -0
    Madhav lent out Rs. 7953 for 2 years and Rs. 1800 for 3 years at the same rate of simple interest. If he got Rs. 2343. 66 as total, then find the percent rate of interest.
    Solution
    We know that Simple Interest $$ = \cfrac {PNR}{100} $$
    Given,  $$ \cfrac {7953 \times 2 \times R}{100}  + \cfrac {1800  \times 3 \times R}{100}  = Rs 2343.66 $$
    $$=> 159.06R + 54R = Rs 2343.66 $$
    $$ => 213.06R = 2343.66 $$
    $$ => R = 11 \%$$ 
  • Question 10
    1 / -0
    $$A$$ began a business with Rs. $$85{,}000$$. He was joined afterwards by $$B$$ with Rs. $$42{,}500$$. For how much period does $$B$$ join, if the profits at the end of the year are divided in the ratio of $$3 : 1$$?
    Solution

    Suppose B joined for x months . Then, $$\dfrac{ ( 85000 \times 12 )}{(42500 \times  x)} = 3$$

    $$=> x = \dfrac{(85000 \times 12)}{  (42500 \times 3) }$$

    $$=>x= 8$$

    So, B joined for 8 months.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now