Comparing Quantities Test

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Comparing Quantities Test - 52

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Question 1
1 / -0

A person buys $$100$$ caps at Rs. $$10$$ each. On the way $$10$$ caps are Stolen. He sells the remaining caps at Rs. $$12$$ each. His Profit per cent is ?

A
$$5$$%

B
$$6$$%

C
$$7$$%

D
$$8$$%

Solution

Person buys 100 caps at Rs 10 each.

So, Cost Price (CP) $$=100\times10=1000\ Rs$$

10 caps are stolen. Remaining $$100-10=90$$ are sold at Rs 12 each.

So, Selling Price (SP) $$=90\times12=1080\ Rs$$

$$\therefore Profit=SP-CP = 1080-1000=80\ Rs$$

$$\Rightarrow Profit\ percentage=\dfrac{profit\times 100}{CP}=\dfrac{80\times 100}{1000}=8\%$$
Question 2
1 / -0

Convert $$\dfrac{15}{50}$$ into percentage

A
$$35\%$$

B
$$30\%$$

C
$$25\%$$

D
$$20\%$$

Solution

$$\Rightarrow$$ We have to convert $$\dfrac{15}{50}$$ into percentage.
$$\Rightarrow$$ $$\%=(\dfrac{15}{50}\times 100)\%$$

$$\Rightarrow$$ $$\%=(15\times 2)\%$$

$$\therefore$$ $$\%=30\%$$
Question 3
1 / -0

Convert $$\dfrac{14}{25}$$ into percentage

A
$$55\%$$

B
$$56\%$$

C
$$57\%$$

D
$$58\%$$

Solution

$$\Rightarrow$$ We have to convert $$\dfrac{14}{25}$$ into percentage.
$$\Rightarrow$$ $$\%=(\dfrac{14}{25}\times 100)\%$$

$$\Rightarrow$$ $$\%=(14\times 4)\%$$

$$\therefore$$ $$\%=56\%$$
Question 4
1 / -0

Find the profit per cent or loss per cent made when the S.P. of 15 identical articles is equal to the C.P. of 30 articles.

A
Profit = $$\displaystyle 33\frac{1}{3}$$%

B
Profit = $$55$$%

C
Profit = $$100$$%

D
Profit = $$\displaystyle 73\frac{1}{3}$$%

Solution

Let cost price of an article $$= X\ Rs$$

Cost price for 15 articles $$= 15X\ Rs$$

Selling price for 15 articles = Cost Price of 30 articles $$= 30X\ Rs$$ ( Given)

So, $$Profit=Selling\ price-Cost\ price=30X-15X=15X\ Rs$$

$$\therefore Profit\ percentage=\dfrac{profit\times100}{Cost\ price}=\dfrac{15X\times100}{15X}=100\%$$
Question 5
1 / -0

If SP of an article is $$\displaystyle\frac{5}{4}$$ of its CP then the profit percentage in the transaction is :

A
$$10$$

B
$$20$$

C
$$30$$

D
$$25$$

Solution

Let $$CP = x$$

Given that, $$SP=\dfrac{5}{4}CP=\dfrac{5x}{4}$$

$$\therefore profit = SP-CP=\dfrac{5}{4}SP-SP=\dfrac{SP}{4}=\dfrac{x}{4}$$

$$\therefore profit\ percentage=\dfrac{profit\times100}{CP}=\dfrac{\dfrac{x}{4}\times100}{x}=25\%$$
Question 6
1 / -0

C.P. $$=$$ Rs. $$250$$, S.P. $$=$$ Rs. $$285$$, then Profit $$=$$ ________$$\%$$

A
$$12$$

B
$$13$$

C
$$14$$

D
$$15$$
Question 7
1 / -0

Equal sums of Rs.$$7200$$ were lent to Megha and Priya at $$5$$ $$\%$$ per annum for a period of $$4$$ years and $$5$$ years respectively. Find the difference of the interest paid by Megha and Priya.

