Statistics Test

Result

Statistics Test - 27

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Weekly Quiz Competition

Question 1
1 / -0

Find the arithmetic mean of numbers from $$1$$ to $$9$$.

A
$$9$$

B
$$5$$

C
$$8$$

D
$$3$$

Solution

The numbers from $$1$$ to $$9$$ are $$1,2,3,4,5,6,7,8,9$$
$$ A.M. =\dfrac{\text{Sum of observations}}{\text{Number of observations}}= \dfrac {1+2+3+4+5+6+7+8+9}{9} = \dfrac {45}{9} = 5 $$
Question 2
1 / -0

Mean of $$9$$ observations was founded to be $$35$$. Later on, it was detected that an observation $$81$$ was misread as $$18$$, then the correct mean of the observations is ____________.

A
$$40$$

B
$$41$$

C
$$42$$

D
$$43$$

Solution

Mean of $$9$$ observations $$= 35$$
Sum of $$9$$ observations $$= 35\times9 = 315$$

Since $$81$$ was misread as $$18$$
New sum $$= 315-18+81= 378$$

The correct mean $$= \dfrac{378}{9} = 42$$
Question 3
1 / -0

Primary data in statistics is the data collected from :

A
Primary sources

B
Secondary sources

C
Both

D
None of the above

Solution

Primary data is data originated for the first time by the researcher through direct efforts and experience so it is collected from primary sources.
Question 4
1 / -0

The given bar graph shows the number of matches played by different teams. Read the bar graph and answer the questions:
How many matches did both India and Bangladesh play?

A
$$34$$

B
$$22$$

C
$$38$$

D
$$40$$

Solution

From the bar graph,
The number of matches played by India $$=26$$.
The number of matches played by Bangladesh $$=8$$.

Therefore, the total number of matches played by both India and Bangladesh $$=26 + 8 = 34$$.

Thus, total number of matches played by both India and Bangladesh $$34$$.

Hence, option $$A$$ is correct.
Question 5
1 / -0

The mean of $$\displaystyle\frac{1}{3},\frac{3}{4},\frac{5}{6},\frac{1}{2}$$ and $$\displaystyle\frac{7}{12}$$ is ____________.

A
$$\displaystyle\frac{2}{5}$$

B
$$\displaystyle\frac{3}{5}$$

C
$$\displaystyle\frac{1}{5}$$

D
None of these

Solution

Given data is $$\dfrac{1}{3},\dfrac{3}{4},\dfrac{5}{6},\dfrac{1}{2},\dfrac{7}{12}$$

Mean $$=$$ Sum of observations $$\div$$ Total number of observations

Sum of observations$$=$$ $$\dfrac{1}{3}+\dfrac{3}{4}+\dfrac{5}{6}+\dfrac{1}{2}+\dfrac{7}{12}$$

Mean $$=$$$$\dfrac{\dfrac{4+9+10+6+7}{12}}{5}$$

$$= \dfrac{3}{5}$$
Question 6
1 / -0

Length of the class $$11-20$$ is ______.

A
$$9$$

B
$$10$$

C
$$11$$

D
$$20$$

Solution

Length of a class is given by $$b-a$$, where $$b$$ and $$a$$ are the upper and lower limits of the class respectively.
$$\therefore$$ length $$=20-11=9$$
Option $$A$$ is correct.
Question 7
1 / -0

What temperature does the given thermometer shows?

A
$$35^{\circ}C$$

B
$$77^{\circ}F$$

C
$$95^{\circ}C$$

D
$$122^{\circ}F$$

Solution

Thermometer shows $$35^o C$$ or $$95^o F$$
Hence the correct answer is option A.
Question 8
1 / -0

In a frequency distribution with classes $$(1-8),(9-16),(17-24).... $$the class interval is

A
8

B
9

C
7

D
3

Solution

Class interval$$=$$(high$$-$$low value $$+1$$)
$$=8-1+1$$
$$=8$$.
Question 9
1 / -0

The mean weight of 9 students is 25 kg. If one more student is joined in the group the mean is unaltered, then the weight of the 10th student is

A
25 kg

B
24 kg

C
26 kg

D
23 kg

Solution

Formula used:
$$Arithmetic\ mean= \dfrac{Sum\ of\ given\ numbers}{Total\ numbers}$$

Apply the above formula, we get the sum of weights of the 9 students = $$25\times 9=225$$ kg
If one more student is joined in the group, then total number of students is 10, and the mean isn 25.
The sum of weights of the 10 students is $$25\times 10=250$$ kg
The weight of the tenth student is $$250-225=25$$ kg
Question 10
1 / -0

The sum of $$15$$ observations is $$434+x.$$ If the mean of the data is $$x,$$ then find $$x.$$

A
$$25$$

B
$$27$$

C
$$31$$

D
$$33$$

Solution

Given, sum of all observations $$=434+x$$
Number of observations$$=15$$

and
$$Mean=x$$

$$\Rightarrow \dfrac{434+x}{15}=x$$

$$\Rightarrow 434+x=15x$$

$$\Rightarrow x-15x=-434$$

$$\Rightarrow -14x=-434$$

$$\Rightarrow x=\dfrac{-434}{-14}$$

$$\Rightarrow x=31$$

Hence, the value of $$x$$ is $$31$$ .

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Re-Attempt Weekly Quiz Competition

Statistics Test - 27

Result

Statistics Test - 27

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Rank

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SHARING IS CARING

Question 1

$$9$$

$$5$$

$$8$$

$$3$$

Solution

Question 2

$$40$$

$$41$$

$$42$$

$$43$$

Solution

Question 3

Primary sources

Secondary sources

Both

None of the above

Solution

Question 4

$$34$$

$$22$$

$$38$$

$$40$$

Solution

Question 5

$$\displaystyle\frac{2}{5}$$

$$\displaystyle\frac{3}{5}$$

$$\displaystyle\frac{1}{5}$$

None of these

Solution

Question 6

$$9$$

$$10$$

$$11$$

$$20$$

Solution

Question 7

$$35^{\circ}C$$

$$77^{\circ}F$$

$$95^{\circ}C$$

$$122^{\circ}F$$

Solution

Question 8

8

9

7

3

Solution

Question 9

25 kg

24 kg

26 kg

23 kg

Solution

Question 10

$$25$$

$$27$$

$$31$$

$$33$$

Solution

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