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Coordinate Geometry Test - 28

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Coordinate Geometry Test - 28
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  • Question 1
    1 / -0
    Abscissa of a point is positive in
    Solution
    Step -1: Observing the X-Y graph.\textbf{Step -1: Observing the X-Y graph.}
                    We can divide the X-Y graph into 4 quadrants where \text{We can divide the X-Y graph into 4 quadrants where }
                    x- +ve and y-+ve    1st quadrant\text{x- +ve and y-+ve}\implies \text{1st quadrant}
                    x- -ve and y- +ve    2nd quadrant\text{x- -ve and y- +ve}\implies \text{2nd quadrant}
                    x- -ve and y- -ve    3rd quadrant\text{x- -ve and y- -ve}\implies \text{3rd quadrant}
                    x-+ve and y- - ve    4th quadrant\text{x-+ve and y- - ve}\implies \text{4th quadrant}
    Step -2: Finding points with positive abscissa\textbf{Step -2: Finding points with positive abscissa}                
                    On observing the graph we can see that the x-coordinate of a point is positive in the  I\text{On observing the graph we can see that the x-coordinate of a point is positive in the  }I
                     and IV quadrants\text{ and }IV \text{ quadrants}
    Hence, the abscissa of a point is positive in the I and IV quadrants .\textbf{Hence, the abscissa of a point is positive in the }\mathbf{I \text{ and } IV \text{ quadrants .} }
  • Question 2
    1 / -0
    If y - coordinate of a point is zero, then this point always lies
    Solution
    We know that if y - coordinate of a point, i.e ...., ordinate is zero, then this point always lies on x - axis.
    Hence, (C)\left(C\right) is the correct answer.
  • Question 3
    1 / -0
    If P(1,1),Q(3,4),R(1,1),S(2,3)P \left(-1,1\right), Q \left(3,-4\right), R \left(1,-1\right), S \left(-2,-3\right) and T(4,4)T \left(-4,4\right) are plotted on the graph paper, then the points in the fourth quadrant are:
    Solution
    We know that quadrant IVIV consists of all the points (x,y)\left(x,y\right) for which x is positive and y negative, So, the points in the fourth quadrants are Q(3,4)andR(1,1)Q \left(3,-4\right) \, and \, R \left(1, -1\right).
    Hence, (B)\left(B\right) is the correct answer.
  • Question 4
    1 / -0
    Point (0,7)\left(0, -7\right) lies
    Solution
    In Point (0,7)\left(0,-7\right) co-ordinate of x - axis is zero so it lies on y - axis.
    Hence, (C)\left( C\right) is the correct answer.
  • Question 5
    1 / -0
    Point (3,5)\left(-3,5\right) lies in the 
    Solution
    Every point on second quadrant has value of abscissa  negative and its ordinate is positive.
    Point (3,5)\left(-3,5\right) has abscissa is negative and ordinate is positive. So, it lies in the second quadrant.
     Hence, (B)\left(B\right) second quadrant, is the correct answer.
  • Question 6
    1 / -0
    If P(5,1),Q(8,0),R(0,4),S(0,5)P \left(5, 1 \right), Q \left(8,0\right), R \left(0,4\right), S \left(0,5\right) and O(0,0) O \left(0,0 \right) are plotted on the graph paper, then the point (s)\left(s\right) on the x - axis are
    Solution
    We now that, a point lies on X - axis, if its y - coordinate is zero.
    So, the points on the axis are Q(8,0)Q(8,0) is the correct answer.
  • Question 7
    1 / -0
    Which of the points P(0,3),Q(1,0),R(0,1),S(5,0),T(1,2)P \left(0,3\right), Q \left(1,0\right),R \left(0,-1\right),S \left(-5,0\right),T \left(1,2\right) do not lie on the x - axis ?
    Solution
    We know that a point on the a-axis has always its ordinate equal to 00. So, the points which do not lies the x - axis are P(0,3),R(0,1)andT(1,2)P \left(0,3\right),R \left(0,-1\right) \, and\, T \left(1,2\right).
    Hence, (C)\left(C\right) is the correct answer.
  • Question 8
    1 / -0
    The point whose ordinate is 44 and which lies on y - axis is 
    Solution

    Step  -  1 : Apply properties of y axis.{\textbf{Step  -  1 : Apply properties of y axis}}{\text{.}}

                         We know that any point, suppose (x,y) on Y axis will have x=0{\text{We know that any point, suppose }}\left( {{x,y}} \right){\text{ on Y axis will have }x = 0}{\text{. }}

                         hence, any point on Y axis will be in the form of (0,y).{\text{hence, any point on Y axis will be in the form of }}\left( {0,{y}} \right).

    Step  -  2 : Determine the point.{\textbf{Step  -  2 : Determine the point}}{\text{.}}

                          So given that the  ordinate is 4.{\text{So given that the  ordinate is 4}}{\text{.}}

                          To be on Y axis it must be of form (0,y).{\text{To be on Y axis it must be of form }}\left( {0,{y}} \right).

                          So simply the point will be (0,4){\text{So simply the point will be }}\left( {0,4} \right)

    Hence, the point with ordinate 4 and on Y axis is (0,4).{\textbf{Hence, the point with ordinate 4 and on Y axis is }} \mathbf{ \left({0,4} \right).}

     

  • Question 9
    1 / -0
    The point which lies on y - axis at a distance of 55 units in the negative direction of y - axis is:
    Solution
    Given the point lies on Y-axis this shows that its x - coordinate is zero. Also, it is at a distance of 55 units in the negative direction of Y - axis, so its y - coordinate is negative. Hence, the required point is  (0,5)\left(0,-5\right).
    Hence, (A)\left(A\right) is the correct answer.
  • Question 10
    1 / -0
    Abscissa of a point is positive in
    Solution
    A coordinate is an ordered pair of numbers in which the first number is the abscissa i.e. the measurement along the XX axis.
    The signs of the coordinates in the first quadrant is (+,+)(+,+),
    the second quadrant is (,+)(-,+),
    the third quadrant is (,)(-,-),
    fourth quadrant is (+,)(+,-).
    So, the abscissa of the point is positive in the first and fourth quadrant. 

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