Statistics Test

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Statistics Test - 38

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Weekly Quiz Competition

Question 1
1 / -0

Consider the following statements in respect of a histogram:
1. The histogram consists of vertical rectangular bars with a common base such that there is no gap between consecutive bars.
2. The height of the rectangle is determined by the frequency of the class it represents.
Which of the statement given above is/are correct?

A
$$1$$ only

B
$$2$$ only

C
Both $$1$$ and $$2$$

D
Neither $$1$$ nor $$2$$
Solution
The above graph shows a histogram.
The histogram consists of vertical rectangular bars with a common base such that there is no gap between consecutive bars.
The area of the rectangle represents the frequency of the corresponding class interval unlike the bar graph where the height represents the frequency
$$\Rightarrow$$ Only statement 1 is true
Question 2
1 / -0

The two types of the statistical data are ______ data and secondary data.

A
presentation data

B
Primary data

C
personal data

D
None of the above
Question 3
1 / -0

The mean of $$48, 27, 36, 24, x$$, and $$2x$$ is $$37.x =$$

A
$$13\dfrac {1}{3}$$

B
$$16\dfrac {2}{3}$$

C
$$29$$

D
$$33\dfrac {3}{4}$$

E
$$40$$

Solution

Mean $$=$$ $$\dfrac{sum \quad of \quad no.}{total \quad no}$$
$$\Rightarrow 37=\dfrac{48+27+36+24+x+2x}{6}$$
$$\Rightarrow 135+3x=222$$
$$\Rightarrow 3x=222-135$$
$$\Rightarrow 3x=87$$
$$\Rightarrow x=\dfrac{87}{3}=29$$
Question 4
1 / -0

Directions For Questions

Study the bar chart and answer the questions.

...view full instructions

The difference in the sales of cellular phones for the years $$1997$$ and $$1999$$ is?

A
$$500$$ units

B
$$1,000$$ units

C
$$5,000$$ units

D
$$18,000$$ units

Solution

The given graph shows the sale of cellular phones in the years $$1997, 1998, 1999, 2000,2001$$ and $$2002$$.

In the year $$1997$$, the sale of cellular phones is $$48000$$.
In the year $$1999$$, the sale of cellular phones is $$30000$$.

Therefore, the difference in the sales of cellular phones for the year $$1997$$ and $$1999$$ is,
$$48000-30000=18000$$

Hence, the difference in the sales of cellular phones for the year $$1997$$ and $$1999$$ is $$18,000$$ units.
Thus, option $$D$$ is correct.
Question 5
1 / -0

The average of six numbers is 4. If the average of two of those numbers is 2, what is the average of the other four numbers?

A
5

B
6

C
7

D
8

E
9

Solution
Question 6
1 / -0

Directions For Questions

Jerry measured the temperature at 2 p.m. at the same spot in his garden and recorded his results to the nearest degree ($$^oF$$) for each day in the year. The results are shown in the histogram:

...view full instructions

On approximately, the number pf days with more than $$70^oF$$ temperature is ____.

A
Approx. $$12$$

B
Approx. $$39$$

C
Approx. $$93$$

D
None of these

Solution

Given histogram shows the number of days with temperature.
From the graph, we can observe that number of days with more than $$70^0F$$ is $$26+13=39$$ approx.
Question 7
1 / -0

The range of the following data is:
$$84,56,39,45,54,39,56,54,84,21,77,56$$

A
$$55$$

B
$$56$$

C
$$58.5$$

D
$$63$$

Solution

Range of a data is the difference between the smallest and the largest number in the data.
In the guven data:
Smallest number $$=21$$
Largest number $$=84$$
Hence, Range $$={84-21}=63$$
Question 8
1 / -0

For a collection of $$11$$ items, sum of all items is $$132$$, then the arithmetic mean is.

A
$$11$$

B
$$12$$

C
$$14$$

D
$$13$$

Solution
Question 9
1 / -0

Find the mean of the first five prime numbers.

A
3.3

B
7.8

C
5.6

D
12.1

Solution

First five prime numbers are $$2, 3, 5, 7$$ and $$11.$$
Number of observations $$=5$$
$$Mean=\dfrac{Sum\,of\,the\,numbers}{No.\,of\,observations}$$
$$=\dfrac{2+3+5+7+11}{5}$$
$$=\dfrac{28}{5}$$
$$=5.6$$
Question 10
1 / -0

The average of five numbers is $$40$$ and the average of another six numbers is $$50$$. The average of all numbers taken together is _______.

A
$$44.44$$

B
$$45.00$$

C
$$45.45$$

D
$$90.00$$

Solution

The average of five numbers is 40 , so the total of these five numbers will be 5x40.
The average of another six numbers is 50 , so the total of these six numbers will be 6x50.
Therefore, the average of all these taken together will be
$$= \dfrac{( 200+ 300)}{5+6}$$
$$= \dfrac{500}{11 }$$
$$= 45.45 $$

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Re-Attempt Weekly Quiz Competition

Statistics Test - 38

Result

Statistics Test - 38

Score

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Rank

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SHARING IS CARING

Question 1

$$1$$ only

$$2$$ only

Both $$1$$ and $$2$$

Neither $$1$$ nor $$2$$

Solution

Question 2

presentation data

Primary data

personal data

None of the above

Question 3

$$13\dfrac {1}{3}$$

$$16\dfrac {2}{3}$$

$$29$$

$$33\dfrac {3}{4}$$

$$40$$

Solution

Question 4

$$500$$ units

$$1,000$$ units

$$5,000$$ units

$$18,000$$ units

Solution

Question 5

5

6

7

8

9

Solution

Question 6

Approx. $$12$$

Approx. $$39$$

Approx. $$93$$

None of these

Solution

Question 7

$$55$$

$$56$$

$$58.5$$

$$63$$

Solution

Question 8

$$11$$

$$12$$

$$14$$

$$13$$

Solution

Question 9

3.3

7.8

5.6

12.1

Solution

Question 10

$$44.44$$

$$45.00$$

$$45.45$$

$$90.00$$

Solution

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