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Structure of the Atoms Test - 35

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Structure of the Atoms Test - 35
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  • Question 1
    1 / -0
    What do you think would be the observation if the α\alpha-particle scattering experiment is carried out using a foil of a metal other than gold?
    Solution
    If α\alpha -particle scattering experiment is carried out using a foil of any metal as thin as gold foil used by Rutherford, there would be no change in observations. But since other metals are not so malleable so, such a thin foil is difficult to obtain. If we use a thick foil, then more α-particles would rebound.

    Hence, the correct option is DD
  • Question 2
    1 / -0
    This diagram represents the atomic structure of which element?

    Solution
    The total number of electrons present in carbon is 6. The distribution of electrons in carbon atom is given by: 
    First orbit or K shell =2(2n2=2×1=2) =\displaystyle 2\left( 2{ n }^{ 2 }=2\times 1=2 \right) 
    Second orbit or L shell =4 (62=4)\displaystyle = 4\ (6-2=4)
  • Question 3
    1 / -0
    The following diagram represents the atomic structure of which element?

    Solution
    The total number of electrons present in fluorine is 9. The distribution of electrons in fluorine atom is given by:
    First orbit or K shell = 2(2n2=2×1=2)=\displaystyle 2\left( 2{ n }^{ 2 }=2\times 1=2 \right)
    Second orbit or L shell =7(92=7)=\displaystyle 7(9-2=7)
    Its electronic configuration will be 2,72,7

    For Chlorine, (atomic number 17), the electronic configuration will be 2,8,72,8,7
    For Carbon, (atomic number 6), the electronic configuration will be 2,42,4
    For Oxygen, (atomic number 8), the electronic configuration will be 2,62,6

    Hence option AA is correct.
  • Question 4
    1 / -0
    Which of the following statement is incorrect according to Thomson's model of an atom?
    Solution
    Thomson proposed the model of an atom be similar to that of a Christmas pudding. The electrons, in a sphere of positive charge, were like currants (dry fruits) in a spherical Christmas pudding.
    One can also think of a watermelon, the positive charge in the atom is spread all over like the red edible part of the watermelon, while the electrons are studded in the positively charged sphere, like the seeds in the watermelon.
  • Question 5
    1 / -0
    Helium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?
    Solution
    Helium has 2 neutrons. The mass of an atom is given by the sum of the masses of protons and neutrons present in the nucleus. The number of protons present in helium is 2 and, the given mass is 4. Therefore, the number of neutrons will be equal to 22 that is 42.4-2.. Hence option B is correct.
  • Question 6
    1 / -0
    Which of the following are features of Rutherford nuclear model of an atom?
    Solution
    Rutherford put forward the nuclear model of an atom, which had the following features:
    There is a positively charged center in an atom called the nucleus.
    The electrons revolve around the nucleus in circular paths.
    The size of the nucleus is very small as compared to the size of the atom.
  • Question 7
    1 / -0
    Which of the following observations were obtained from α\alpha-particle scattering experiment?
    Solution
    Ernest Rutherford performed an experiment to know the arrangement of electrons within an atom. In this experiment, fast-moving alpha particles were made to fall on a thin gold foil (100 nm thickness). The α\alpha-particles are doubly charged helium ions. It was expected that α\alpha-particles would be deflected by subatomic particles in the gold atom. Since α\alpha-particles were much heavier than protons, he did not expect to see large deflections. 
    But, the α\alpha-particle scattering experiment gave totally unexpected results.
    The following observations were made: 
    (i) Most of the fast-moving -particles passed straight through the gold foil. 
    (ii) Some of the -particles were deflected by the foil by small angles.
    (iii) Surprisingly one out of every 12000 particles appeared to rebound.
  • Question 8
    1 / -0
    Atoms react to achieve an octet in the outermost shell. This is achieved by:
    Solution
    Atoms react to achieve an octet in the outermost shell. This can be done by sharing, gaining or losing electrons.
  • Question 9
    1 / -0
    What is the distribution of electrons in nitrogen atom?
    Solution
    The total number of electrons present in nitrogen atom is 77.
    The distribution of electrons in nitrogen atom is given by:
    First orbit or KK shell = 2(2n2=2×11=2) =\displaystyle 2\left( 2{ n }^{ 2 }=2\times { 1 }^{ 1 }=2 \right) 
    Second orbit or LL shell =5(72=5)=\displaystyle 5 (7-2=5)
    Hence, option B is correct.
  • Question 10
    1 / -0
    What is the distribution of electrons in an oxygen atom?
    Solution
    The total number of electrons present in oxygen is 88.
    Therefore, for OO electron configuration will be 1s22s22p41s^22s^22p^4.
    The distribution of electrons in oxygen atom is given by:
    First orbit or KK shell =2(2n2=2×11=2) =\displaystyle 2\left( 2{ n }^{ 2 }=2\times { 1 }^{ 1 }=2 \right) 
    Second orbit or LL shell =6(82=6)=\displaystyle 6(8-2=6)
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