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Comparing Quantities Test - 59

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Comparing Quantities Test - 59
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  • Question 1
    1 / -0
    A man bought goods worth $$Rs.6000$$ and sold half of them at a gain of $$10$$%. At what gain percent must he sell the remainder so as to get a gain of $$25$$% on the whole ?
    Solution
    Let the gain percent be $$x\%$$.

    According to the question,
    $$(110\%\ of\ 3000)+(100+x)\%\ of\ 3000=125\%\ of\ 6000$$
    $$(110\times 30)+(100+x)\times 30=125\times 60$$
    $$3300+3000+30x=7500$$
    $$30x=1200$$
    $$x=40\%$$

    Hence, this is the answer.
  • Question 2
    1 / -0
    Alfred buys an old scooter for $$Rs. 4700$$ and spends $$Rs. 800$$ on its repairs. If he sells the scooter for $$Rs. 5800$$, his gain percent is :
    Solution
    Given,

    C.P. $$=Rs( 4700 + 800) = Rs. 5500$$

    S.P. $$= Rs. 5800$$

    Gain $$= Rs(5800 - 5500 )= Rs.300$$

    $$Gain\% = \dfrac{Gain}{CP}\times 100\%$$

                  $$=\dfrac{300}{5500}\times 100\%$$

                  $$=5\dfrac {5}{11}\%$$

    Hence, the gain percent is  $$5\dfrac {5}{11}\%$$
  • Question 3
    1 / -0
    Rani bought a piece of cloth for $$Rs.950$$ and spend $$Rs.300$$ on designing it. At what price should she sell it to make $$30$$% profit?
    Solution
    Total price of cloth $$= 950 + 300$$

    $$= Rs. 1250$$

    Let she sell in $$Rs. x$$

    $$Profit = \dfrac {x - 1250}{1250} \times 100 = 30$$

    $$10x = 13\times 1250$$

    $$x = 1625$$.
  • Question 4
    1 / -0
    Three hundred oranges were bought at Rs.40 per dozen and sold at a profit of Rs.25. The selling price of the oranges per dozen is           
    Solution
    Let the selling price of the oranges per dozen $$= x$$

    profit for selling one dozen oranges $$= S.P - C.P=(x - 40)$$

    $$300$$ oranges $$= 25$$ dozen orange 

    profit for $$25$$ dozen $$= 25 (x - 40)$$

    $$25 = 25(x - 40)$$

    $$1 = x - 40$$

    $$x = 41$$
  • Question 5
    1 / -0
    The owner of an electronics shop charges his customer $$22$$% more then the cost price. If a customer paid $$Rs.10980$$ for a DVD player then what was the cost price of a DVD player?
    Solution
    Let the cost price of DVD player$$=x$$

    owner will take$$=x+\dfrac{22}{100}\times x$$        from the customer,
    According to the question;
    $$\left(x+\dfrac{22}{100}x\right)=10980$$

    $$\dfrac{122}{100}x=10980$$

    $$x=\dfrac{10980\times 100}{122}$$

    $$x=9,000 = $$ Cost price of DVD player
  • Question 6
    1 / -0
    If a mobile costs Rs. $$2786$$, then $$257$$ mobiles costs?
    Solution
    The cost of $$1$$ mobile phone is $$Rs. 2786$$
    $$\Rightarrow$$ The cost of $$257$$ mobile phone are $$Rs \left( 257\times 2786\right)$$
                                                               $$=Rs. 7,16,002$$
    Hence, the answer is $$Rs. 7,16,002.$$

  • Question 7
    1 / -0
    A man gain $$20\%$$ by selling an article for a certain price. If he sells it at double the price the percentage of profit will be 
    Solution

  • Question 8
    1 / -0
    Rice costing rs $$480$$ is needed for $$8$$ member for $$20$$ days. What is the cost of the rice required for $$12$$ members for $$15$$ days
    Solution

    Rice cost for $$8$$ members  for $$20$$ days= $$480$$rs

    $$8$$ members for $$1$$ day = $$480/20=24$$

    $$1$$ member for $$1$$ day =$$24/8=3$$

     $$12$$ members for $$1$$ day =$$12 \times 3=36$$

    $$12$$ members for $$15$$ days =$$36 \times 15=540$$

    Cost of rice required for $$12$$ members for $$15$$ days = Rs $$540$$
  • Question 9
    1 / -0
    A shopkeeper sells 20 article for Rs. 6000 and earns profit equal to the selling price of 5 articles. Find the cost price of each articles?
    Solution
    Given that,
    A shopkeeper sells $$20$$ articles for $$Rs.\ 6000$$.
    He earns of profit equal to the selling price of $$5$$ articles.

    To find out,
    The cost price of each article.

    Selling price of $$20$$ articles $$=Rs.\ 6000$$

    Hence, the selling price of one article $$=\dfrac{6000}{20}$$

    $$=Rs.\ 300$$

    Hence, profit $$=$$ selling price of $$5$$ articles $$=5\times 300$$

    $$=Rs.\ 1500$$

    We know that, $$C.P.=S.P.-\ profit$$

    Hence, the cost price of $$20$$ articles $$=Rs.\ 6000-Rs.\ 1500$$

    $$=Rs.\ 4500$$

    So, the cost price of one article $$=\dfrac{4500}{20}$$

    $$=Rs.\ 225$$

    Hence, the cost price of each article is $$Rs.\ 225$$.
  • Question 10
    1 / -0
    $$10$$ cylindrical pillars of building have to be painted.If the diameter of each pillar is $$50$$m and the height is $$4$$m.Find the cost of painting at the rate of Rs.$$7$$ per square metre.
    Solution
    Diameter of the pillar$$=50$$m
    Radius$$=25$$m
    Height$$=4$$m
    $$\therefore$$ Curved surface area of a pillar$$=2\pi rh=2\times\dfrac{22}{7}\times 25\times 4$$ 
    Curved surface area of $$10$$ pillars$$=2\times\dfrac{22}{7}\times 25\times 4\times 10$$ 
    Cost of painting$$=$$Rs.$$7$$per sq.m
    $$\therefore$$ Total cost of painting $$10$$ pillars$$=2\times\dfrac{22}{7}\times 25\times 4\times 10\times 7$$
    $$=$$Rs.$$44,000$$

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