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Comparing Quantities Test - 53

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Comparing Quantities Test - 53
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  • Question 1
    1 / -0
    In a village three different crops are cultivated in four successive years. The profit(in rupees) on the crops, per acre is shown in the table below-
    Crop\Year2005200620072008
    Ground nuts7000800075007500
    Jawar6000100080001000
    Millets9000500030004000

    Based on your answers, which crop should be cultivated in the next year?
    Solution

  • Question 2
    1 / -0
    Aarati bought 10 dresses at Rs 6300. She paid Rs 200 extra as expenses. If she sold all the dresses at the cost of Rs 780 per dress, how much percentage profit or loss does she make?
    Solution
    Cost price of $$10$$ dresses is $$Rs.\ 6300$$ and expanses is $$Rs.\ 200$$.

    So, cost price after expanses$$=Rs.\ (6300+200)=Rs.\ 6500$$

    Also, selling price of $$1$$ dress is $$Rs.\ 780$$.

    Hence, selling prince $$10$$ dresses$$=10\times 780=Rs.\ 7800$$

    Now, $$SP>CP$$, so their will be net profit.

    So, profit percent is,

    $$Profit(\%)=\dfrac{7800-6500}{6500}\times 100=\dfrac{1300}{65}=20\%$$
  • Question 3
    1 / -0
    The simple interest at $$x\%$$ for $$x$$ years will be Rs. $$x$$ on a sum of _________.
    Solution
    Let principal sum be $$y$$
    Simple Interest $$=$$ Principal $$\times$$ Rate $$\times$$ Time

    $$\therefore x = y\times \dfrac{x}{100} \times x$$

    $$\therefore y =$$  Rs. $$\dfrac{100}{x}$$
  • Question 4
    1 / -0
    A dishonest dealer professes to sell his goods at cost price. But he uses a false weight'  and thus gains $$6\frac {18}{47}$$ %. For a kg, he uses a weight of  
    Solution
    Let the error is $$xgm$$ and profit is $$6\frac{18}{47}\%= \frac{300}{47}\%$$
    So we have , 
    $$\dfrac{Error}{True weight- Error}\times 100=\%\:  of \: profit$$
    $$\implies \frac{x}{1000-x}\times100=\dfrac{300}{47}$$
    $$\implies x=60$$
    Therefore error is $$60gm$$. Hence for a kg he uses a weight of $$1000-60=940gms$$
  • Question 5
    1 / -0
    Subhash purchased a tape recorder at $$\left(\displaystyle\frac{9}{10}\right)^{th}$$ of its selling price and sold it at $$8\%$$ more than its S.P. His gain percent is _________.
    Solution
    he bought the tape for $$0.9 \times (S.P.)$$

    and sell it for $$1.08\times  (S.P.)$$

    gain percentage $$=\dfrac{1.08\times (S.P.)-0.9\times (S.P.)}{0.9\times (S.P.)}$$
    $$=\dfrac{0.18}{0.9}=0.2$$

    $$=20 \%$$
  • Question 6
    1 / -0
    A man earns Rs. $$20$$ on the first day and spends Rs. $$15$$ on the next day. He again earns Rs. $$20$$ on the third day and spends Rs. $$15$$ on the fourth day. If he continues to save in this way, how soon will he have Rs. $$60$$ in hand?
    Solution
    In two days saving $$=$$Rs. $$5$$
    Saving in $$16$$ days $$=$$ Rs. $$40$$
    Income on $$17$$th day $$=$$Rs. $$60$$
    Inhand on $$17$$th day $$=$$Rs. $$60$$.
  • Question 7
    1 / -0
    Bhajan Singh purchased $$120$$ reams of paper at Rs. $$80$$ per ream. He spent Rs. $$280$$ on transportation, paid octroi at the rate of $$40$$ paise per ream and paid Rs. $$72$$ to the coolie. If he wants to have a gain of $$8\%$$, what must be the selling price per ream?
    Solution
    Total money he spent $$=(120\times 80)+(280+0.4)\times (120+72)$$ 
                                         $$=10000$$
    Let the selling price of paper per ream is $$x$$ then total $$S.P.=120x$$

    If he wants to have a gain of $$8\% $$.

    Then by using the formula $$P\%=\dfrac{S.P.-C.P.}{C.P.}\times100$$

    $$8=\dfrac{120x-10000}{10000}\times100$$

    $$\Rightarrow 120x=1.08\times 10000$$

    $$\Rightarrow x=90$$

    Therefore, selling price per ream is Rs. $$90$$.
  • Question 8
    1 / -0
    A man sells two horses for Rs. 4000 each, neither losing nor gaining in the deal. If he sold one horse at a gain of 25$$\%$$, the other horse is sold at a loss of _____ .
    Solution
    Given that, selling price of 1 horse=Rs 4000
    and profit $$\%=25\%$$
    We know that, $$\text{cost price}(C.P.)=\dfrac{S.P.\times 100}{100+\text{profit}\%}$$
    $$\therefore \ C.P.=\dfrac{4000\times 100}{125}=3200$$
    Since the man is having neither loss nor gain.
    $$\therefore$$ C. P. of second horse=S.P. of 2 horses - C.P. of 1 horse
    $$=Rs.\ (8000-3200)=Rs.\  4800$$
    $$\therefore \ $$ C.P. of $$2^{nd}$$ horse $$= Rs. \ 4800$$ and S.P.$$=Rs.\ 4000$$
    $$\therefore\ Loss=C.P.-S.P.=Rs.\ 800$$
    $$\Rightarrow Loss\, \% =\dfrac{800}{4800}\times 100 =16\dfrac{2}{3}\%$$
    Hence, option B is correct.
  • Question 9
    1 / -0
    A shopkeeper sold an article for $$\text{Rs. } 2090.42$$ without any loss or profit. Approximately, what will be the profit percent, if he sells that article for  $$\text{Rs. }2602.58$$?
    Solution
    Selling price of an article without any loss or profit $$=\text{Rs. } 2090.42$$
    $$\therefore$$ Cost price $$=\text{Rs. } 2090.42$$
    New selling price $$=\text{Rs. } 2602.58$$
    Profit $$=S.P - C.P. = \text{Rs. }2602.58 - \text{Rs. } 2090.42 $$
    $$=\text{Rs. } 512 .16$$
    $$\therefore\text{Profit} \%=\dfrac{\text{Profit}}{C.P} \times 100 = \dfrac{512.16}{2090.42}\times 100$$
     $$\simeq  25\%$$ (approx)

  • Question 10
    1 / -0
    Venkat purchased $$20$$ dozens of toys at the rate of Rs. $$375$$ per dozen. He sold each one of them at the rate of Rs. $$33$$ per toy. What was his percentage profit?
    Solution
    $$CP$$ of 20 dozen toys$$=375\times20=$$ $$Rs.$$ $$7500$$
    $$SP$$ of 20 dozen toys$$=33\times 12\times 20 =$$ $$Rs.$$ $$7920$$

    $$\therefore$$ Profit $$=7920-$$$$7500$$
                 $$=Rs. 420$$

    $$\therefore$$ Profit $$\%=\dfrac{Profit}{CP}\times 100 = \dfrac{420\times100}{7500}=5.6\%$$
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