Statistics Test

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Statistics Test - 30

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Weekly Quiz Competition

Question 1
1 / -0

The class mark of the class 90-120 is

A
90

B
105

C
115

D
120

Solution

Class mark is the mean of the upper and lower limit of the class interval = $$\frac{90+120}{2}$$ = 105
Question 2
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For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are the:

A
upper limits of the classes

B
lower limits of the classes

C
class marks of the classes

D
upper limits of perceeding classes

Solution

For drawing a frequency polygon of a continuous frequency distribution,
we draw the class marks of the classes on the abscissae and the frequency of the classes on the ordinates.

We know, class marks are the mean of lower and upper limit of the class intervals.

Hence, option $$C$$ is correct.
Question 3
1 / -0

According to above histogram, which group has the maximum number of workers?

A
$$810$$

B
$$820$$

C
$$830$$

D
$$840$$

Solution

From the given histogram,
$$800-810$$ rupees was given to $$3$$ workers,
$$810-820$$ rupees was given to $$2$$ workers,
$$820-830$$ rupees was given to $$1$$ workers,
$$830-840$$ rupees was given to $$9$$ workers,
$$840-850$$ rupees was given to $$5$$ workers,
$$850-860$$ rupees was given to $$1$$ workers,
$$860-870$$ rupees was given to $$3$$ workers,
$$870-880$$ rupees was given to $$1$$ workers,
$$880-890$$ rupees was given to $$1$$ workers,
$$890-900$$ rupees was given to $$4$$ workers.

Hence, $$830-840$$ rupees was given to maximum number of workers, i.e. $$9$$.

Therefore, $$830$$ group has the maximum number of workers.
Thus, option $$C$$ is correct.
Question 4
1 / -0

What is the sum of the frequencies of the intervals 40-50 and 50-60 ?

A
$$15$$

B
$$25$$

C
$$45$$

D
$$20$$

Solution

$$\Rightarrow$$ In above graph we can see, frequencies of the intervals $$40-50$$ and $$50-60$$ are $$10$$ and $$5$$.
$$\therefore$$ The sum of the frequencies of the intervals $$40-50$$ and $$50-60$$ $$=10+5=15$$
Question 5
1 / -0

Directions For Questions

...view full instructions

How many students watched TV for less than 4 hours?

A
$$34$$

B
$$32$$

C
$$24$$

D
$$30$$

Solution

From the given diagram, we have
$$4$$ students watch television for $$1-2$$ hours
$$8$$ students watch television for $$2 - 3$$ hours
$$22$$ students watch television for $$3-4$$ hours
Thus, in total $$4+8+22 = 34$$ students watch television for less than $$4$$ hours
Question 6
1 / -0

What is the difference of frequencies of the intervals 30-40 and 40-50 ?

A
$$5$$

B
$$20$$

C
$$15$$

D
$$25$$

Solution

$$\Rightarrow$$ In given histogram we can see, frequencies of the class intervals $$30-40$$ and $$40-50$$ are $$25$$ and $$10$$.
$$\Rightarrow$$ Difference of frequencies of the intervals $$30-40$$ and $$40-50$$ $$=25-10=15$$

Question 7

1 / -0

Directions For Questions

...view full instructions

The number of hours for which students of a particular class watched television during holidays are shown through the given graph.

For how many hours did the maximum number of students watch TV?

$$5-6$$

$$3-4$$

$$4-5$$

$$2-3$$

Solution

Class Interval	Frequency
No. of hours	No. of Students
$$1 -2$$	$$4$$
$$2 - 3$$	$$8$$
$$3 - 4$$	$$22$$
$$4 - 5$$	$$32$$
$$5 - 6$$	$$8$$
$$6 - 7$$	$$6$$
Total-	$$80$$

The highest frequency is $$32$$, and the corresponding class interval is $$4-5$$

Hence, maximum number of students watched TV for $$4-5$$ hours,

Question 8
1 / -0

According to above histogram, how many workers earn less than $$Rs. 850$$?

A
$$30$$

B
$$20$$

C
$$10$$

D
$$40$$

Solution

From the given histogram,
$$800-810$$ rupees was given to $$3$$ workers,
$$810-820$$ rupees was given to $$2$$ workers,
$$820-830$$ rupees was given to $$1$$ workers.
$$830-840$$ rupees was given to $$9$$ workers,
$$840-850$$ rupees was given to $$5$$ workers,
$$850-860$$ rupees was given to $$1$$ workers,
$$860-870$$ rupees was given to $$3$$ workers.
$$870-880$$ rupees was given to $$1$$ workers,
$$880-890$$ rupees was given to $$1$$ workers,
$$890-900$$ rupees was given to $$4$$ workers.

Then, the number of workers who earn less than rupees $$850$$
$$=n(800)+n(810)+n(820)+n(830)+n(840)$$
$$=3+2+1+9+5=20$$.

Hence, option $$B$$ is correct.
Question 9
1 / -0

If the class intervals in a frequency distribution are $$(72 - 73.9), (74 - 75.9), (76 - 77.9), (78 - 79.9)$$ etc., then the mid-point of the class $$(74 - 75.9)$$ is

A
$$74.50$$

B
$$74.90$$

C
$$74.95$$

D
$$75.00$$

Solution

Midpoint $$= \cfrac{\text{lower limit} + \text{upper limit}}{2}$$
$$= \cfrac{74 +75.9}{2} = 74.95$$
Question 10
1 / -0

The upper limit of $$5 -12.5$$ is?

A
$$5$$

B
$$12.5$$

C
$$5$$ or $$12.5$$

D
None of these

Solution

The upper limit of the class interval is the maximum value of that interval.
Therefore, the upper limit of $$5-12.5$$ is $$12.5$$.

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Re-Attempt Weekly Quiz Competition

Statistics Test - 30

Result

Statistics Test - 30

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SHARING IS CARING

Question 1

90

105

115

120

Solution

Question 2

upper limits of the classes

lower limits of the classes

class marks of the classes

upper limits of perceeding classes

Solution

Question 3

$$810$$

$$820$$

$$830$$

$$840$$

Solution

Question 4

$$15$$

$$25$$

$$45$$

$$20$$

Solution

Question 5

$$34$$

$$32$$

$$24$$

$$30$$

Solution

Question 6

$$5$$

$$20$$

$$15$$

$$25$$

Solution

Question 7

$$5-6$$

$$3-4$$

$$4-5$$

$$2-3$$

Solution

Question 8

$$30$$

$$20$$

$$10$$

$$40$$

Solution

Question 9

$$74.50$$

$$74.90$$

$$74.95$$

$$75.00$$

Solution

Question 10

$$5$$

$$12.5$$

$$5$$ or $$12.5$$

None of these

Solution

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