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Comparing Quantities Test - 54

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Comparing Quantities Test - 54
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  • Question 1
    1 / -0
    Choose the correct answer from the alternative given.
    If the annual rate of simple interest increases from 10% to 12.5% . A mans yearly income increases by Rs. 1250. his principal (in rupees) is:
    Solution
    Change in Rate of interest= (25210)%=52%\left ( \dfrac{25}{2} - 10 \right )\%= \dfrac{5}{2}\%
    According to the question, 
    52\dfrac{5}{2}% of principal = Rs. 1250
    Hence, Principal = 1250× 2×1005\dfrac{1250 \times 2 \times 100}{5} = Rs. 50000
  • Question 2
    1 / -0
    A shopkeeper mixes two varieties of Tea, one costing Rs. 4040/kg and another Rs. 5050/kg in the ratio 3:23:2. if he sells the mixed variety of Tea at Rs. 4848/kg, his gain or loss percent is
    Solution
    Average CP of Mixed Tea when Mixed in Ratio 3:23:2
    =40×3+50×23+2=2205=Rs.44=\cfrac { 40\times 3+50\times 2 }{ 3+2 } =\cfrac { 220 }{ 5 } =Rs.44
    Wen SP=Rs. 48/kg48/kg
    =444×100=9.0910=\cfrac { 4 }{ 44 } \times 100=9.09\approx 10% gain
  • Question 3
    1 / -0
    If some articles are bought at prices ranging from Rs. 200 to Rs. 350 and are sold at prices ranging from Rs. 300 to Rs. 425, what is the maximum possible profit that might be made in selling 16 such articles?
    Solution
    Maximum profit will be if we purchase in minimum
    price & sell in maximum price.
    Minimum price for purchasing = Rs 200
    Maximum price for purchasing =  Rs 425
    Net profit on 1 article 425200=Rs225 425 - 200 = Rs\, 225
    Net profit on 16 article =225×16= Rs3600 = 225 \times 16 =  Rs \,3600

  • Question 4
    1 / -0
    A farmer took a loan at 12% p.a. at S.I. After 4 years he settled the loan by paying Rs. 2,442. What was the principal amount?
    Solution

  • Question 5
    1 / -0
    A trader sells rice at a profit of 2020% and uses weights which are 1010% less than the correct weight. The total gain earned by him is:
    Solution
    Let us consider a packet of rice maked 1 kg.1\text{ kg}. But its actual weight is 90%90\% of 1000 gm=900 gm.1000\text{ gm}=900\text{ gm}.

    Let C.P of each gram of rice is Rs. 1.\text{Rs. }1. Then, C.P of this packet will be Rs. 900.\text{Rs. }900.

    S.P of this packet will be 120%120\% of C.P of 1 kg.1\text{ kg}. So,
    S.P=120100×1000S.P=\cfrac { 120 }{ 100 } \times 1000
             =Rs. 1200=\text{Rs. }1200

    \therefore Gain %(300900×100)=3313\left( \cfrac { 300 }{ 900 } \times 100 \right) =33\cfrac { 1 }{ 3 } %
  • Question 6
    1 / -0
    A shopkeeper sells a T.V. set of Rs 16560\text{Rs }16560 at 10%10\% discount on its marked price and earns 15%15\% profit. If no discount is offered, then what will be his present profit?
    Solution
    Cost price of the article=Rs 16560=\text{Rs }16560
    let marked price be Rs x\text{Rs }x
    discount =10%=10\%
    $$\text{S.P.=M.P.}\left(\dfrac{100-\text{discount %}}{100}\right)$$
    =x(10010100)=x\left(\dfrac{100-10}{100}\right)
    =9x10=\dfrac{9x}{10}
    Profit =15%=15\%
    Profit %=ProfitC.P.×100\%=\dfrac{\text{Profit}}{C.P.}\times 100  Where, Profit == Selling price - Cost price

        15=S.P.C.P.C.P.×100\implies 15=\dfrac{S.P.-C.P.}{C.P.}\times 100
        15×16560=(9x1016560)×100\implies 15\times 16560=\left(\dfrac{9x}{10}-16560\right)\times 100
        15×1656=9x165600\implies 15\times 1656=9x-165600
        9x=165600+24840=190440\implies 9x=165600+24840=190440
        x=21160\implies x=21160
     M.P.=21160\therefore ~M.P. =21160
    If  no discount  is offered then S.P.=M.P.S.P.=M.P.
    Profit=S.P.C.P.\therefore Profit =S.P.-C.P.
    =2116016560=21160-16560
    =4600=4600
    Profit %=ProfitC.P.×100\therefore Profit ~\% =\dfrac{Profit}{C.P.}\times 100
    =460016560×100%=\dfrac{4600}{16560}\times 100\%

    =2509%=\dfrac{250}{9}\%
    \therefore Profit is 2509%\dfrac{250}{9}\%
  • Question 7
    1 / -0
    The sale price of an article including taxes is Rs. 616.Rs.\ 616. The rate of sales tax is 10%.10\%. If the shopkeeper has made a profit of 12%.12\%. find the cost price
    Solution
    Let us assume that the sales price and cost price of the article is xx and y.y.


