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Comparing Quantities Test - 58

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Comparing Quantities Test - 58
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  • Question 1
    1 / -0
    The cost price of an article is $$x$$. It is marked up by $$150$$%. It is sold at Rs. $$600$$ after giving $$40$$% discount. What is $$x$$ (in Rs.)?
    Solution
    Given that, the cost price of an article is $$Rs.\ x$$. It is marked up by $$150\%$$ and sold at $$Rs.\ 600$$ after a discount of $$40\%$$.
    To find out: The value of $$x$$.

    $$C.P.=Rs.\ x$$
    Hence, marked price $$(M.P.)=150\% \ of\ x=Rs.\ 1.5x$$
    We know that,
    $$S.P.=\dfrac{100-\%\text{discount}}{100}\times M.P.$$

    $$\therefore \ 600=\dfrac{100-40}{100}\times 1.5x$$

    $$\Rightarrow \ 600=\dfrac{6}{10}\times 1.5x$$

    $$\Rightarrow \ 1.5x=1000$$

    $$\Rightarrow \ x=\dfrac{1000}{1.5}=\dfrac{10000}{15}$$

    $$\therefore \ x=666.66$$

    Hence, the cost price of the article $$(x)$$ is $$Rs.\ 666.66$$.
  • Question 2
    1 / -0
    Mr,A owns a home worth Rs.$$10,000$$. He sells it to Mr.B at a $$10\%$$ profit based on the worth of the house. Mr.B sells the house back to Mr.A at a $$10\%$$ loss. Then:
    Solution
    $$\text{C.P. of B = 110% of Rs. 10000 = Rs. 11000}$$
    $$\text{Loss of B = 10%}$$
    $$\text{S.P. of B = 90% of Rs. 11000 = Rs. 9900}$$
    $$\text{Thus, C.P. of A = Rs. 9900}$$
    $$\text{So, A gets [(10% of Rs. 10000) + (10000 - 9900)] = Rs. 1100}$$
  • Question 3
    1 / -0
    $$5$$% more is gained by selling a watch for $$Rs. 350$$ than by selling it for $$Rs. 340$$. The cost price of the watch is
    Solution
    Let cost price be $$Rs. x$$
    Then $$5$$% of $$x = (350 - 340)$$
    $$5$$% of $$x = 10$$
    $$x = 10\times \dfrac {100}{5} = 200$$
    Hence, cost price is $$Rs. 200$$.
  • Question 4
    1 / -0
    Find the whole quantity if $$5\%$$ of it is $$600$$.
    Solution
    Given $$\dfrac{5}{100}$$ of $$x=600$$

    $$\implies x=\dfrac{600\times 100}{5}= Rs$$ $$12000$$
  • Question 5
    1 / -0
    A house and store were sold for $$\text{Rs. } 12,000$$ each. The house was sold at a loss of $$20\%$$ of the cost and the store at a gain of $$20\%$$ of the cost. The entire transaction resulted in
    Solution
    $$12,000 = H - \dfrac {1}{5}H  \therefore H = 15,000$$
    $$12,000 = S + \dfrac {1}{5}S  \therefore S = 10,000$$
    $$ H + S = 25,000$$.
    Therefore, the sale resulted in a loss of $$Rs. 1000$$.
  • Question 6
    1 / -0
    The cost $$C$$ of sending a parcel post package weighing $$P$$ gms, $$P$$ an integer is $$Rs. 10$$ for the first grams and $$Rs. 3$$ for each additional grams. The formula for the cost is
    Solution
    For $$P - 1$$ gms the charge is $$3$$ rupees per grams. For the first gram the charge is $$10$$ rupees. $$\therefore C = 10 + 3(P - 1)$$; or
    The charge for each gram is $$3$$ rupees with an additional charge of $$7$$ rupees for the first gram. $$\therefore C = 3P + 7 = 3P - 3 + 10 = 10 + 3(P - 1)$$.
  • Question 7
    1 / -0
    A shopkeeper allows a discount of $$10\%$$ on the marked price of an item but charges a sales tax of $$8\%$$ on the discounted price. If the customer pays $$Rs.680.40$$ as the price including the sales tax, then what is the marked price of the item?
    Solution
    Let marked price be $$Rs.x$$
    Price after discount of $$10\%=x-x\times \dfrac{10}{100}=\dfrac{9x}{10}$$

