Self Studies

Comparing Quantities Test - 34

Result Self Studies

Comparing Quantities Test - 34
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    Mukesh purchased $$40$$ kg of wheat at Rs. $$12. 50$$ per kg and $$25$$ kg of wheat at Rs. $$15.10$$ per kg. He mixed the two qualities of wheat for selling. At what rate(in Rs.) should it be sold to gain $$10\%$$?
    Solution
    C.P. of the wheat $$= 40 \times$$ Rs. $$12.50 + 25 \times $$ Rs. $$15.10 = Rs.877.5$$, 

    Gain $$= 10\%$$

    $$\displaystyle \therefore$$ S.P. of the wheat $$\displaystyle =$$  $$Rs.\dfrac{877.5\times 110}{100}$$
                                  $$= Rs. $$965.25$$

    $$\displaystyle \therefore$$ S.P. per kg of wheat $$\displaystyle =$$ Rs. $$\dfrac{965.25}{65}=$$  $$Rs.14.85$$
  • Question 2
    1 / -0
    Jatin bought a refrigerator with $$20\%$$ discount on the labelled price. If he woud have bought it with $$25\%$$ discount, he could have saved Rs. $$500$$. At what price did he buy the refrigerator?
    Solution
    $$\Rightarrow$$  Let actual price of refrigerator is $$Rs.x$$
    $$\Rightarrow$$  The cost of refrigerator to jatin after 20% discount $$=\dfrac{80}{100}\times x=\dfrac{4x}{5}$$
    $$\Rightarrow$$  Cost of refrigerator to jatin after 25% discount $$=\dfrac{75}{100}\times x=\dfrac{3x}{4}$$
    $$\Rightarrow$$  Then according to the question,
    $$\Rightarrow$$  $$\dfrac{4x}{5}-\dfrac{3x}{4}=500$$

    $$\Rightarrow$$  $$\dfrac{16x-15x}{20}=500$$

    $$\therefore$$  $$x=20\times 500=10000$$
  • Question 3
    1 / -0
    What is the compound interest on an amount of Rs. $$4800$$ at the rate of $$6$$ percent p.a. at the end of $$2$$ years?
    Solution
    Given, $$P = $$ $$Rs.$$ $$4800, r = 6\%$$ $$p.a.$$, $$n = 2$$

    $$\displaystyle \therefore C.I.=A-P=P\left ( 1+\frac{r}{100} \right )^{n}-P$$

    $$\displaystyle =4800\left ( 1+\frac{6}{100} \right )^{2}-4800$$

    $$\displaystyle =4800\times \dfrac{106\times 106}{100\times 100}-4800$$

    $$= 5393.28 - 4800 =$$ $$Rs.$$ $$593.28$$
  • Question 4
    1 / -0
    If a company sells a car with a marked price of Rs. $$2,72,000$$ and gives a discount of $$4\%$$ on Rs. $$2,00,000$$ and $$2.5\%$$ on the remaining amount of Rs. $$72,000$$, then the actual price charged by the company for the car is
    Solution

    M.P. $$=$$ Rs. $$2,72,000$$.
    Discount $$=$$ Rs. $$[(4\%$$ of $$2,00,000)+ (2.5\%$$ of $$72,000)]$$

    $$=\left [\left (\dfrac{4}{100}\times 200000)+(\dfrac{2.5}{100}\times 72000\right)\right]$$
    $$= $$ Rs. $$(8,000 + 1,800)$$
    $$=$$ Rs. $$9,800. $$
    Therefor, actual price $$=$$ Rs. $$(2,72,000 - 9,800)$$
    $$=$$ Rs. $$2,62,200.$$

  • Question 5
    1 / -0
    Profit earned by selling an article for Rs. $$1,060$$ is $$20$$% more than the loss incurred by selling the article for Rs. $$950$$. At what price should the article be sold to earn $$20$$% profit?
    Solution

