Statistics Test

Result

Statistics Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

In the graph you can find the takings of a chocolate bar for $$8$$ months.
Answer the following question:
What is the average chocolate bars taken out from the month January to May?

A
$$23000$$

B
$$35000$$

C
$$50000$$

D
$$42000$$

Solution

From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$.

Then, Average of chocolate bars taken out $$=$$ $$\dfrac{50000 + 40000+35000+45000+40000}{5}$$
$$=$$ $$\dfrac{210000}{5}$$ $$= 42000$$.

Therefore, $$42000$$ chocolate bars are taken out from the month January to May.
Hence, option $$D$$ is correct.
Question 2
1 / -0

The architecture student counted the number of bricks in each building in his neighbourhood. How many buildings are there in the interval $$6-20$$?

A
$$2$$

B
$$6$$

C
$$10$$

D
$$14$$

Solution

Number of buildings in interval $$6-10=2$$
Number of buildings in interval $$11-15=2$$
Number of buildings in interval $$16-20=6$$.

Therefore, the total number of buildings in $$6-20=2+2+6$$ $$=10$$.

Hence, option $$C$$ is correct.
Question 3
1 / -0

Use the histogram and find the sum of the number of students studying for $$4 - 5$$ and $$8 - 9$$ hours.

A
5

B
8

C
4

D
2

Solution

From the histogram,
The number of students studying for $$4 - 5$$ $$= 5 $$.
The number of students studying for $$6 - 7$$ $$= 4 $$.
The number of students studying for $$8 - 9$$ $$= 3 $$.

Therefore, the sum of the number of students studying for $$4 - 5$$ and $$8 - 9$$ hours $$= 5 + 3 = 8$$.

Hence, option $$B$$ is correct.
Question 4
1 / -0

In the graph you can find the takings of a chocolate bar for $$8$$ months.
Answer the following question:
Find the percent increase from May to June.

A
$$10\%$$

B
$$25\%$$

C
$$30\%$$

D
$$50\%$$

Solution

From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$.

$$\therefore$$ Percent increase for month May and June $$=$$ $$\dfrac{50000-40000}{40000}\times 100\%$$ $$= 25\%$$.

Hence, option $$B$$ is correct.
Question 5
1 / -0

In the graph you can find the takings of a chocolate bar for $$8$$ months. Answer the following question
Identify in which two months $$50000$$ chocolate bars are taken out?

A
Jan and Feb

B
Jun and Jul

C
Jan and Jun

D
Feb and Mar

Solution

From the given frequency polygon,
Number of chocolates taken in Jan $$=50000$$
Number of chocolates taken in Feb $$=40000$$
Number of chocolates taken in Mar $$=35000$$
Number of chocolates taken in Apr $$=45000$$
Number of chocolates taken in May $$=40000$$
Number of chocolates taken in June $$=50000$$
Number of chocolates taken in Jul $$=60000$$
Number of chocolates taken in Aug $$=60000$$.

Clearly, we can say Jan and June months shows the same number of chocolates, i.e. $$50000$$ chocolates.
So, in the months of Jan and June, $$50000$$ chocolate bars are taken out.

Hence, option $$C$$ is correct.
Question 6
1 / -0

The histogram shows the age groups of working women in a city. Find the number of working women in the age group of $$29 - 34$$ years.

A
$$300$$

B
$$230$$

C
$$320$$

D
$$410$$

Solution

From the histogram, the number of working women in the age group:
$$23 - 24$$ years is $$= 120$$
$$25 - 26$$ years is $$=80$$
$$27 - 28$$ years is $$= 110$$
$$29 - 30$$ years is $$= 90$$
$$31 - 32$$ years is $$= 100$$
$$33 - 34$$ years is $$= 130$$.

Therefore, the number of working women in the age group of $$29 - 34$$ years $$= 90 + 100 + 130 = 320$$.

Hence, option $$C$$ is correct.
Question 7
1 / -0

In which frequency polygon is best suitable for the following table.
Month
Jun.
Jul.
Aug.
Sep.
Oct.
Number of burgers sold
100
400
300
500
200

A

B

C

D

Solution

We know, the frequency polygon is formed by joining the mid-points of each upper sides of adjacent rectangles of the histogram by line segments.

To draw the frequency polygon of the given data:
Step 1: The heights of the bars in the histograms indicate the number of burgers sold.
Step 2: Observe the heights of the bars in the histograms to match with the given values.
Step 3: Compute the midpoints of the bars and draw the lines along these midpoints.
Step 4: Frequency polygon of this data will be as follows.

Therefore, option $$A$$ represents the frequency polygon for the given data.
Question 8
1 / -0

Find the arithmetic mean of $$\dfrac {1}{2}, \dfrac {1}{3}, 2n$$ and $$m$$.

A
$$\dfrac {5 + 12n + 6m}{24}$$

B
$$\dfrac {5 + 8n + 4m}{24}$$

C
$$\dfrac {5 + 2n + m}{4}$$

D
$$\dfrac {5 + 12n + 6m}{6}$$

E
$$\dfrac {5 + 2n + m}{12}$$

Solution

The arithmetic mean of $$\dfrac {1}{2}, \dfrac {1}{3}, 2n, m$$ is
$$\dfrac { \dfrac { 1 }{ 2 } +\dfrac { 1 }{ 3 } +2n+m }{ 4 } $$
$$=\dfrac { \dfrac { 5 }{ 6 } +2n+m }{ 4 } $$
$$=\dfrac { 5+12n+6m }{ 24 } $$
Question 9
1 / -0

Brian got grades of $$92,89$$ and $$86$$ on his first three math tests. What grade must he get on his final test to have an overall average of $$90$$?

A
90

B
93

C
87

D
85

Solution

Let the grade he got on final test be $$x$$
The average of all four grades is $$90$$.
So, we have $$\dfrac {(92+89+86+x)}{4}=90$$
$$\Rightarrow x = 360-267 = 93$$
Question 10
1 / -0

Which year did the same number of boys and girls attend the conference?

A
1995

B
1996

C
1997

D
1998

E
None