    Price after Tax $$=\dfrac{9x}{10}+\left(\dfrac{9x}{10}\times \dfrac{8}{100} \right)=\dfrac{972x}{1000}$$

    It is given that:

    $$\Rightarrow$$  $$\dfrac{972x}{1000}=680.40$$

    $$\Rightarrow$$  $$x=\dfrac{680400}{972}$$

    $$\therefore$$  $$x=Rs.700.$$

    $$\therefore$$  Marked price of the item is $$Rs.700$$
  • Question 8
    1 / -0
    A wholesaler bought $$120$$ watches for $$\text{Rs }30$$ each. He sold $$50\%$$ of the watches for $$\text{Rs }20$$ each, one-third at $$\text{Rs }40$$ each and the rest for $$\text{Rs }60$$. What was the wholesaler's approximate avenge profit per watch?
    Solution
    C.P. of each watch $$=\text{Rs }30$$ , number of watches $$=120$$
    total C.P. $$=30\times 120=\text{Rs }3600$$
    Wholesaler sold $$50\%$$  ($$60$$ watches) at $$\text{Rs }20$$
    S.P. of these $$60$$ watches $$(S.P_1)=60 \times 20=\text{Rs }1200=$$
    $$\left(\dfrac{1}{3}\right)^{rd}$$ of $$120$$ watches are sold at $$\text{Rs }40$$
    $$S.P_2=40\times 40=\text{Rs }1600$$
    rest $$(120-60-40=20)$$ watches are sold at $$\text{Rs }60$$
    $$S.P_3=20\times 60=\text{Rs }1200$$
    Total S.P. $$=1200+1600+1200=\text{Rs }4000$$
    profit $$=$$ S.P. $$-$$ C.P. $$=4000-3600=\text{Rs }400$$
    Average profit per watch $$=\dfrac{400}{120}=\text{Rs }3.3$$

  • Question 9
    1 / -0

    A trader allows successive discounts of $$15\%$$ and $$10\%$$ on the marked price of an article. If the marked price is $$Rs. 100$$, what would be the selling price?

    Solution
    Marked Price $$= Rs\ 100$$

    Price after $$15\%$$ discount:

    $$15\%$$ Discount $$= 0.15 x 100 = Rs\ 15$$

    Price after discount $$= 100 - 15 = Rs\ 85$$

    Price after $$10\%$$ discount:

    $$10\%$$ Discount $$= 0.10 x 85 = Rs\ 8.50$$

    Price after discount $$= 85 - 8.5 = Rs\ 76.50$$

    Hence, the selling price is $$Rs\ 76.50$$
  • Question 10
    1 / -0
    A TV was bought at a price of Rs. 21,000. After one year the value of the TV was depreciated by 5%. (Depreciation means reduction of value due to use and age of the item). Find the value of the TV after one year.
    Solution
    $$\textbf{Step -1:Calculate the value to be deduced}.$$
                    $$\text{We are given that after one year, the value of the TV is depreciated by}$$ $$5\%.$$
                    $$\text{Value to be deduced =}$$$$5$$$$\text{% of}$$ $$Rs.21,000$$
                                                           $$=Rs.\dfrac{21000\times 5}{100}$$
                                                           $$=Rs.\: 1050$$
    $$\textbf{Step -2:Calculate the value of the TV after one year}.$$
                    $$\text{Value after one year=}$$$$Rs.(21000-1050)$$
                                                         $$=Rs.\: 19,950$$

    $$\textbf{Hence, the correct option is C.}$$
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