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Comparing Quantities Test - 55

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Comparing Quantities Test - 55
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  • Question 1
    1 / -0
    A loss of $$20$$% is incurred when $$6$$ articles are sold for a rupee. To gain $$20$$% how many articles should be sold for a rupee?
    Solution
    Given than, $$SP = 1, Loss$$% $$= 20$$%
    We know that, $$SP = 0.8\times CP$$
    $$CP = \dfrac {5}{4}$$
    To gain $$20$$%, $$SP = 1.2\times CP = \dfrac {120}{100}\times \dfrac {5}{4} = \dfrac {3}{2} \Rightarrow SP = \dfrac {3}{2}$$
    For $$Rs. 3/2$$ number of articles sold $$= 6$$
    For $$Rs. 1$$ number of articles to be sold $$= 6\times \dfrac {2}{3} = 4$$ articles.
  • Question 2
    1 / -0
    A, B, C enter into partnership. A invests some money at the beginning, B invests double the amount after $$6$$ months and C invests thrice the amount after $$8$$ months. If the annual profit is Rs$$27,000$$. C's share is (in Rs)
    Solution
    Let the amount A invest is Rs$$x$$.
    Time period of investment of A is $$12$$ months.
    Amount B invest is Rs$$2$$x.
    Time period of investment of B is $$6$$ months.
    Amount C investment is Rs$$3$$x.
    Time period of investment of C is $$4$$ months.
    Profit is divided in the ratio = Amount of investment \times Time period of investment
    $$P_A : P_B : P_C = x \times 12 : 2x \times 6 : 3x \times 4$$
    =$$12 x : 12 x : 12 x$$
    =$$1 : 1 : 1$$
    C's share of profit = $$\dfrac{1}{3} \times 27000 = 9000$$
  • Question 3
    1 / -0
    A house and store were sold for $$\text{Rs. } 12,000$$ each. The house was sold at a loss of $$20\%$$ of the cost and the store at a gain of $$20\%$$ of the cost. The entire transaction resulted in
    Solution
    $$12,000 = H - \dfrac {1}{5}H  \therefore H = 15,000$$
    $$12,000 = S + \dfrac {1}{5}S  \therefore S = 10,000$$
    $$ H + S = 25,000$$.
    Therefore, the sale resulted in a loss of $$Rs. 1000$$.
  • Question 4
    1 / -0
    Select the ratio that is equivalent to $$12:14$$
    Solution
    Given ratio is $$12:14$$
    It can be rewritten as $$\dfrac{12}{14}=\dfrac{6\times 2}{7\times 2}$$
    Cancelling $$2$$ from numerator and denominator, we get
    $$\dfrac{12}{14}=\dfrac{6}{7}$$ i.e $$6:7$$
    Hence, the answer is $$6:7$$.
  • Question 5
    1 / -0
    A shop keeper earns a profit of $$12$$% on selling a book at $$10$$% discount on the printed price. The ratio of cost price to the printed price of the book is
    Solution
    Using the formula
    $$\dfrac {100\pm (Profit\ Loss)}{100 - Discount} = \dfrac {M.P}{C.P}$$
    $$\dfrac {M.P}{C.P} = \dfrac {112}{100 - 10} = \dfrac {112}{90} = \dfrac {56}{45}$$
    Hence, $$\dfrac {C.P}{M.P} = \dfrac {45}{56}$$.
  • Question 6
    1 / -0
    Mr,A owns a home worth Rs.$$10,000$$. He sells it to Mr.B at a $$10\%$$ profit based on the worth of the house. Mr.B sells the house back to Mr.A at a $$10\%$$ loss. Then:
    Solution
    $$\text{C.P. of B = 110% of Rs. 10000 = Rs. 11000}$$
    $$\text{Loss of B = 10%}$$
    $$\text{S.P. of B = 90% of Rs. 11000 = Rs. 9900}$$
    $$\text{Thus, C.P. of A = Rs. 9900}$$
    $$\text{So, A gets [(10% of Rs. 10000) + (10000 - 9900)] = Rs. 1100}$$
  • Question 7
    1 / -0
    The cost $$C$$ of sending a parcel post package weighing $$P$$ gms, $$P$$ an integer is $$Rs. 10$$ for the first grams and $$Rs. 3$$ for each additional grams. The formula for the cost is
    Solution
    For $$P - 1$$ gms the charge is $$3$$ rupees per grams. For the first gram the charge is $$10$$ rupees. $$\therefore C = 10 + 3(P - 1)$$; or
    The charge for each gram is $$3$$ rupees with an additional charge of $$7$$ rupees for the first gram. $$\therefore C = 3P + 7 = 3P - 3 + 10 = 10 + 3(P - 1)$$.
  • Question 8
    1 / -0
    $$5$$% more is gained by selling a watch for $$Rs. 350$$ than by selling it for $$Rs. 340$$. The cost price of the watch is
    Solution
    Let cost price be $$Rs. x$$
    Then $$5$$% of $$x = (350 - 340)$$
    $$5$$% of $$x = 10$$
    $$x = 10\times \dfrac {100}{5} = 200$$
    Hence, cost price is $$Rs. 200$$.
  • Question 9
    1 / -0
    Tanishka deposited Rs. $$50,000$$ in a bank for two years with the interest rate of $$5.5\%$$ p.a. How much interest would she earn?
    Solution
    $$ Interest = \cfrac{ 50000 \times 2 \times 5.5 }{100} = 5500$$
  • Question 10
    1 / -0
    A sum of money invested at 14$$\%$$ per annum amounted to Rs. 10400 in 5 years. Calculate the principal.
    Solution
    We have the formula for amount in simple interest as:

    $$A=P(1+rt)$$

    Given, $$A=10400$$, $$t=5$$, $$r=14\%$$

    $$\therefore \ 10400=P(1+5(0.14))$$

    $$10400=P(1+0.7)=P(1.7)$$

    $$P=\dfrac{10400}{1.7}$$

    $$=6117.647.6$$

    Hence, the principal amount is Rs. $$6117.65$$.
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