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Comparing Quantities Test - 49

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Comparing Quantities Test - 49
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  • Question 1
    1 / -0
    The question given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

    By selling an article what is the profit percent gained?
    I. 5%5\% discount is given on list price.
    II. If the discount is not given, 20%20\% profit is gained.
    III. The cost price of the articles is Rs. 5000\text{Rs. } 5000.
    Solution
    I. Let the list price be Rs. x\text{Rs. } x
    Then, S.P.=95%\text{S.P.} = 95\% of Rs. x=Rs. (x×95100)=Rs. 19x20\text{Rs. } x = \text{Rs. } \left (x\times \dfrac {95}{100}\right ) = \text{Rs. } \dfrac {19x}{20}
    II. When S.P.=Rs. x\text{S.P.} = \text{Rs. } x and gain =20%= 20\%
    Then, C.P.=Rs. (100120×x)=Rs. 5x6\text{C.P.} =\text{Rs. } \left (\dfrac {100}{120}\times x\right ) =\text{Rs. } \dfrac {5x}{6}
    Gain=(19x205x6)=(57x50x60)=7x60\therefore \text{Gain} = \left (\dfrac {19x}{20} - \dfrac {5x}{6}\right ) = \left (\dfrac {57x - 50x}{60}\right ) = \dfrac {7x}{60}
    Gain%\therefore \text{Gain}\% =(7x60×65x×100)%=\left (\dfrac {7x}{60}\times \dfrac {6}{5x} \times 100\right )\% =14%= 14\%.
    Thus, I and II only give the answer.
    \therefore Correct answer is (A).
  • Question 2
    1 / -0
    A trader marks 10%10\% higher than the cost price. He gives a discount of 10%10\% on the marked price. In this kind of sales how much percent does the trader gain or lose?
    Solution
    Let the cost price be Rs 100\text{Rs }100
    Then the mark-up price is 10%10\% above the cost price.
    Mark price =(100+10% of 100)==(100+10\% \ \text{of}\ 100)= Rs.\text{Rs.} 110110
    Trader gives 10%10\% discount on the marked price, then  the 
    Selling price =(11010% of 110)==(110-10\% \ \text{of}\ 110)= Rs.\text{Rs.} 9999
    Therefore, Loss == cost price - selling price
     Loss =10099=Rs 1=100-99= \text{Rs }1 on cost price of Rs 100\text{Rs }100
    Thus loss percent is 1%1\%.
  • Question 3
    1 / -0
    Two bicycles were sold for Rs. 39903990 each, gaining 5%5 \% on one and losing 5%5 \% on the other. The gain or loss %\% on the whole transaction is.
    Solution
    Selling price of two bicycles =3990 = 3990 Rs. each

    Let the cost price of a bicycle on which gain is 5%5\% =x=x
    and another bicycle on which loss is 20%20\% =y=y

    Solving for bicycle on which he gain
    We know that, Selling price=Cost price+ profitSelling\ price = Cost\ price +  profit

    3990=x+5% of x\Rightarrow 3990 = x + 5\%\ of\ x

    3990=x+0.05x\Rightarrow 3990 = x+0.05x

    3990=1.05x\Rightarrow 3990 = 1.05x

    x=39901.05\Rightarrow x = \dfrac{3990}{1.05}

    x=3800 Rs\therefore x = 3800\ Rs

    Now, Solving for bicycle on which he loss
    We know that, Selling price=Cost pricelossSelling\ price=Cost\ price-loss

    3990=y5% of y\Rightarrow 3990 = y - 5\%\ of\ y

    3990=y0.05y\Rightarrow 3990 = y - 0.05y

    3990=0.95y\Rightarrow 3990 = 0.95y

    y=39900.95\Rightarrow y = \dfrac{3990}{0.95}

    y=4200 Rs\therefore y = 4200\ Rs

    Now, Total Cost price=x+y=3800+4200=8000Total\ Cost\ price = x + y = 3800+4200 = 8000

    and Total Selling price=2×3990=7980Total\ Selling\ price = 2\times3990 = 7980

    Since Selling price<CostPriceSelling\ price < Cost Price

    So, In whole transaction, there is a loss and loss =80007980=20= 8000-7980=20

    Loss Percentage=Loss×100Cost Price=20×1008000=0.25% loss\therefore Loss\ Percentage=\dfrac{Loss\times100}{Cost\ Price}=\dfrac{20\times100}{8000}=0.25\%\ loss

  • Question 4
    1 / -0
    Two blends of tea costing Rs 3535 per kg and Rs 4040 per kg respectively are mixed in the ratio 2:32 : 3 by weight. If one-fifth of the mixture is sold at Rs 4646 per kg and the remaining at the rate of Rs 5555 per kg, find the profit percent.
    Solution
    Let's assume the proportional value is xx

    So, First kind of tea =2x= 2x kg and Second kind of tea =3x= 3x kg

    Now, CP=(Amount×Cost price rate)CP=\sum(Amount\times Cost\ price\ rate)

     CP=2x×35+3x×40=190x Rs\therefore\ CP=2x\times 35+3x\times 40=190x\ Rs

    Amount of mixture =2x+3x=5x kg=2x+3x=5x\ kg

    Given that, 15th of mixture=x kg\dfrac{1}{5}th\ of\ mixture=x\ kg sold at 46 Rs46\ Rs per kg and remaining (5xx=4x kg)(5x-x=4x\ kg) sold at 55 Rs55\ Rs per kg

    So, SP=(Amount×Selling price rate)SP=\sum(Amount\times Selling\ price\ rate)

