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Comparing Quantities Test - 17

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Comparing Quantities Test - 17
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  • Question 1
    1 / -0
    The list price of a parker pen is Rs 160 and a customer buys it for Rs 122.40 after two successive discounts. If first is 10% then the second is
    Solution
    Total discount $$= Rs 160 -Rs 122.40 = Rs 37.60$$
    1st discount $$= 10\% of Rs 160 = Rs 16$$.
    2nd discount $$= Rs 37.60-Rs 16 = Rs 21.60$$
    Balance after firsr discount $$= Rs 160-Rs 16 = Rs 144$$.
    If 2nd discount is $$x\%$$, then $$x\% of Rs 144 =Rs 21.60$$, so $$x =15$$.
  • Question 2
    1 / -0
    When the price of eggs is reduced by 20% it enables a man to buy 20 more eggs for Rs 40. Then the reduced price per egg is:
    Solution
    Let's say Price per egg $$=x$$
    Number of eggs  bought for $$Rs40= $$ $$\dfrac{40}{x}$$
    Reduced price of egg $$= x-20\%$$ of $$x$$
     $$\Rightarrow x-0.2x=0.8x$$ 
    Number of eggs that can be bought=$$\dfrac{40}{0.8x}$$
    As per question,
    $$\Rightarrow \dfrac { 40 }{ 0.8x } -\dfrac { 40 }{ x } =20$$

    $$\Rightarrow \dfrac { 40-32 }{ 0.8x } =20$$

    $$\Rightarrow \dfrac { 8 }{ 0.8x } =20$$

     $$\Rightarrow 16x=8$$
     $$\Rightarrow x=2$$
    Reduced price $$= 2\times \dfrac { 20 }{ 100 } =0.40\ paise$$
    Hence, the reduced price per egg will be 40 paise as 20% of Rs 2 is 40paise.       
  • Question 3
    1 / -0
    Ranga buys a car for Rs 1,00,000 and spends Rs 20,000 on repairs. He rents it and earns Rs 4,000 per month. After 8 months, he sells the car for Rs 1,00,000. His total earning in rupees is
    Solution
    Total investment $$= 1,00,000 + 20,000 = 1,20,000$$
    His earning in 8 months $$= 4,000 \times 8 = 32,000$$
    Total earnings $$= 1,00,000 + 32,000 -1,20,000 = 1,32,000 -1,20,000 =Rs 12,000$$
  • Question 4
    1 / -0
    A trader marked the price of his commodity so as to include a profit of 25%. He allowed a discount of 16% on the MP. His actual profit was
    Solution
    Let the $$\text {CP}$$ of the commodity is $$Rs.\ 100.$$

    Therefore, expected $$\text {MP}$$ of the commodity is $$Rs.\ 125$$.

    According to the question,
    Discount$$=\dfrac{125\times 16}{100}=Rs.\ 20$$

    Therefore,
    $$SP=125-20=Rs.\ 105$$

    Therefore,
    Actual Profit $$=\dfrac{(105-100)}{100}\times 100=5\%$$

    Therefore, net profit is $$5\%$$.
  • Question 5
    1 / -0
    Which tax is collected by Panchayat?
    Solution
    Tax on Local Affairs is collected by Panchayat. 
    All other taxes are collected by Central Government.
  • Question 6
    1 / -0
    Which of the following is a source of income of the Gram Panchayats ?
    Solution
    Levy Duties constitute to the source of income of the Gram Panchayats. 
    All other sources constitute to the income of Central Government.
  • Question 7
    1 / -0
    A and B invest Rs 200 and Rs 300 respectively in a business for a period for three years and two years respectively. Then the profit will be divided into the ratio of
    Solution
    $$Ratio\quad in\quad which\quad they\quad should\quad share\quad their\quad profits=Raio\quad of\quad investments\times \quad Time\quad period$$
    $$=\frac { 200\times 3 }{ 300\times 2 } =\frac { 600 }{ 600 } =1:1$$
  • Question 8
    1 / -0
    Jayant sold two books at Rs 14 each. On one he gains 20% and on the other loses 20%. Then he made
    Solution
    on the first article Jayant gains 20%
    so if CP is 100, selling price will be 120 and profit will be Rs20
    when selling price is 120 profit is 20
    when selling price is 14 profit is $$=\frac { 20 }{ 120 } \times 14=2.33$$
    cost price =selling price-profit
                      =14-2.33
                       =Rs11.67
    on second article he losses 20%
    so if CP is 100, selling price will be 80 and Loss will be Rs20
    when selling price is 80 loss is 20
    when selling price is 14 loss is $$=\frac { 20 }{ 80 } \times 14=3.5$$
    cost price is =selling price+loss
                          =14+3.5
                            =17.5
    total selling price=14+14=Rs28
    total cost price=17.5+11.67=Rs29.17
    net loss=29.17-28=Rs1.17
    loss percantage=$$=\frac { 1.17 }{ 29.17 } \times 100=4$$
    he makes a loss of 4%
  • Question 9
    1 / -0
    A shopkeeper buys paper at Rs 50 per ream. To gain 20%, the selling price per quire will be (take 1 ream = 20 quires)
    Solution
    Shopkeeper buys paper at Rs 50 per ream
    1 ream=20 quires(given)
    20 quires he buys at Rs50
    1 quire he buys at=$$Rs\frac { 50 }{ 20 } $$
    To gain 20 percant, selling price per quire will be
    $$Rs\left( \frac { 50 }{ 20 } +\frac { 20 }{ 100 } \times \frac { 50 }{ 20 }  \right) $$
    $$\left( 2.5+0.5 \right) =Rs3$$

  • Question 10
    1 / -0
    If the cost of a pen is $$Rs.\ 12.60$$ and the gain was $$10\%$$ of the marked price, then the marked price of the pen was
    Solution
    Let the marked price be $$Rs.\ 100.$$

    It is given that $$10\%$$ gain is made on the marked price.
    So,
    $$Gain=100\times \dfrac { 10 }{ 100 } $$
               $$=Rs.\ 10$$

    Cost price will be $$100-10=Rs.\ 90.$$

    When $$Rs.\ 90$$ is the cost price marked price is $$Rs.\ 100.$$
    So, when $$Rs.\ 12.60$$ is the cost price marked price will be $$\dfrac { 100 }{ 90 } \times 12.60=Rs.\ 14.$$

    Hence, option $$B$$ is correct.
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