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Statistics Test - 17

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Statistics Test - 17
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  • Question 1
    1 / -0
    Consider the data  :  $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2.$$ The frequency of 
    $$2$$ is ..............
    Solution
    In the data series: $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2$$
    $$2$$ occurs $$5$$ times, hence its frequency is $$5$$
  • Question 2
    1 / -0
    The mid-point of a class intervals is called:
    Solution
    Class mark is defined as the mean of the lower limit and upper limit. 
    Hence, the mid point of a class interval is called the class mark.
  • Question 3
    1 / -0
    The formula $$\dfrac{Upper\  class\  limit +  Lower\  class\  limit }{2}$$ is known as
    Solution
    True. Class Mark is given by $$\dfrac{Upper  class  limit +  Lower  class  limit }{2}$$
  • Question 4
    1 / -0
    The number of times a particular item occurs in a class interval is called its:
    Solution
    The number of times a particular item is occurs in a class interval is called its frequency.
    For, example the data set is $$1,2,3,3,5,6,12,14,23,12,22,16,18$$. In the data set the frequency of the class interval $$10-15$$ is $$3$$ i.e., the values in the class interval are $$12,14,12$$
  • Question 5
    1 / -0
    The mean of $$x, y, z$$ is $$y$$, then $$x+z =$$
    Solution
    The question tells us that the mean of $$x, y$$ and $$z$$ is $$y$$. 

    i.e. $$ \dfrac {x+y+z}{3} =y $$

    i.e. $$x+z=3y-y$$

    $$\rightarrow x+z=2y$$
  • Question 6
    1 / -0
    In the class interval $$35-46$$, the lower limit is _____
    Solution
    For the class interval, $$ 35 - 46$$
    Lower limit $$= 35$$
    Upper limit $$= 46$$
  • Question 7
    1 / -0
    The mid-value of $$20-30$$ is _____
    Solution
    Mid value $$= \dfrac{\text{Lower Limit} + \text{Upper limit}}{2}$$
    Mid Value $$= \dfrac{20 + 30}{2}$$
    Mid Value $$= 25$$
  • Question 8
    1 / -0
    A class interval of a data has $$15$$ as the lower limit and $$25$$ as the size then the class mark is :
    Solution
    Given,
    Lower limit $$= 15$$
    Size of class interval $$= 25$$
    Upper limit $$= \text{lower limit }+ \text{ size} = 15 + 25$$ = $$40$$
    Class mark is calculated from mean of lower and upper limit.
     Class mark $$ =\dfrac{ \text{lower limit }+ \text{upper limit }}{2}$$
                          $$= \dfrac{15 + 40}{2}$$ 
                          $$=27.5$$
  • Question 9
    1 / -0
    $$0-10, 10-20, 20-30 ...$$  so on are the classes, the lower boundary of the class $$20-30$$ is _____
    Solution
    Lower boundary means the lower limit of the class interval.
    The lower limit of $$20 - 30$$ is $$20$$.
  • Question 10
    1 / -0
    Which one of the following groups has different class size from others?
    Solution
    Class size $$=$$ Upper limit $$-$$ lower limit

    All other classes have a class size $$= 5$$ except, $$243-249$$ which has a size of $$6$$
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