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Coordinate Geometry Test - 28

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Coordinate Geometry Test - 28
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  • Question 1
    1 / -0
    Abscissa of a point is positive in
    Solution
    $$\textbf{Step -1: Observing the X-Y graph.}$$
                    $$\text{We can divide the X-Y graph into 4 quadrants where }$$
                    $$\text{x- +ve and y-+ve}\implies \text{1st quadrant}$$
                    $$\text{x- -ve and y- +ve}\implies \text{2nd quadrant}$$
                    $$\text{x- -ve and y- -ve}\implies \text{3rd quadrant}$$
                    $$\text{x-+ve and y- - ve}\implies \text{4th quadrant}$$
    $$\textbf{Step -2: Finding points with positive abscissa}$$                
                    $$\text{On observing the graph we can see that the x-coordinate of a point is positive in the  }I $$
                    $$\text{ and }IV \text{ quadrants}$$
    $$\textbf{Hence, the abscissa of a point is positive in the }\mathbf{I \text{ and } IV \text{ quadrants .} }$$
  • Question 2
    1 / -0
    If y - coordinate of a point is zero, then this point always lies
    Solution
    We know that if y - coordinate of a point, i.e ...., ordinate is zero, then this point always lies on x - axis.
    Hence, $$\left(C\right)$$ is the correct answer.
  • Question 3
    1 / -0
    If $$P \left(-1,1\right), Q \left(3,-4\right), R \left(1,-1\right), S \left(-2,-3\right)$$ and $$T \left(-4,4\right)$$ are plotted on the graph paper, then the points in the fourth quadrant are:
    Solution
    We know that quadrant $$IV$$ consists of all the points $$\left(x,y\right)$$ for which x is positive and y negative, So, the points in the fourth quadrants are $$Q \left(3,-4\right) \, and \, R \left(1, -1\right)$$.
    Hence, $$\left(B\right)$$ is the correct answer.
  • Question 4
    1 / -0
    Point $$\left(0, -7\right)$$ lies
    Solution
    In Point $$\left(0,-7\right)$$ co-ordinate of x - axis is zero so it lies on y - axis.
    Hence, $$\left( C\right)$$ is the correct answer.
  • Question 5
    1 / -0
    Point $$\left(-3,5\right)$$ lies in the 
    Solution
    Every point on second quadrant has value of abscissa  negative and its ordinate is positive.
    Point $$\left(-3,5\right)$$ has abscissa is negative and ordinate is positive. So, it lies in the second quadrant.
     Hence, $$\left(B\right)$$ second quadrant, is the correct answer.
  • Question 6
    1 / -0
    If $$P \left(5, 1 \right), Q \left(8,0\right), R \left(0,4\right), S \left(0,5\right)$$ and $$ O \left(0,0 \right)$$ are plotted on the graph paper, then the point $$\left(s\right)$$ on the x - axis are
    Solution
    We now that, a point lies on X - axis, if its y - coordinate is zero.
    So, the points on the axis are Q(8,0)Q(8,0) is the correct answer.
  • Question 7
    1 / -0
    Which of the points $$P \left(0,3\right), Q \left(1,0\right),R \left(0,-1\right),S \left(-5,0\right),T \left(1,2\right)$$ do not lie on the x - axis ?
    Solution
    We know that a point on the a-axis has always its ordinate equal to $$0$$. So, the points which do not lies the x - axis are $$P \left(0,3\right),R \left(0,-1\right) \, and\, T \left(1,2\right)$$.
    Hence, $$\left(C\right)$$ is the correct answer.
  • Question 8
    1 / -0
    The point whose ordinate is $$4$$ and which lies on y - axis is 
    Solution

    $${\textbf{Step  -  1 : Apply properties of y axis}}{\text{.}}$$

                         $${\text{We know that any point, suppose }}\left( {{x,y}} \right){\text{ on Y axis will have }x = 0}{\text{. }}$$

                         $${\text{hence, any point on Y axis will be in the form of }}\left( {0,{y}} \right).$$

    $${\textbf{Step  -  2 : Determine the point}}{\text{.}}$$

                          $${\text{So given that the  ordinate is 4}}{\text{.}}$$

                          $${\text{To be on Y axis it must be of form }}\left( {0,{y}} \right).$$

                          $${\text{So simply the point will be }}\left( {0,4} \right)$$

    $${\textbf{Hence, the point with ordinate 4 and on Y axis is }} \mathbf{ \left({0,4} \right).}$$

     

  • Question 9
    1 / -0
    The point which lies on y - axis at a distance of $$5$$ units in the negative direction of y - axis is:
    Solution
    Given the point lies on Y-axis this shows that its x - coordinate is zero. Also, it is at a distance of $$5$$ units in the negative direction of Y - axis, so its y - coordinate is negative. Hence, the required point is  $$\left(0,-5\right)$$.
    Hence, $$\left(A\right)$$ is the correct answer.
  • Question 10
    1 / -0
    Abscissa of a point is positive in
    Solution
    A coordinate is an ordered pair of numbers in which the first number is the abscissa i.e. the measurement along the $$X$$ axis.
    The signs of the coordinates in the first quadrant is $$(+,+)$$,
    the second quadrant is $$(-,+)$$,
    the third quadrant is $$(-,-)$$,
    fourth quadrant is $$(+,-)$$.
    So, the abscissa of the point is positive in the first and fourth quadrant. 

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