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Comparing Quantities Test - 19

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Comparing Quantities Test - 19
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Weekly Quiz Competition
  • Question 1
    1 / -0
    A share is said to be ______, if its market value is less than its face value.
    Solution
    A share is said to be at discount, if its market value is less than its face value.
  • Question 2
    1 / -0
    The cost price of $$20$$ articles is the same as the selling price of x articles. If the profit is $$25$$%, then the value of is:
    Solution
    Let C.P. of each article be $$Re. 1$$ C.P. of x articles $$= Rs. x$$.
    S.P. of x articles $$= Rs. 20$$.
    $$Profit = Rs. (20 - x)$$.
    $$\therefore \left (\dfrac {20 - x}{x}\times 100 = 25\right )$$
    $$\Rightarrow 2000 - 100x = 25x$$
    $$125x = 2000$$
    $$\Rightarrow x = 16$$
  • Question 3
    1 / -0
    Which option is an example of interest on interest?
    Solution
    Compound interest is an example of interest on interest.
  • Question 4
    1 / -0
    A shopkeeper expects a gain of $$22.5\%$$ on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
    Solution
    Given that,
    $$S.P.=Rs.\ 392$$ and $$\text{gain}\%=22.5\%$$
    To find out: profit
    We know that, $$C.P.=\dfrac{S.P.\times 100}{100+\text{gain}\%}$$

    $$\therefore \ C.P. = Rs. \left (\dfrac {100}{122.5}\times 392\right ) \\$$

    $$= Rs. \left (\dfrac {1000}{1225}\times 392\right ) \\$$

    $$= Rs. 320\\$$

    We also know that, $$\text{profit}=S.P.-\ C.P.$$

    $$\therefore \ \text{Profit} = Rs. (392 - 320) \\$$
    $$= Rs. 72$$.

    Hence, the profit of the shopkeeper on the sale of $$Rs.\ 392$$ is $$Rs.\ 72$$.
  • Question 5
    1 / -0
    _________ is interest calculated on the initial principal and also on the accumulated interest of previous periods of a deposit or loan.
    Solution
    Compound interest is the interest calculated on the initial principal and also on the accumulated interest of previous periods of a deposit or loan.

    So $$Op.B$$
  • Question 6
    1 / -0
    Identify in which type of interest rate is applied to the original principal and any accumulated interest?
    Solution
    When the interest rate is applied to the original principal and any accumulated interest, this is called compound interest.
  • Question 7
    1 / -0
    __________ is calculated on both the amount borrowed and any previous interest.
    Solution
    Compound interest is calculated on both the amount borrowed and any previous interest.
  • Question 8
    1 / -0
    The percentage profit earned by selling an article for Rs. $$1920$$ is equal to the percentage loss incurred by selling the same article for Rs. $$1280$$. At what price should the article be sold to make $$25$$% profit?
    Solution
    Let C.P. be $$Rs. x$$.
    Then, $$\dfrac {1920 - x}{x} \times 100 = \dfrac {x - 1280}{x}\times 100$$
    $$\Rightarrow 1920 - x = x - 1280$$
    $$\Rightarrow 2x = 3200$$
    $$\Rightarrow x = 1600$$
    $$\therefore$$ Required $$S.P. = 125$$% of $$Rs. 1600 = Rs. \left (\dfrac {125}{100}\times 1600\right ) = Rs 2000$$.
  • Question 9
    1 / -0
    Which tax is paid to government for the sales of certain goods and services?
    Solution
    Sales tax is paid to government for the sales of certain goods and services.
  • Question 10
    1 / -0
    In what time will Rs, $$15,000$$ yield Rs. $$4965$$ as compound interest at $$10$$% per year compounded annually?
    Solution
    Interest for the first year 
    $$=\cfrac{1500\times 10\times 1}{100}$$
    $$=$$ Rs $$1500$$
    Amount after the first year $$=$$ Rs $$15000+1500$$
    $$=$$ Rs $$ 16500$$ 
    Interest for the second year
    $$=$$ $$\cfrac{16500\times 10\times 1}{100}$$
    $$=$$ Rs $$1650$$
    Amount after the third year 
    $$=$$ $$\cfrac{18150\times 10\times 1}{100}$$
    $$=$$ Rs $$1815$$
    Final amount $$= $$ Rs $$18150+1815$$
    $$=$$ Rs $$19965$$
    Compound interest $$=$$ Rs $$19965-15000$$
     $$=$$ Rs $$4965$$
    Required time $$= 3$$ years
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