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Comparing Quantities Test - 58

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Comparing Quantities Test - 58
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  • Question 1
    1 / -0
    A retailer buys a radio for Rs. 225225. His overhead expenses are Rs. 1515. If he sells the radio for Rs. 300300, determine his profit percent.
    Solution
    cost price for radio=225+15225+15
    =240Rs. = 240 Rs.
    profit=x%=x\%

    240+x100(240)=300 240+\dfrac{x}{100}(240)=300

    240 240(x+100100)\left ( \dfrac{x+100}{100} \right )=300300

     (x+100x+100)=10008\dfrac{1000}{8} 

    xx=250100%250-100 \%

    xx=25%25\%
  • Question 2
    1 / -0
    If the cost price is 96%96\% of the selling price, then what is the profit percent?
    Solution
    If the CPCP is 96%96\% of the SPSP
    i.eSP=100i.e SP=100 then CP=96CP=96
    Profit =SPCP=SP-CP
    profit 4\Rightarrow 4
    profit %496×100\%\Rightarrow \dfrac{4}{96}\times 100
    4.16%\Rightarrow 4.16\%

  • Question 3
    1 / -0
    If the cost of transporting 150150 kg of goods for 120120 km is Rs 50.50. what will be the cost of transporting 180180 kg of goods for 300300 km?
    Solution

    Cost of transporting 150 kg150\ kg over 120 km=50120\ km=50

    Cost of transporting 1 kg1\ kg over 1 km=50(150×130)1\ km=\dfrac{50}{(150\times 130)}

    Cost of transporting 180 kg180\ kg over 300 km=50(150×130)×(180×300)=Rs.150300\ km=\dfrac{50}{(150\times 130)}\times (180\times 300)=Rs.150

  • Question 4
    1 / -0
    Aditya bought 200200 dozen orange at Rs. 10Rs.\ 10 per dozen and he spent Rs. 500Rs. \ 500 on transportation. He sold each orange at Rs. 1Rs.\ 1 each. What was his profit or loss %\% ?
    Solution

  • Question 5
    1 / -0
    Ram purchases a chair at Rs.70Rs.70 and spent Rs.17Rs.17 on its repair and 5050 paise on cartage. If he sold the chair at Rs.100Rs.100 then his approximate margin of profit will be ?
    Solution
    Profit %=SPCPCP×100Profit ~\%=\dfrac{SP-CP}{CP}\times100

                     =10087.587.5×100=\dfrac{100-87.5}{87.5}\times100

                     =14.3%=14.3\%
  • Question 6
    1 / -0
    15% of 10% of 20% of 1000 is 
    Solution
    15%15\% of 10%10\% of 20%20\% of 10001000

    15%\Rightarrow 15\% of 10%[20100×1000]10\%\left[\dfrac{20}{100}\times 1000\right]

    15%\Rightarrow 15\% of 10%10\% of 200200

    15%[10100×200]\Rightarrow 15\%\left[\dfrac{10}{100}\times 200\right]

    15%\Rightarrow 15\% of 2020

    15100×20\Rightarrow \dfrac{15}{100}\times 20

     3\Rightarrow  3

     15%\therefore\ 15\% of 10%10\% of 20%20\% of 1000=31000=3
  • Question 7
    1 / -0
    If Rs 28002800 is 27th\dfrac{2}{7}th of the value of a house, the worth of the house (in Rs ) is?
    Solution
    let the worth of the house be xx 
    Given that 27\dfrac {2}{7} of value of house is 28002800
    27x=2800\dfrac {2}{7}x=2800
    x=2800×72x=2800\times \dfrac {7}{2}
    =1400×7=1400\times 7
    Rs.9800Rs. 9800
    Worth of house =Rs.9800=Rs. 9800

  • Question 8
    1 / -0
    Ram, Karan and Rohan invested capital in the ratio of 2:3:42 : 3 : 4 for time period of 6:4:36 : 4 : 3 . Find the ratio of profit distributed?
    Solution
    Profit depends on total amount invested.
    amount invested by Ram = 2×6=12k2\times6 = 12k
    amount invested by Karan = 3×4=12k3\times 4 = 12k
    amount invested by Rohan = 4×3=12k4\times 3 = 12k

    As amount total invested is same in all three cases hence profit distributed will be same and is 1:1:11 : 1 : 1
  • Question 9
    1 / -0
    Which of the following is the most beneficial customer? 
    Solution
    More the discount more it is beneficial Let xx be the cost price of article.
    a) 22 successive discount 20100×[20100x][x25]\rightarrow \dfrac{20}{100}\times \left[\dfrac{20}{100}x\right]\rightarrow \left[\dfrac{x}{25}\right]
    b) 40%40\% at a time discount 40100x[2x5][10x25]\rightarrow \dfrac{40}{100}x\rightarrow \left[\dfrac{2x}{5}\right]\rightarrow \left[\dfrac{10x}{25}\right]
    bdiscount>adiscount\therefore b \,discount >a\,discount

  • Question 10
    1 / -0
    The owner of a toy shop charges his customer 3333% more then the cost price. If the customer paid Rs. 49214921 for a toy, then what was the cost price of the toy?
    Solution
    Let cost price of the toy =x=x 

    Owner will change =x+33100×x=x+ \dfrac{33}{100} \times x
    =494=494

    4921=133100x4921=\dfrac{133}{100}x

    x=4921×100133x=\dfrac{4921 \times 100}{133}

    x=3700 Rsx=3700\ Rs
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