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Rational Numbers Test - 13

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Rational Numbers Test - 13
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  • Question 1
    1 / -0
    Which are three rational numbers between $$-2$$ and $$-1$$?
    Solution
    Mean $$= \dfrac {(-2) + (-1)}{2} = \dfrac {-1 -2}{2} = \dfrac {-3}{2}$$.
    $$\frac{(-2)+\dfrac{-3}{2}}{2}$$ =$$\dfrac {-7}{4}$$
    $$\frac{(-1)+\dfrac{-3}{2}}{2}$$ =$$\dfrac {-5}{4}$$
    Mean of numbers  lies between the two numbers.
    So, answer is option $$B.$$
  • Question 2
    1 / -0
    Out of the following numbers, which can be represented on a number line?
    $$0, \dfrac56, 1, \dfrac24$$
    Solution
    Given numbers are $$0,\dfrac{5}{6} ,1,\dfrac{2}{4}$$
    $$0,1$$ are integers and $$\dfrac{5}{6}, \dfrac{2}{4}$$ are rational numbers.
    As, rationals and integers are subset of reals.
    Thus, all the above numbers are real.
    Hence, we can represent all above numbers on a number line.
  • Question 3
    1 / -0
    While representing $$\dfrac23$$ on a number line, between which two integers does the point lie?
    Solution
    $$\dfrac{2}{3}=0.67$$
    It is clear that 0.67 lies between 0 and 1
    So correct answer will be option B
  • Question 4
    1 / -0
    The rational number between the pair of number $$\dfrac{1}{2}$$ and $$\sqrt 1$$ is:
    Solution
    The rational number between $$\dfrac12$$ and $$\sqrt1$$ :
    Since, $$\sqrt1=1$$
    So. the rational number between $$\dfrac12$$ and $$1=\dfrac12\times \left(\dfrac12+1\right)$$
    $$=\dfrac12 \times \dfrac32$$
    $$=\cfrac34$$
    So, $$B$$ is the correct option.
  • Question 5
    1 / -0
    The value of X such that $$-\displaystyle\frac{3}{8}$$ and $$\displaystyle\frac{X}{-24}$$ are equivalent rational numbers is __________.
    Solution
    $$-\dfrac{3}{8}=\dfrac{X}{-24}$$
    $$X=\dfrac{-3\times-24}{8}$$
    $$X=9$$
    Hence the correct answer is option D.
  • Question 6
    1 / -0
    For any two rational numbers x and y which of the following are correct, if x is positive and y is negative?
    $$(1)$$ x $$<$$ y
    $$(2)$$ x $$=$$ y
    $$(3)$$ x $$>$$ y.
    Solution
    If x is positive and y is negative, then the value of x will always be greater than value of y
    $$\therefore$$ $$x>y$$
    Hence the correct answer is option C.
  • Question 7
    1 / -0
    State which of the following statements is/are true?
    I. Numerator and denominator of a positive rational number need not to have like signs.
    II. Numerator and denominator of a negative rational number should have like signs.
    Solution
    If both the numerator and denominator has same sign, then the fraction is a positive rational number.
    If the numerator and denominator have different signs, then the fraction is a negative rational number.

  • Question 8
    1 / -0
    A rational number lie between $$\displaystyle\frac{1}{4}$$ and $$\displaystyle\frac{1}{3}$$ is _________.
    Solution
    So, a rational number between $$\dfrac {1}{4} $$ and $$ \dfrac {1}{3}$$
    $$ = \dfrac {\dfrac {1}{4} + \dfrac {1}{3}}{2} = \dfrac {7}{24} $$

    Now, another rational number between $$ \dfrac {1}{4} $$ and $$ \dfrac {7}{24} $$
    $$= \dfrac {\dfrac {1}{4} + \dfrac {7}{24}}{2} = \dfrac {13}{48} $$ 
    Now, another rational number between $$ \dfrac {1}{3} $$ and $$ \dfrac {7}{24} $$
    $$= \dfrac {\dfrac {1}{3} + \dfrac {7}{24}}{2} = \dfrac {15}{48} $$ 

    Hence, required two rational numbers between $$\dfrac {1}{4} $$ and $$ \dfrac {1}{3} $$ are $$\dfrac {7}{24} ,\dfrac {13}{48}, \dfrac {15}{48}$$
  • Question 9
    1 / -0
    Which of the following rational numbers is positive?
    Solution
    A rational number is positive only when both its numerator and denominator are positive.
    We can see that only $$\dfrac{6}{5}$$ has positive numerator and denominator. Rest all the given options have either negative numerator or negative denominator.
    Therefore, only $$\dfrac{6}{5}$$ is a positive rational number.
    Hence, option C is correct.
  • Question 10
    1 / -0
    Where does a rational number $$\displaystyle\frac{-2}{3}$$ lies on the number line?
    Solution
    $$\dfrac{-2}{3}=-0.667$$
    $$-0.667<0$$
    Hence it will lie to the left side of $$0$$ on the number line.
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