Comparing Quantities Test

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Comparing Quantities Test - 48

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Weekly Quiz Competition

Question 1
1 / -0

A men's clothing retailer order $ $$25,400$$ worth of outer garments and receives a discount of $$15$$% followed by an additional discount of $$10$$%. What is the cost of the clothing after these two discounts?

A
9431

B
19431

C
1943

D
19234

Solution

First he got $$15$$ $$\%$$ discount, therefore after discount the cost of clothing is $$\left (1-\dfrac{15}{100}\right) \times 25400 = 21590$$
Now he got additional $$10$$ $$\%$$ discount
Now the cost of clothing is $$\left (1-\dfrac{10}{100}\right) \times 21590 = 19431$$
Question 2
1 / -0

If an item is purchased at $ $$150$$ and sold at $ $$165$$, what percent of the original cost is the profit?

A
$$110$$ percent

B
$$89$$ percent

C
$$100$$ percent

D
$$9$$ percent

E
$$10$$ percent

Solution

Given:
cost price$$=150$$ dollar
Selling price$$=165$$ dollar
Profit$$=$$selling price$$-$$cost price
$$=165-150=15$$ dollar
Percent of the original cost$$=\dfrac{15}{150}\times 100$$
$$=10\%$$
Option 'E'.
Question 3
1 / -0

Rajesh bought an arm-chair for Rs. $$2200$$ and sold it for Rs. $$2420$$. Find his profit percent.

A
$$5\%$$

B
$$10\%$$

C
$$12\%$$

D
$$15\%$$

Solution

Here, $$CP = 2200\ Rs, SP = 2420\ Rs$$

$$Profit = SP - CP = 2420 - 2200 = 220\ Rs$$

$$Profit Percentage = \dfrac{Profit\times100}{CP}=\dfrac{220\times100}{2200}=10\%$$
Question 4
1 / -0

Mr. Ambani purchased a car of $$3,00,000$$ and a bike for his son for $$1,00,000$$. He sold the car at a profit of $$10$$% and bike at a loss of $$20$$%. What is the net gain or loss?

A
$$2$$% gain

B
$$1.5$$% gain

C
$$2.5$$% loss

D
$$2.5$$% gain

Solution

CP of a car = 3,00,000 Rs

Profit on car = 10%

$$\therefore SP\ of\ car=CP+CP\times\dfrac{Profit\ Percentage}{100}=300000+300000\times\dfrac{10}{100}=3,30,000\ Rs$$

CP of a bike = 1,00,000 Rs.

Loss on bike = 20%

$$\therefore SP\ of\ bike=CP-CP\times\dfrac{Loss\ Percentage}{100}=100000-100000\times\dfrac{20}{100}=80,000\ Rs$$

So, $$Total\ CP = 3,00,000 + 1,00,000 = 4,00,000$$ Rs

And $$Total\ SP = 3,30,000+80,000=4,10,000$$ Rs

Here SP > CP.

$$\therefore Gain = SP - CP = 4,10,000-4,00,000=10,000\ Rs$$

$$\Rightarrow Gain\ percentage = \dfrac{gain\times100}{CP}=\dfrac{10,000\times100}{4,00,000}=2.5\%$$
Question 5
1 / -0

A barrel of crude oil is extracted from shale at a cost of $$\$51$$, and then transported to and from the refinery at a cost of $$\$6$$ each direction. Oil is processed three times at the refinery plant, at a cost of $$\$9$$ each time. What is the profit, in dollars per barrel, if one barrel is sold for $$\$93$$? (Profit is equal to revenue minus expenses.)

A
$$1$$

B
$$2$$

C
$$3$$

D
$$4$$

Solution

Costing in the process of making and transporting oil are:
Cost of extraction$$=\$51$$
Cosr of transportation to and from refinery= $$\$(6+6)=$12$$
Cost of processing $$3$$ times at $$\$9$$ each time $$=\$(3\times 9)=\$27$$
Total Cost$$= \$(51+12+27)=$$ $$ $90$$
Selling Price=$$ $93$$
Profit$$=\$(93-90)=$3$$
Question 6
1 / -0

Sunita is making a profit of $$25$$% on her selling price. What is her actual profit percentage?

A
$$\dfrac { 100 }{ 3 } $$%

B
$$20$$%

C
$$25$$%

D
$$30$$%

Solution

Let assume selling price 100 Rs

Profit = 25% of selling price = $$100\times\dfrac{25}{100}=25\ Rs$$

$$\therefore Cost\ Price=Selling\ Price-Profit=100-25=75$$

Hence, actual profit percentage = $$\dfrac{profit\times100}{Cost\ Price}=\dfrac{25\times100}{75}=\dfrac{100}{3}\%$$
Question 7
1 / -0

If an article is sold at $$8\%$$ profit instead of $$8\%$$ loss, it would have brought Rs. $$12$$ more, what is the cost price of the article?

