Comparing Quantities Test

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Comparing Quantities Test - 51

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Weekly Quiz Competition

Question 1
1 / -0

If the cost price of $$14$$ articles is equal to the selling price of $$10$$ articles. What is profit per cent?

A
$$18\%$$

B
$$20\%$$

C
$$40\%$$

D
$$80\%$$

Solution

Let cost price of an article $$= X\ Rs$$

Cost price for 10 articles $$= 10X\ Rs$$

Selling price for 10 articles $$=$$ Cost Price of 14 articles $$= 14X\ Rs$$ ( Given)

So, Profit $$=$$ Selling price-Cost price $$=14X-10X=4X\ Rs$$

$$\therefore Profit\ percentage=\dfrac{profit\times100}{Cost\ price}=\dfrac{4x\times100}{10x}=40\%$$
Question 2
1 / -0

An article cost Rs $$80$$ to the vendor. If he marks the article for $$50$$% more than the cost price and sells it $$25$$% less than the marked price. What is his gain percentage ?

A
$$\dfrac{25}{2}$$ %

B
$$\dfrac{84}{4}$$ %

C
$$25$$%

D
$$\dfrac{31}{2}$$ %

Solution

Cost price $$= 80$$ Rs

Since marked price is $$50\%$$ more than the cost price.

$$\therefore MP=CP+50\%\ of\ CP=80+\dfrac{50\times 80}{100}=120\ Rs$$

Discount $$=25\%$$

$$\therefore SP=MP-Discount$$

$$\Rightarrow SP=120-25\%\ of\ 120$$

$$\Rightarrow SP=120-30=90\ Rs$$

$$\therefore Gain=SP-CP=90-80=10\ Rs$$

$$\Rightarrow Gain\ percentage=\dfrac{Gain\times 100}{CP}=\dfrac{10\times 100}{80}=\dfrac{25}{2}\%$$
Question 3
1 / -0

In terms of percentage profit, which among the following is the best transaction ?

A
C.P $$=36$$, Profit $$=17$$

B
C.P $$=46$$, Profit $$=27$$

C
C.P $$=39$$, Profit $$=19$$

D
C.P $$=36$$, Profit $$=20$$
Question 4
1 / -0

Joshita borrowed Rs. $$3,000$$ for $$3$$ years and had to pay Rs.$$ 1,000$$ simple interest at the end of that time. What rate of interest did she pay?

A
$$11.11$$

B
$$22.22$$

C
$$33.33$$

D
$$44.44$$

Solution

$$\Rightarrow$$ $$P=Rs.3000,\,T=3\,years$$ and $$S.I.=Rs.1000$$.
$$\Rightarrow$$ $$S.I.=\dfrac{P\times R\times T}{100}$$

$$\Rightarrow$$ $$1000=\dfrac{3000\times R\times 3}{100}$$

$$\Rightarrow$$ $$R=\dfrac{1000}{90}$$

$$\therefore$$ $$R=11.11\%$$
Question 5
1 / -0

Principal $$= 2500$$, rate $$= 6$$%, time$$= 4$$ years. Calculate the interest.

A
Rs.$$500$$

B
Rs.$$600$$

C
Rs.$$300$$

D
Rs.$$400$$

Solution

Simple interest $$=\dfrac{P \times R \times T}{100}$$
$$=\dfrac{2500 \times 6 \times 4}{100} =600$$
Therefor the interest is $$Rs \ 600$$
Question 6
1 / -0

By selling on article for $$ Rs \ 950$$, a man loses $$ 5 \%$$. If he had sold it for $$Rs. 1,220$$, the gain would be

A
$$20 \%$$

B
$$22 \%$$

C
$$24 \%$$

D
$$26 \%$$

Solution

Selling price of article $$= 950$$ Rs, Loss $$= 5\%$$

We know that $$SP=CP-Loss$$

$$\Rightarrow 950=CP-5\%\ of\ CP$$

$$\Rightarrow 950=CP-0.05\times CP$$

$$\Rightarrow 950=0.95\times CP$$

$$\therefore CP=\dfrac{950}{0.95}=1000\ Rs$$

Now, Selling Price $$(SP)= 1220$$ Rs

Here $$SP > CP$$, there will be a profit.

