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Comparing Quantities Test - 58

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Comparing Quantities Test - 58
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  • Question 1
    1 / -0
    A retailer buys a radio for Rs. $$225$$. His overhead expenses are Rs. $$15$$. If he sells the radio for Rs. $$300$$, determine his profit percent.
    Solution
    cost price for radio=$$225+15$$
    $$ = 240 Rs. $$
    profit$$=x\%$$

    $$ 240+\dfrac{x}{100}(240)=300$$

    $$ 240$$$$\left ( \dfrac{x+100}{100} \right )$$=$$300$$

     ($$x+100$$)=$$\dfrac{1000}{8}$$ 

    $$x$$=$$250-100 \%$$

    $$x$$=$$25\%$$
  • Question 2
    1 / -0
    If the cost price is $$96\%$$ of the selling price, then what is the profit percent?
    Solution
    If the $$CP$$ is $$96\%$$ of the $$SP$$
    $$i.e SP=100$$ then $$CP=96$$
    Profit $$=SP-CP$$
    profit $$\Rightarrow 4$$
    profit $$\%\Rightarrow \dfrac{4}{96}\times 100$$
    $$\Rightarrow 4.16\%$$

  • Question 3
    1 / -0
    If the cost of transporting $$150$$ kg of goods for $$120$$ km is Rs $$50.$$ what will be the cost of transporting $$180$$ kg of goods for $$300$$ km?
    Solution

    Cost of transporting $$150\ kg$$ over $$120\ km=50$$

    Cost of transporting $$1\ kg$$ over $$1\ km=\dfrac{50}{(150\times 130)}$$

    Cost of transporting $$180\ kg$$ over $$300\ km=\dfrac{50}{(150\times 130)}\times (180\times 300)=Rs.150$$

  • Question 4
    1 / -0
    Aditya bought $$200$$ dozen orange at $$Rs.\ 10$$ per dozen and he spent $$Rs. \ 500$$ on transportation. He sold each orange at $$Rs.\ 1$$ each. What was his profit or loss $$\%$$ ?
    Solution

  • Question 5
    1 / -0
    Ram purchases a chair at $$Rs.70$$ and spent $$Rs.17$$ on its repair and $$50$$ paise on cartage. If he sold the chair at $$Rs.100$$ then his approximate margin of profit will be ?
    Solution
    $$Profit ~\%=\dfrac{SP-CP}{CP}\times100$$

                     $$=\dfrac{100-87.5}{87.5}\times100$$

                     $$=14.3\%$$
  • Question 6
    1 / -0
    15% of 10% of 20% of 1000 is 
    Solution
    $$15\%$$ of $$10\%$$ of $$20\%$$ of $$1000$$

    $$\Rightarrow 15\%$$ of $$10\%\left[\dfrac{20}{100}\times 1000\right]$$

    $$\Rightarrow 15\%$$ of $$10\%$$ of $$200$$

    $$\Rightarrow 15\%\left[\dfrac{10}{100}\times 200\right]$$

    $$\Rightarrow 15\%$$ of $$20$$

    $$\Rightarrow \dfrac{15}{100}\times 20$$

    $$\Rightarrow  3$$

    $$\therefore\ 15\%$$ of $$10\%$$ of $$20\%$$ of $$1000=3$$
  • Question 7
    1 / -0
    If Rs $$2800$$ is $$\dfrac{2}{7}th$$ of the value of a house, the worth of the house (in Rs ) is?
    Solution
    let the worth of the house be $$x$$ 
    Given that $$\dfrac {2}{7}$$ of value of house is $$2800$$
    $$\dfrac {2}{7}x=2800$$
    $$x=2800\times \dfrac {7}{2}$$
    $$=1400\times 7$$
    $$Rs. 9800$$
    Worth of house $$=Rs. 9800$$

  • Question 8
    1 / -0
    Ram, Karan and Rohan invested capital in the ratio of $$2 : 3 : 4$$ for time period of $$6 : 4 : 3$$ . Find the ratio of profit distributed?
    Solution
    Profit depends on total amount invested.
    amount invested by Ram = $$2\times6 = 12k$$
    amount invested by Karan = $$3\times 4 = 12k$$
    amount invested by Rohan = $$4\times 3 = 12k$$

    As amount total invested is same in all three cases hence profit distributed will be same and is $$1 : 1 : 1$$
  • Question 9
    1 / -0
    Which of the following is the most beneficial customer? 
    Solution
    More the discount more it is beneficial Let $$x$$ be the cost price of article.
    a) $$2$$ successive discount $$\rightarrow \dfrac{20}{100}\times \left[\dfrac{20}{100}x\right]\rightarrow \left[\dfrac{x}{25}\right]$$
    b) $$40\%$$ at a time discount $$\rightarrow \dfrac{40}{100}x\rightarrow \left[\dfrac{2x}{5}\right]\rightarrow \left[\dfrac{10x}{25}\right]$$
    $$\therefore b \,discount >a\,discount$$

  • Question 10
    1 / -0
    The owner of a toy shop charges his customer $$33$$% more then the cost price. If the customer paid Rs. $$4921$$ for a toy, then what was the cost price of the toy?
    Solution
    Let cost price of the toy $$=x$$ 

    Owner will change $$=x+ \dfrac{33}{100} \times x$$
    $$=494$$

    $$4921=\dfrac{133}{100}x$$

    $$x=\dfrac{4921 \times 100}{133}$$

    $$x=3700\ Rs$$
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