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Comparing Quantities Test - 46

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Comparing Quantities Test - 46
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Ram buys a wrist watch for Rs. 250 and spend Rs. 50 on its repairs. If he sells same for Rs. 450, find his profit percent.
    Solution
    Purchase price of wrist watch = Rs. 250
    Amount spent on repairs = Rs. 50
    Cost price of the watch = Purchase price + repair expenses= 250 + 50 = 300
    Selling price = Rs. 450
    Since SP > CP so profit = 450 - 300 = 150
    Profit% = $$\dfrac{Total \space\ profit}{CP}\times 100=\dfrac{150}{300}\times 100=50$$%
  • Question 2
    1 / -0
    Oscar earned Rs. $$2400$$ as simple interest on Rs. `$$4500$$ for $$3$$ months. What is the annual rate of interest?
    Solution
    Given, principal $$=4500$$, Interest $$=$$ Rs. $$2400$$, period $$=3$$ months
    We know the formula,
    Rate of interest, $$R =$$ $$\dfrac{I\times 100}{PT}$$
    $$\Rightarrow R =$$ $$\dfrac{2400\times 100}{4500\times 3}$$
    $$\Rightarrow R = 17.77\%$$
    Therefore, the annual rate of interest is $$17.77\%$$.
  • Question 3
    1 / -0
    To start a grocery shop, a woman borrowed Rs. $$1,500$$. If the loan was for four years and the amount of interest was Rs. $$150$$, what simple interest rate was she charged?
    Solution
    Given, principal $$=$$ Rs. $$1500$$, Interest $$=$$ Rs. $$150$$, period $$=4$$ years
    We know the formula,
    Rate of interest, $$R =$$ $$\dfrac{I\times 100}{PT}$$
    $$\Rightarrow R =$$ $$\dfrac{150\times 100}{1500\times 4}$$
    $$\Rightarrow R = 2.5\%$$
    Therefore, the simple interest is $$2.5\%$$.
  • Question 4
    1 / -0
    You borrow Rs. $$4,000$$ from a loan shark. If you owe Rs. $$7,200$$ in $$4$$ years, what would be the simple interest rate?
    Solution
    Given:
    Principal $$=$$ Rs. $$ 4,000$$
    Interest $$= 7200 - 4000 = 3200$$
    We know the formula,
    Rate of interest, $$R =$$ $$\dfrac{I\times 100}{PT}$$
    $$\Rightarrow R =$$ $$\dfrac{3200\times 100}{4000\times 4}$$
    $$\Rightarrow R = 20\%$$
    Thus, the simple interest rate is $$20\%$$.
  • Question 5
    1 / -0
    Sharmila got a Rs. $$1300$$ loan for $$5$$ years. She paid Rs. $$100$$ in interest. What was the interest rate?
    Solution
    Given, principal $$=$$ Rs. $$1300$$, Interest $$=$$ Rs. $$100$$, period $$=5$$ years
    We know the formula,
    Rate of interest, $$R =$$ $$\dfrac{I\times 100}{PT}$$
    $$\Rightarrow R =$$ $$\dfrac{100\times 100}{1300\times 5}$$
    $$\Rightarrow R = 1.5\%$$
    Therefore, the interest rate is $$1.5\%$$.
  • Question 6
    1 / -0
    You invested Rs. $$1500$$ and received Rs. $$5000$$ after three years. What had been the interest rate?
    Solution
    Amount invested $$= 1500$$
    Amount received after three years $$= 5000$$

    $$\Rightarrow$$ Interest earned $$= 5000-1500 = 3500$$
    Let interest rate$$\%$$ be $$r$$
    $$\Rightarrow$$ $$3500 = \dfrac{1500 \times 3 \times r}{100}$$
    $$\Rightarrow$$ $$r = 77.77\%$$
  • Question 7
    1 / -0
    Anu bought a second-hand car for $$Rs.\ 15,000$$ and spent $$Rs.\ 5000$$ on its repair. She then sold it to Deepika at a loss of $$10\%$$. What is Anu's loss?
    Solution
    $$CP = 15,000 + 5,000$$
            $$ = Rs.\  20,000$$

    Now,
    $$\text{loss }\%=\dfrac{CP-SP}{CP}\times 100$$
    $$\Rightarrow 10=\dfrac{\text{loss}}{20000}\times 100$$
    $$\Rightarrow 10=\dfrac{\text{loss}}{200}$$
    $$\Rightarrow {\text{loss}}=Rs.\ 2000$$

    Hence, option $$B$$ is correct.
  • Question 8
    1 / -0
    Jenn borrowed Rs. $$5,000$$ for $$5$$ years and had to pay Rs. $$1,500$$ simple interest at the end of that time. What rate of interest did she pay?
    Solution
    Given, $$I=1500,P=5000, T=5$$ years
    We need to find rate of interest $$R$$.
    We know the formula,
    Rate of interest, $$R =$$ $$\dfrac{I\times 100}{PT}$$
    $$\Rightarrow R =$$ $$\dfrac{1500\times 100}{5000\times 5}$$
    $$\Rightarrow R = 6\%$$
  • Question 9
    1 / -0
    If paintbrushes cost $$1.50$$ each and canvases cost 6 times that much, which of the following represents the cost, in dollars, of $$p$$ paintbrushes and $$c$$ canvases?
    Solution
    Cost of $$1$$ paintbrush $$=1.50$$

    Hence cost of $$p$$ paintbrushes$$=(p\times 1.5)$$

    Also,

    Cost of $$1$$ canvas $$=1.50\times 6=9$$

    Hence cost of $$c$$ canvases$$=(c\times 9)$$.

    So,

    Cost of $$p$$ paintbrushes and $$c$$ canvases$$=1.5p+9c$$
  • Question 10
    1 / -0
    FURNITURE SET
    Set$$A$$$$B$$$$C$$
    Tables$$1$$$$2$$$$3$$
    Chairs$$7$$$$5$$$$2$$

    PRICES
    Year$$2002$$$$2007$$$$2012$$
    Table$$ $60$$$$ $80$$$$ $100$$
    Chair$$ $30$$$$ $35$$$$ $40$$

    A furniture company sells three sets of furniture: set $$A$$, set $$B$$, and set $$C$$. Each set consists of a different number of tables and chairs as shown in the first table above. The second table shows the sale prices in dollars of each table and chair in three different years. Based on the prices shown, calculate the greatest possible sale price in dollars of a furniture set bought in $$2007$$.
    Solution
    Consider furniture set $$A$$: it consists $$1$$ table and $$7$$ chairs.
    The price of set $$A$$ in $$2007$$: $$1\times$80+7\times$35=$325$$
    Consider furniture set $$B$$: it consists $$2$$ tables and $$5$$ chairs.
    The price of set $$B$$ in $$2007$$: $$2\times$80+5\times$35=$335$$
    Consider furniture set $$C$$: it consists $$3$$ tables and $$2$$ chairs.
    The price of set $$B$$ in $$2007$$: $$3\times$80+2\times$35=$310$$
    The greatest of these three is $$\$335$$.
    Hence,option $$B$$ is correct.
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