$$\therefore$$ Profit $$=SP-CP=1220-1000=220\ Rs$$

$$\Rightarrow Profit\ percentage =\dfrac{Profit\times 100}{CP}=\dfrac{220\times 100}{1000}=22\%$$
Question 7
1 / -0

A sum of money at simple interest amounts to Rs. $$600$$ in $$2$$ years and to Rs. $$800$$ in $$4$$ years. The sum is:

A
$$100$$

B
$$200$$

C
$$300$$

D
$$400$$
Question 8
1 / -0

Principal + Amount - $$2 \times $$ principle =

A
Principle

B
Interest

C
Amount

D
Rate

Solution

Principal + Amount - $$2 \times $$ principle
$$= \,P+A-2P$$
$$=P+(P+I)-2P$$
$$=P+P+I-2P$$
$$=I$$
Question 9
1 / -0

Find the profit per cent or loss per cent made when the S.P. of 15 identical articles is equal to the C.P. of 25 articles.

A
Profit = $$\displaystyle 66\frac{2}{3}$$%

B
Profit = $$\displaystyle 33\frac{1}{3}$$%

C
Profit = $$50$$%

D
Loss = $$\displaystyle 33\frac{1}{3}$$%

Solution

Let the cost price of an article $$= Rs.\ X$$

Cost price for 15 articles $$= Rs.\ 15X$$

Given: Selling price for 15 articles = Cost Price of 25 articles $$= Rs.\ 25X$$

So, Profit $$=$$ Selling price $$-$$ Cost price

$$=25X-15X$$

$$=Rs.\ 10X$$

$$\therefore $$ Profit percent $$=\dfrac{\mathrm{profit}\times100}{\mathrm{Cost\ price}}$$

$$=\dfrac{10X\times100}{15X}$$

$$=\dfrac{200}{3}$$

$$=66\dfrac{2}{3}\%$$
Question 10
1 / -0

Convert $$\dfrac{16}{50}$$ into percentage.

A
$$32\%$$

B
$$34\%$$

C
$$36\%$$

D
$$38\%$$

Solution

$$\Rightarrow$$ We have to convert $$\dfrac{16}{50}$$ into percentage.
$$\Rightarrow$$ $$\%=(\dfrac{16}{50}\times 100)\%$$

$$\Rightarrow$$ $$\%=(16\times 2)\%$$

$$\therefore$$ $$\%=32\%$$

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 51

Result

Comparing Quantities Test - 51

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SHARING IS CARING

Question 1

$$18\%$$

$$20\%$$

$$40\%$$

$$80\%$$

Solution

Question 2

$$\dfrac{25}{2}$$ %

$$\dfrac{84}{4}$$ %

$$25$$%

$$\dfrac{31}{2}$$ %

Solution

Question 3

C.P $$=36$$, Profit $$=17$$

C.P $$=46$$, Profit $$=27$$

C.P $$=39$$, Profit $$=19$$

C.P $$=36$$, Profit $$=20$$

Question 4

$$11.11$$

$$22.22$$

$$33.33$$

$$44.44$$

Solution

Question 5

Rs.$$500$$

Rs.$$600$$

Rs.$$300$$

Rs.$$400$$

Solution

Question 6

$$20 \%$$

$$22 \%$$

$$24 \%$$

$$26 \%$$

Solution

Question 7

$$100$$

$$200$$

$$300$$

$$400$$

Question 8

Principle

Interest

Amount

Rate

Solution

Question 9

Profit = $$\displaystyle 66\frac{2}{3}$$%

Profit = $$\displaystyle 33\frac{1}{3}$$%

Profit = $$50$$%

Loss = $$\displaystyle 33\frac{1}{3}$$%

Solution

Question 10

$$32\%$$

$$34\%$$

$$36\%$$

$$38\%$$

Solution

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