    SP+Tax=616x+10x100=61611x10=616x=616×1011=Rs. 560\begin{aligned}{}SP + Tax& = 616\\x + \frac{{10x}}{{100}}& = 616\\\frac{{11x}}{{10}} &= 616\\x& = \frac{{616 \times 10}}{{11}}\\ &=Rs.\ 560\end{aligned}

    And,
    CP+Profit=SPy+12y100=56028y25=560y=560×2528=Rs. 500\begin{aligned}{}CP + Profit &= SP\\y + \frac{{12y}}{{100}}& = 560\\\frac{{28y}}{{25}} &= 560\\y& = \frac{{560 \times 25}}{{28}}\\ &=Rs.\ 500\end{aligned}

    Hence, the cost price of the article is Rs. 500.Rs.\ 500.
  • Question 8
    1 / -0
    A shirt was sold at a profit of 15%\%. If its cost had been 5%\% less and it had been sold for Rs. 21 less, then the profit would have been 10%\%. Find the cost of the shirt.
    Solution
    Given that:
    A shirt was sold at a profit of 15%15\%.
    If the cost had been 5%5\% less, and it had been sold for Rs. 21Rs.\ 21 less, then the profit would have been 10%10\%.

    To find out:
    The cost of the shirt.

    Let the cost of the shirt be Rs. xRs.\ x.
    We know that, S.P.=(profit%+100)C.P.100S.P.=\dfrac{(profit\%+100)C.P.}{100}
    Here, profit%=15profit\%=15

     S.P.=(15+100)x100\therefore\ S.P.=\dfrac{(15+100)x}{100}\\
    S.P.=1.15x\Rightarrow S.P.=1.15x\\

    Now, if the cost is 5%5\% less, then,
    C.P.=95% of xC.P.=95\%\ of\ x\\
    C.P.=95100x\Rightarrow C.P.=\dfrac{95}{100}x\\
     C.P.=0.95x\therefore \ C.P.=0.95x\\
    Also, the selling price is Rs. 21Rs. \ 21 less.
     S.P.=1.15x21\therefore\ S.P.=1.15x-21\\
    In this case, the profit would have been 10%10\%, as given in the problem.

    Now, we know that, profit%=S.P. C.P.C.P.×100profit\%=\dfrac{S.P.-\ C.P.}{C.P.}\times 100

     10=(1.15x21)0.95x0.95x×100\therefore \ 10=\dfrac{(1.15x-21)-0.95x}{0.95x}\times 100\\
     10=1.15x210.95x0.95x×100\Rightarrow  10=\dfrac{1.15x-21-0.95x}{0.95x}\times 100\\
     10×0.95x=(0.20x21)×100\Rightarrow  10\times 0.95x=(0.20x-21)\times 100\\
     9.5x=20x2100\Rightarrow  9.5x=20x-2100\\
     20x9.5x=2100\Rightarrow  20x-9.5x=2100\\
     10.5x=2100\Rightarrow  10.5x=2100\\
     x=210010.5\Rightarrow  x=\dfrac{2100}{10.5}\\
     x=Rs. 200\therefore \ x=Rs.\ 200\\

    Hence, the cost of the shirt is Rs. 200Rs.\ 200.
  • Question 9
    1 / -0
    PP sells a table to QQ at a profit of 1010% and QQ sells it to RR at a profit of 1212%. If RR pays Rs. 246.40246.40 for it, then how much had PP paid for it?
    Solution
    Let PP paid for table == Rs. PP
    After all RR paid =Rs. 246.40246.40
    According to the question,
    246.40=P[110100 ][112100 ]246.40=P\left[ \cfrac { 110 }{ 100 }  \right] \left[ \cfrac { 112 }{ 100 }  \right]
    P=246.40×100×100110×112P=\cfrac { 246.40\times 100\times 100 }{ 110\times 112 }
    =24640011×112=\cfrac { 246400 }{ 11\times 112 }
    =Rs.200 =Rs.200
  • Question 10
    1 / -0
    A shopkeeper offers successive discounts of 2020%, 1010% and 55% respectively on a Titan watch which is marked at Rs.15001500. He offers successive discounts of 2020%. 2020% and 1010% espectively on a Ajanta watch which is marked at Rs. 20002000. What is the difference between their selling price?
    Solution
    Selling price of Titan watch
    = 0.8×0.9×0.95×1500=Rs.10260.8 \times 0.9 \times 0.95 \times 1500 = Rs. 1026
    Selling price of Ajanta watch
    = 0.8×0.8×8.9×2000=Rs.11520.8 \times 0.8 \times 8.9 \times 2000 = Rs. 1152
    Difference is selling price = Rs.(11521026)=Rs.126 (1152 - 1026) = Rs. 126
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