     SP=x×46+4x×55=266x Rs\therefore\ SP=x\times 46+4x\times 55=266x\ Rs

    Now, Profit=SPCP=266x190x=76x RsProfit=SP-CP=266x-190x=76x\ Rs

    Profit percentage=Profit×100CP=76x×100190x=40%\therefore Profit\ percentage=\dfrac{Profit\times 100}{CP}=\dfrac{76x\times 100}{190x}=40\%
  • Question 5
    1 / -0
    A vendor bought toffees at 66 for a rupee. How many for a rupee must he sell to gain 2020%?
    Solution

  • Question 6
    1 / -0
    A trader purchased an old bicycle for Rs. 480 Rs.\ 480. He spent 20%20 \% of the cost on its repair. If he wants to earn Rs 144 Rs\ 144 as net profit on it, find profit %\%.
    Solution
    CPCP of an old bicycle =480=480

    Cost on repairs =480×20100=96=480\times {\dfrac{20}{100}}=96

    Total CP =480+96=576=480+96=576

    Profit =144=144

    Profit  %=144576×100=25\%=\dfrac{144}{576}\times 100=25
  • Question 7
    1 / -0
    A man bought two goats for Rs. 10081008. He sold one at a loss of 2020% and the other a profit of 4444%. If each goat was sold for the same price, the cost price of the goat which was sold at a loss was
    Solution
    \Rightarrow  Cost price of two goats is Rs.1008Rs.1008.
    \Rightarrow 80%80\% of cost price of first goat = 144%144\% of cost price of second goat.
    \Rightarrow   cost price of first goat : cost price of second goat = 144:80=9:5144:80=9:5
    \Rightarrow   Cost price of first goat= 99+5×1008=\dfrac{9}{9+5}\times 1008=Rs. 648648
  • Question 8
    1 / -0
    Raghav purchased a scooter at 1315 \dfrac {13}{15} of its selling price and sold it at 12%12 \% more than its selling price. What is his gain per cent ?
    Solution
    Let selling price of scooter be X Rs.

    Cost price for Raghav (CP) =1315 of X=13X15=\dfrac{13}{15}\ of\ X=\dfrac{13X}{15}

    Selling price for Raghav is 12% more than Selling price.

    SP=X+12% of X=X+0.12X=28X25 Rs\Rightarrow SP=X+12\%\ of\ X=X+0.12X=\dfrac{28X}{25}\ Rs

    Gain=SPCP=28X2513X15=168X130X150=38X150\therefore Gain=SP-CP=\dfrac{28X}{25}-\dfrac{13X}{15}=\dfrac{168X-130X}{150}=\dfrac{38X}{150}

    Gain Percentage=Gain×100CP=38X150×10013X15=38013=29313%\therefore Gain\ Percentage=\dfrac{Gain\times100}{CP}=\dfrac{\dfrac{38X}{150}\times100}{\dfrac{13X}{15}}=\dfrac{380}{13}=29\dfrac{3}{13}\%
  • Question 9
    1 / -0
    A tradesman fixed the selling prices of goods at 3030% above the cost price. He sells half of the stock at this price, one-quarter of his stock at a discount of 1515% on the original selling price, and the rest at a discount of 3030% on the original selling price. Find the gain percent altogether.
    Solution
    Let cost price of goods be x Rsx\ Rs per unit and total unit be yy units.

    Then total cost price (CP) =xy Rs=xy\ Rs

    Selling price of goods is 30% higher than cost price.

    So, Selling price of goods =x+30% of x=13x10=x+30\%\ of\ x=\dfrac{13x}{10} per units.

    According to question, y2\dfrac{y}{2} units of goods sold at selling price, y4\dfrac{y}{4} units of goods sold at 15% discount and remaining y4\dfrac{y}{4} units of goods sold at 30% discount.

    So, Total Selling Price (SP) =(Amounts×Selling price rate)=\sum(Amounts\times Selling\ price\ rate)

    SP=(y2×13x10)+(y4×(13x1015% of 13x10))+(y4×(13x1030% of 13x10))\Rightarrow SP=(\dfrac{y}{2}\times \dfrac{13x}{10})+(\dfrac{y}{4}\times (\dfrac{13x}{10}-15\%\ of\ \dfrac{13x}{10}))+(\dfrac{y}{4}\times (\dfrac{13x}{10}-30\%\ of\ \dfrac{13x}{10}))

    SP=13xy20+(y4×221x200)+(y4×91x100)\Rightarrow SP=\dfrac{13xy}{20}+(\dfrac{y}{4}\times \dfrac{221x}{200})+(\dfrac{y}{4}\times \dfrac{91x}{100})

    SP=520xy800+221xy800+182xy800\Rightarrow SP=\dfrac{520xy}{800}+\dfrac{221xy}{800}+\dfrac{182xy}{800}

    SP=923xy800\therefore SP=\dfrac{923xy}{800}

    Hence, Gain=SPCP=923xy800xy=123xy800Gain=SP-CP=\dfrac{923xy}{800}-xy=\dfrac{123xy}{800}

    So, Gain percentage=Gain×100CP=123xy800×100xy=1238=1538%Gain\ percentage = \dfrac{Gain\times 100}{CP}=\dfrac{\dfrac{123xy}{800}\times 100}{xy}=\dfrac{123}{8}=15\dfrac{3}{8}\%
  • Question 10
    1 / -0
    The shopkeeper gives a discount of 1212% on the pair of shoes marked for Rs. 14251425, then S.P is:
    Solution
    Discount =12=12 %
    MP =1425=1425
    SP =MP -Discount
    =142512100×1425=1425-\dfrac{12}{100} \times 1425
    =1254=1254
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