Statistics Test

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Statistics Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

Observe the adjoining bar graph, showing the number of one-day international matches played by cricket teams of different countries. Choose the correct answer from the given four options:
How many matches did South Africa play?

A
$$16$$

B
$$18$$

C
$$20$$

D
$$24$$

Solution

The given bar graph represents the number of matches played by cricket teams of different country.
We can prepare frequency table from given bar graph as follows:
Country No. of matches
India $$30$$
Pakistan $$24$$
West Indies $$20$$
England $$28$$
South Africa $$18$$
Australia $$32$$
Sri Lanka $$24$$
Clearly, the number of matches played by South Africa is $$18$$.
Hence, option $$B$$ is correct.
Question 2
1 / -0

The mean of first ten odd natural number is

A
5

B
10

C
20

D
19

Solution

Since, first ten odd natural numbers are$$1, 3, 5, 7, 9, 11, 13, 15, 17, 19$$

We know that
$$\text{Mean}=\dfrac{\text{sum of observation}}{\text{number of observation}}$$
$$\therefore$$ Mean $$=\dfrac{(1 + 19 + 3 + 17 + 5 + 15 + 7 + 13 + 9 + 11) }{ 10} = \dfrac{100}{10} = 10$$
Question 3
1 / -0

What is the upper-class limit for the class $$25-35$$?

A
$$25$$

B
$$35$$

C
$$60$$

D
$$30$$

Solution

Since the upper-class limit for the class 25−35 is 35.Hence, the correct alternative answer is (B)
Question 4
1 / -0

Which of the following data is not primary?

A
By visiting a certain class, gathering information about the attendance of students.

B
By an actual visit to homes, to find a number of family members.

C
To get information regarding the plantation of soyabean done by each farmer from the village Talathi.

D
Review the cleanliness status of canals by actually visiting them.
Question 5
1 / -0

Fill in the blank:
The height of a rectangle in a histogram represent _______.

A
class interval

B
midpoint

C
frequency density

D
frequency

Solution

We know, histogram is a graphical representation of data using bars of equal width and no gaps between them. The height of the bars gives the frequency of the particular class interval.

Therefore, the height of a rectangle in a histogram represents the frequency.

Hence, option $$D$$ is correct.
Question 6
1 / -0

The class mark of the class interval 20 - 29 is

A
20

B
29

C
25

D
24.5

Solution

The class mark of the class interval 20 - 29 is $$\dfrac{20+29}{2}=24.5$$
Question 7
1 / -0

The class marks of a continuous distribution are:
$$1.04, 1.14, 1.24, 1.34, 1.44, 1.54$$ and $$1.64$$
Is it correct to say that the last interval will be $$1.55 - 1.73$$? Justify your answer.

A
It is correct.

B
It is not correct. Reason is that difference between two consecutive marks should be equal to the class size.

C
Ambiguous

D
Data insufficient

Solution

Class mark means the mid point of a class interval.
Difference between two consecutive class marks is always equal to the class size.
Now $$1.14-1.04=0.1$$
$$1.24-1.14=0.1$$
$$1.34-1.24=0.1$$ and so on
Class size $$=0.1$$
But in class interval $$(1.55 - 1.73), 1.73-1.55=0.8$$ which is not equal to the class size found previously.
So class interval $$(1.55 - 1.73 )$$ cannot be the correct class interval for the given class marks.
Question 8
1 / -0

The mean marks (out of $$100$$) of boys and girls in an examination are $$70$$ and $$73$$, respectively. If the mean marks of all the students in that examination is $$71$$, find the ratio of the number of boys to the number of girls.

A
$$1:1$$

B
$$2:1$$

C
$$1:2$$

D
$$2:3$$

Solution

Let the total number of boys be $$x$$ and the total number of girls br $$y$$.
Let the sum of the marks of boys be $$a$$ and the sum of the marks of girls be $$b$$.
Mean marks of boys are $$=70$$
Mean marks of girls are $$=73$$
Therefore,
$$\Rightarrow \dfrac{a}{x}=70$$
$$\Rightarrow a=70x$$
and
$$\Rightarrow \dfrac{b}{y}=73$$
$$\Rightarrow b=73y$$
Now, mean marks of all the students is $$71$$
Therfore,
$$\Rightarrow \dfrac{sum\ of\ the\ marks\ of\ all\ the\ students}{x+y}=71$$
$$\Rightarrow sum\ of\ the\ marks\ of\ all\ the\ students=a+b$$
$$\Rightarrow a+b=70x+73y$$
Therefore,
$$\Rightarrow \dfrac{70x+73y}{x+y}=71$$
$$\Rightarrow 70x+73y=71x+71y$$
$$\Rightarrow2y=x$$
$$\Rightarrow \dfrac{x}{y}=\dfrac{2}{1}$$
$$Hence\ the\ ratio\ is\ 2:1$$
Question 9
1 / -0

Prepare a continuous grouped frequency distribution from the following data:

Mid Point
Frequency
$$5$$
$$4$$
$$15$$
$$8$$
$$25$$
$$13$$
$$35$$
$$12$$
$$45$$
$$6$$
Also find the size of class intervals.

A
Class size $$= 16$$

B
Class size $$= 14$$

C
Class size $$= 12$$

D
Class size $$= 10$$

Solution

classes 0-10 10-20 20-30 30-40 40-50
frequency 4 8 13 12 6
Question 10
1 / -0

In the figure, there is a histogram depicting daily wages of workers in a factory. Construct the frequency distribution table and find the total number of workers.

A
$$145$$

B
$$142$$

C
$$148$$

D
$$146$$

Solution

Frequency Distribution table for Daily wages & Number of workers is:

Class Interval Frequency
$$150-200$$ $$50$$
$$200-250$$ $$30$$
$$250-300$$ $$35$$
$$300-350$$ $$20$$
$$350-400$$ $$10$$
Total Workers $$145$$

Hence, the total number of workers is $$145$$.
Thus, option $$A$$ is correct.

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Mid Point	Frequency
$$5$$	$$4$$
$$15$$	$$8$$
$$25$$	$$13$$
$$35$$	$$12$$
$$45$$	$$6$$

Frequency Distribution table for Daily wages & Number of workers is:
Class Interval	Frequency
$$150-200$$	$$50$$
$$200-250$$	$$30$$
$$250-300$$	$$35$$
$$300-350$$	$$20$$
$$350-400$$	$$10$$
Total Workers	$$145$$

classes	0-10	10-20	20-30	30-40	40-50
frequency	4	8	13	12	6

Statistics Test - 28

Result

Statistics Test - 28

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SHARING IS CARING

Question 1

$$16$$

$$18$$

$$20$$

$$24$$

Solution

Question 2

5

10

20

19

Solution

Question 3

$$25$$

$$35$$

$$60$$

$$30$$

Solution

Question 4

By visiting a certain class, gathering information about the attendance of students.

By an actual visit to homes, to find a number of family members.

To get information regarding the plantation of soyabean done by each farmer from the village Talathi.

Review the cleanliness status of canals by actually visiting them.

Question 5

class interval

midpoint

frequency density

frequency

Solution

Question 6

20

29

25

24.5

Solution

Question 7

It is correct.

It is not correct. Reason is that difference between two consecutive marks should be equal to the class size.

Ambiguous

Data insufficient

Solution

Question 8

$$1:1$$

$$2:1$$

$$1:2$$

$$2:3$$

Solution

Question 9

Class size $$= 16$$

Class size $$= 14$$

Class size $$= 12$$

Class size $$= 10$$

Solution

Question 10

$$145$$

$$142$$

$$148$$

$$146$$

Solution

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