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Rational Numbers Test - 4

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Rational Numbers Test - 4
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  • Question 1
    1 / -0

    The rational number 0 is the additive identity for rational numbers

    Solution

    Zero is called the identity for addition on rational numbers, integers and whole numbers. Since the addition of zero doesn’t affect the value of above given numbers.

    Eg: a+0=0+a=a.

     

  • Question 2
    1 / -0

    Which of the following lies between 25/4  and 22/3?

    Solution

    Rational numbers can be compared by making their denominators equal.
    We have the following fractions - 223,254,152,172,132 and the integer 8 which can be written as 81
    LCM of 1, 2, 3 and 4, i.e., the denominators of the above fractions, is 12.
    Converting all the fractions above into fractions with a common denominator, we get:
    223=22×43×4=8812
    254=25×34×3=7512
    132=13×62×6=7812
    152=15×62×6=9012
    172=17×62×6=10212
    8=81=8×121×12=9612

    Arranging these fractions in an ascending order, we get
    7512,7812,8812,9012,9612,10212

    Thus, the number between 223 and 254 is 7812, i.e. 132

     

  • Question 3
    1 / -0

    The average of the two middle rational numbers, if 4/7,1/3,2/3,5/9are arranged in ascending order is ____. 

    Solution

    LCM of 7, 3, 3, 9=63∴
    4/7=4/7×9/9=36/63,1/3=1/3×21/21=21/63,
    2/3=2/3×21/21=42/63,5/9=5/9×7/7=35/63So, ascending 
    order is 21/63,35/63,36/63,42/63i.e., 1/3<5/9<4/7<2/3Now, the
     average of 5/9 and 4/7 is 1/2 [ 5/9 +4/7 ]=1/2[35+36/63]=71/126

     

  • Question 4
    1 / -0

    Division of whole numbers follows the commutative law.

    Solution

    An operation is commutative if changing the order of operands does not change the result.

    Division of whole numbers is not commutative. a/b ≠ b/a;

    For example: a = 2, b = 3; 2/3 ≠ 3/2

     

  • Question 5
    1 / -0

    Which of the following options are equivalent rational numbers?

    Solution

    1/4 can be written as 1×4/4×4=4×(−1)/16×(−1)=−4/−16∴1/4and 
    −4/−16 are equivalent rational numbers. 

     

  • Question 6
    1 / -0

    A box is to be filled with mangoes, each; weighing 1/10kg. The weight of the box; should not exceed 3/5kg. Find the maximum number of mangoes that can be put inside the box.

    Solution

    Weight of each mango =1/10kg Wight of box =3/5kgNumber of mangoes =3/5÷1/10=3/5×10=6

     

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