Triangles Test ...

In $$\triangle ABC$$ and $$\triangle DEF$$, $$AB = FD$$ and $$\angle A = \angle D.$$ The two triangles will be congruent by $$SAS$$ axiom, if:

The construction of a triangle $$ABC$$, given that $$BC =$$ $$6$$ cm, $$B =$$ $$45 ^{\circ}$$ is not possible when difference of $$AB$$ and $$AC$$ is equal to:

Two sides of a triangle are of lengths $$4$$ cm and $$1.5$$ cm. The length of the third side of the triangle cannot be

In $$\Delta ABC, \angle A=100^0, \angle B=30^0$$ and $$\angle C=50^0$$ then

In $$\Delta PQR$$, $$\angle P =$$$$ 70^{\circ}$$ and $$\angle R = 30^{\circ}.$$ Which side of this triangle is the longest? 

If in two triangles $$\Delta ABC$$ and $$\Delta PQR$$, $$AB = QR, BC = PR$$ and $$CA = PQ,$$ then :

In the above figure, if OA $$=$$ OB, OD $$=$$ OC then $$\Delta AOD \cong  \Delta BOC$$ by congruence rule :

In $$\Delta ABC\, \angle A=50^{\circ} $$and$$ \, \angle B=60^{\circ}  $$. By arranging the sides of the triangle in ascending order, we get :

In $$\Delta ABC, \angle A=100^{\circ}, \angle B=30^{\circ}$$ and $$\angle C= 50^{\circ}$$,then

T is a point on side QR of $$\Delta$$ PQR. "S" is a point such that $$RT = ST.$$ then