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Rational Numbers Test - 22

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Rational Numbers Test - 22
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  • Question 1
    1 / -0
    ............ is the additive inverse of $$\dfrac {-3}{11}.$$
    Solution
    In mathematics, the additive inverse of a number is the number that, when added to a, yields zero. 

    This number is also known as the opposite (number), sign change, and negation. 

    For a real number, it reverses its sign: the opposite to a positive number is negative, and the opposite to a negative number is positive.

    The given rational number is $$\dfrac {-3}{11}$$ and its negative is $$-\left (\dfrac {-3}{11}\right ) = \dfrac {3}{11}$$. Thus, the additive inverse of $$\dfrac {-3}{11}$$ is $$\dfrac {3}{11}$$.
  • Question 2
    1 / -0
    The additive inverse of $$\dfrac {2}{7}$$ is ..........
    Solution
    The additive inverse of a number $$a$$ is the number that, when added to $$a$$, yields zero.  

    If $$a$$ is an integer, then its negative $$(-a)$$ is called the additive inverse of $$a$$.

    The given rational number is $$\dfrac {2}{7}$$ and its negative is $$\dfrac {-2}{7}$$. 

    Thus, the additive inverse of $$\dfrac {2}{7}$$ is $$\dfrac {-2}{7}$$.
  • Question 3
    1 / -0
    There are ....... rational number which when multiplied by $$0$$, gives product as $$1.$$
    Solution
    There are no rational numbers which when multiplied by $$0$$ gives product as $$1$$ because the product of $$0$$ and any number is always $$0.$$
  • Question 4
    1 / -0
    $$1$$ is the multiplicative identity for ........
    Solution

    $${\textbf{Step  - 1: Defining Multiplicative identity}}$$

                      $${\text{Multiplicative identity is a number which when multiplied by another number gives}}$$

                      $${\text{the another number again as result}}{\text{.}}$$

                      $${\text{For example, if x }} \times {\text{ y  =  x then y is multiplicative identity of x}}$$

    $${\textbf{Step  - 2: Identifying multiplicative identity}}$$

                      $${\text{We know that, any number multiplied by 1 gives the number itself}}{\text{.}}$$

                      $$ \Rightarrow {\text{ 1 is the multiplicative identity for any real number}}$$

    $${\textbf{Hence correct option is (D) all of the above}}$$

  • Question 5
    1 / -0
    $$\dfrac {3x}{y}\times 1 =  ..........$$ is stated by multiplicative identity property. 
    Solution
    The multiplicative identity property states that when we multiply a number by $$1,$$ then the product is the number itself.
    So, $$\dfrac {3x}{y} \times 1 = \dfrac {3x}{y}$$.
  • Question 6
    1 / -0
    Find using additive inverse property, what should be added to $$\dfrac {-1}{3}$$, so that the sum is zero ?
    Solution
    We know that the sum of a rational number and its additive inverse is zero.

    Since the given rational number is $$\dfrac {-1}{3}$$, its negative is $$-\left (\dfrac {-1}{3}\right ) = \dfrac {1}{3}$$

    Now, $$\dfrac {-1}{3} + \dfrac {1}{3} = 0$$. Hence, $$\dfrac {1}{3}$$ should be added to $$\dfrac {-1}{3}$$ to get the sum as $$0$$.
  • Question 7
    1 / -0
    The product of ........... and any rational number is the rational number itself.
    Solution
    The product of $$1$$ and any rational number is the rational number itself because $$1$$ is the multiplicative identity for rational numbers.

    Ex: $$\dfrac 3 2$$ when multiplied by $$1$$ gives $$\dfrac 3 2$$ itself, which is a rational number.
  • Question 8
    1 / -0
    Which of the following number lines, represents rational numbers?
  • Question 9
    1 / -0
    Which of the following rational number does not have a reciprocal?
    Solution
    If we try to find the reciprocal of 0 then, we get the result which is not defined.
    As, $$\dfrac{1}{0}=$$ Not a number
    So, we can say that $$0$$ does not have a reciprocal.


  • Question 10
    1 / -0
    There exists ....... number of rational numbers between $$\dfrac {2}{5}$$ and $$\dfrac {4}{5}.$$
    Solution
    There exists infinite number of rational numbers between any two rational numbers. i.e. in this case between $$\dfrac {2}{5}$$ and $$\dfrac {4}{5}$$.
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