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Areas of Parallelograms and Triangles Test - 1

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Areas of Parallelograms and Triangles Test - 1
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  • Question 1
    1 / -0

    The median of a triangle divides it into two

    Solution

    Explanation:

    The median of a triangle divides it into two triangles of different areas.

    If in a triangle ABC, AD is a median, then

    Area of triangle ABD = Area of triangle ACD.

     

     

  • Question 2
    1 / -0

    The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is

    Solution

    Explanation:

    Since the figure obtained by joining the mid-points of the adjacent sides of a rhombus is rectangle, then

    Side of rectange = PQ = 1/2AC

    [Mid-point theorem]

    =>     PQ = 1/2 x 16 = 8 cm

    Similarly, QR = 1/2 x 12 = 6 cm

    Therefore, Area of rectangle PQRS = PQ x QR = 8 x 6 = 48 cm2

    The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 16 cm and 12 cm is a rectangle with are 48 sq. cm.

     

  • Question 3
    1 / -0

    The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm is

    Solution

    Explanation:

    Since figure obtained by joining the mid-points of the adjacent sides of a rectange is a rhombus.

    Then diagonals of the rhombus PQRS are QS and PR i.e., sides of rectangle ABCD.

    Therefore, QS = 8 cm and PR = 6 cm

    Now, Area of rhombus PQRS = 1/2x QS x PR = 1/2x 8 x 6 = 24 cm2

    The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm is a rhombus with area 24 sq. cm.

     

     

     

  • Question 4
    1 / -0

    ABCD is quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD

    Solution

    Explanation:

    ABCD is quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD can be either a rhombus or a rectangle or a parallelogram.

    Therefore, it needs not be any of (a), (b) or (c).

     

     

  • Question 5
    1 / -0

    Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is

    Solution

    Explanation:

    Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is 1 : 1.

    Becasue when two parallelogram are on same base and between the same parallels, then the areas of both parallelograms are equal.

     

     

  • Question 6
    1 / -0

    The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to

    Solution

     

    Explanation:

    Mid-point theorem says that the mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to 

    1/2 × area (ΔABC).

  • Question 7
    1 / -0

    If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the area of the parallelogram is

    Solution

    Explanation:

    If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the area of the parallelogram is 1 : 2.

    Area of triangle = 1/2x Area of parallelogram

    =>Area of triangle : Area of parallelogram = 1 : 2

     

     

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