    Let C.P. be Rs $$x$$ 

    Then $$ (1060 - x ) = \dfrac{120}{100} \times (x-950)$$
    $$\Rightarrow 10600 - 10x = 120x- 120 \times 950$$
    $$\Rightarrow 220x = 220000$$
    $$ \Rightarrow x = 1000$$
    $$\therefore$$ Desired  S.P. $$=$$ Rs. $$\left (\dfrac{120}{100} \times 1000\right) =$$ Rs. $$1200$$

  • Question 6
    1 / -0
    A shopkeeper allows a discount of 10% on the marked price. How much above the cost price must he mark his goods to gain 8%?
    Solution
    let Marked price of an article be $$x$$

    Discount on article $$=x-10$$%of$$ x$$
     
                                      $$=x-\frac{10}{100}x$$

                                      $$=0.9x$$


    Therefore, selling price of the article$$=0.9x$$

    Now, Gain % $$=\frac{sp-cp}{cp}$$

    Put the value of  gain % and $$sp$$ in the above equation and calculate $$cp$$.

    $$\frac{8}{100}=\frac{0.9x-cp}{cp}$$

    $$8cp=90x-100cp$$

    $$108cp=90x$$

    $$cp=\frac{90x}{108}$$

    $$cp=\frac{5x}{6}$$

    Therefore, cost price $$cp$$ marked above marked price($$mp$$)  $$=\frac{mp-cp}{cp}\times100$$

    Put the valus of $$cp$$ and $$mp$$ in the above equation
    $$=\frac{x-\frac{5x}{6}}{\frac{5x}{6}}\times100$$

    $$=\frac{\frac{x}{6}}{\frac{5x}{6}}$$

     $$20$$%
  • Question 7
    1 / -0
    A pair of articles was bought for : Rs.37.40 at a discount of 15%. What must be the marked price of each of the articles?
    Solution
    S.P. of each article = Rs. $$\displaystyle\frac{37.40}{2}$$
    = Rs. 18.70.
    Let M.P. be Rs. x.
    Then, 85% of x = 18.70
    $$\Rightarrow\, x\, =\,  \left ( \displaystyle \frac{18.70\, \times\, 100}{85} \right )\, =\, 22$$
  • Question 8
    1 / -0
    The shopkeeper gives a discount of $$12\%$$ on the pair of shoes marked for Rs. $$1425$$, then S.P is:
    Solution
    Given M.P. $$=$$ Rs. $$1425$$ 
    Discount $$=12\%$$ of Rs. $$1425 =$$ $$\displaystyle\frac{12}{100}\,\times\, 1425$$
    $$=$$ Rs. $$171$$ 
    Selling price of shoes $$=$$ Rs. $$(1425 - 171) = $$ Rs. $$1254$$.
  • Question 9
    1 / -0
    A cycle is sold for Rs. 880 at a loss of 20%. For how much should it be sold to gain 10%?
    Solution
    SP of cycle = Rs. 880
    Loss = 20%
    CP of cycle = $$\displaystyle880\, \times\, \frac{100}{100\, -\, 20}\, =\, Rs. 1100$$
    If gain required is 10 % then
    $$SP\,=\, 1100\, \times\, \displaystyle\frac{100\, +\, 10}{100}\, =\, Rs. 1210$$
  • Question 10
    1 / -0
    The current birth rate per thousand is $$32$$, whereas the corresponding death rate is $$11$$ per thousand. The net growth rate in terms of population increase in per cent is given by, 
    Solution

    Given, birth rate per $$1000$$ is $$32$$ and corresponding death rate is $$11$$ per thousand.
    therefore, net growth on $$1000=(32-11)=21$$
    Hence, net growth on $$100=\dfrac  {21}{1000}\times 100=2.1\%$$
    Therefore, net growth rate in terms of population increase in per cent is $$2.1\%$$.
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Selfstudy
Selfstudy
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now