A
Rs. $$60$$

B
Rs. $$70$$

C
Rs. $$72$$

D
Rs. $$75$$

Solution

Let the Cost Price (C.P) be Rs $$x$$ and then at $$ 8\% $$ of profit
Selling Price(S.P) would be :
Gain $$\%$$ = $$ \dfrac{(S.P - C.P)}{C.P} \times 100 $$
$$\Rightarrow 8 \% =\dfrac{S.P- x}{x}\times100$$
$$\Rightarrow \dfrac{8x}{100} = S.P - x $$

$$\Rightarrow S.P = \dfrac{8x}{100} + x$$

$$\Rightarrow S.P = \dfrac{108x}{100}$$ .....(1)
Now, If the loss is $$ 8 \% $$
$$\Rightarrow \dfrac{8x}{100}= x - S.P$$

$$\Rightarrow S.P = \dfrac{92x}{100}$$...(2)

Now we have the condition from 1 and 2 we get :

$$S.P (profit) = S.P(loss) + 12$$

$$\Rightarrow \dfrac{108x}{100} = \dfrac{92x}{100} +12 $$

$$\Rightarrow \dfrac{(108 - 92 )}{100} x = 12 $$

$$\Rightarrow \dfrac{16}{100}x = 12 $$

$$ \Rightarrow 16x = 12 \times 100 $$

$$ \Rightarrow x = \dfrac{12\times 100 }{16}$$

$$\Rightarrow x = 75 $$

$$ \Rightarrow C.P = $$Rs $$75 $$

The Cost Price of the article is $$Rs 75$$ .
Question 8
1 / -0

Round to the nearest whole number: What is 17/68, as a percent?

A
17%

B
25%

C
40%

D
68%

Solution
Question 9
1 / -0

What principal will amount to Rs. $$9,744$$ in two years, if the rates of interest for successive years are $$16$$% and $$20$$% respectively?

A
$$7000$$

B
$$8000$$

C
$$5000$$

D
$$9000$$

Solution

$$\Rightarrow$$ Let the principal (P) be $$Rs.x$$.
$$\Rightarrow$$ Rate of interests for two successive years are $$(R_1)\,\,16\%$$ and $$(R_2)\,\,20\%$$.
$$\Rightarrow$$ $$A=P(1+\dfrac{R_1}{100})(1+\dfrac{R_2}{100})$$

$$\Rightarrow$$ $$9744=x(1+\dfrac{16}{100})(1+\dfrac{20}{100})$$

$$\Rightarrow$$ $$9744=x\times \dfrac{29}{25}\times {6}{5}$$

$$\Rightarrow$$ $$9744=\dfrac{174}{125}x$$

$$\therefore$$ $$x=\dfrac{9744\times 125}{174}$$

$$=56\times 125=Rs.7000$$
$$\therefore$$ Hence, principal = $$Rs.7000$$.
Question 10
1 / -0

In a certain store, the profit is $$320$$% of the cost. If the cost increases by $$25$$% but the selling price remains constant, approximately what percentage of the selling price is the profit?

A
$$30$$%

B
$$70$$%

C
$$100$$%

D
$$250$$%

Solution

Let $$C.P.= Rs. 100$$. Then, $$Profit = Rs. 320, S.P. = Rs. 420$$.
New $$C.P. = 125$$% of $$Rs. 100 = Rs. 125$$
New $$S.P. = Rs. 420$$.
$$Profit = Rs. (420 - 125) = Rs. 295$$.
$$\therefore$$ Required percentage $$=\left (\dfrac {295}{420}\times 100\right )$$% $$= \dfrac {1475}{21}$$% $$= 70$$% (approximately).

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 48

Result

Comparing Quantities Test - 48

Score

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Rank

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SHARING IS CARING

Question 1

9431

19431

1943

19234

Solution

Question 2

$$110$$ percent

$$89$$ percent

$$100$$ percent

$$9$$ percent

$$10$$ percent

Solution

Question 3

$$5\%$$

$$10\%$$

$$12\%$$

$$15\%$$

Solution

Question 4

$$2$$% gain

$$1.5$$% gain

$$2.5$$% loss

$$2.5$$% gain

Solution

Question 5

$$1$$

$$2$$

$$3$$

$$4$$

Solution

Question 6

$$\dfrac { 100 }{ 3 } $$%

$$20$$%

$$25$$%

$$30$$%

Solution

Question 7

Rs. $$60$$

Rs. $$70$$

Rs. $$72$$

Rs. $$75$$

Solution

Question 8

17%

25%

40%

68%

Solution

Question 9

$$7000$$

$$8000$$

$$5000$$

$$9000$$

Solution

Question 10

$$30$$%

$$70$$%

$$100$$%

$$250$$%

Solution

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