A
Rs.$$140$$

B
Rs.$$560$$

C
RS.$$260$$

D
Rs.$$360$$

Solution

Simple interest on the sum $$P$$ at rate of interest $$R$$ for $$N$$ years is given as $$\dfrac{PNR}{100}$$
$$\text{Interest paid by Priya} = \dfrac{7200\times 5\times 5}{100}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =Rs\ 1800$$

$$\text{Interest paid by Megha} = \dfrac{7200\times 4\times 5}{100}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =Rs\ 1440$$

Difference $$= 1800-1440$$
$$=Rs\ 360$$
Hence, D is the right option.
Question 8
1 / -0

A particular sum was divided among A, B and C in the ratio $$2:6:7$$ respectively. If the amount received by A was Rs. $$4,908$$, what was the difference between the amounts received by B and C?

A
Rs. $$2,454$$

B
Rs. $$3,494$$

C
Rs. $$2,135$$

D
Rs. $$2481$$

E
None of these$$

Solution

Amount received by A$$=$$ Rs. $$4908$$
Amount received by B$$=\displaystyle\frac{4908}{2}\times 6=$$Rs.$$14724$$
Amount received by C$$=\displaystyle\frac{4908}{2}\times 7=$$Rs. $$17178$$
Required difference $$=17178-14724$$
$$=$$Rs. $$2454$$.
Question 9
1 / -0

Madhavi bought a scooter for $$Rs. 40,000$$ but she does not have enough money to pay all at once. The shopkeeper says that she can divide the cost into 4 equal monthly instalments but she would have to pay $$Rs.100$$ extra each month for 4 months. What is this additional amount paid by Madhavi to the shopkeeper called as and calculate the total extra amount at the end of 4 months paid by Madhavi?

A
Profit, $$Rs. 400$$

B
Principal, $$Rs. 400$$

C
Loss, $$Rs. 400$$

D
Interest, $$Rs. 400$$

Solution

$$Cost \space of \space scooter=Rs.40000$$
$$No. \space of \space installments=4$$
$$\therefore cost \space of \space each \space installments=\frac{40000}{4}$$
$$=10000$$
$$But \space 100 \space is \space paid \space extra \space in \space each \space instalment.$$
$$Total \space extra \space amt. \space paid=100\times4=400$$
The seller costs this extra $$400$$ as interest as the profit is included in $$Rs.40000$$
$$\therefore option \space D$$
Question 10
1 / -0

Sugar is bought at Rs. $$16.20$$ per kg and sold at Rs. $$17.28$$ per kg. The gain percent is ____________.

A
$$\displaystyle 6\frac{2}{3}\%$$

B
$$\displaystyle 3\frac{1}{3}\%$$

C
$$10\%$$

D
$$\displaystyle 10\frac{2}{3}\%$$

Solution

Cost Price (CP) of 1 kg of sugar $$= 16.20$$ Rs

Selling Price (SP) of 1 kg of sugar $$=17.28$$ Rs

$$Gain = SP-CP=17.28-16.20=1.08\ Rs$$

$$Gain\ Percent=\dfrac{Gain\times100}{CP}=\dfrac{1.08\times100}{16.20}=\dfrac{20}{3}=6\dfrac{2}{3}\%$$

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Comparing Quantities Test - 52

Result

Comparing Quantities Test - 52

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SHARING IS CARING

Question 1

$$5$$%

$$6$$%

$$7$$%

$$8$$%

Solution

Question 2

$$35\%$$

$$30\%$$

$$25\%$$

$$20\%$$

Solution

Question 3

$$55\%$$

$$56\%$$

$$57\%$$

$$58\%$$

Solution

Question 4

Profit = $$\displaystyle 33\frac{1}{3}$$%

Profit = $$55$$%

Profit = $$100$$%

Profit = $$\displaystyle 73\frac{1}{3}$$%

Solution

Question 5

$$10$$

$$20$$

$$30$$

$$25$$

Solution

Question 6

$$12$$

$$13$$

$$14$$

$$15$$

Question 7

Rs.$$140$$

Rs.$$560$$

RS.$$260$$

Rs.$$360$$

Solution

Question 8

Rs. $$2,454$$

Rs. $$3,494$$

Rs. $$2,135$$

Rs. $$2481$$

None of these$$

Solution

Question 9

Profit, $$Rs. 400$$

Principal, $$Rs. 400$$

Loss, $$Rs. 400$$

Interest, $$Rs. 400$$

Solution

Question 10

$$\displaystyle 6\frac{2}{3}\%$$

$$\displaystyle 3\frac{1}{3}\%$$

$$10\%$$

$$\displaystyle 10\frac{2}{3}\%$$

Solution

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