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Probability Test - 6

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Probability Test - 6
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Mean number of ' sixes' in four throws of a fair dice is
  • Question 2
    1 / -0

    A coin is tossed once. If a head comes up , then it is tossed again and if a tail comes up , a dice is thrown . The number of points in the sample space of experiment is

    Solution

    Sample Space is

    S = { HH, HT, T1, T2, T3, T4, T5, T6 }

    so number of outcomes in sample space is 8

  • Question 3
    1 / -0
    Five letters are sent to different persons and addresses on the five envelopes are written at random. The probability that all the letters reach the correct destiny is
  • Question 4
    1 / -0
    A coin with tail on both sides is tossed twice. The probability of getting ' a head' is
  • Question 5
    1 / -0
    The probability of the having atleast one tail in 4 tosses with a coin is
  • Question 6
    1 / -0
    A digit is selected at random from either of two sets {1, 2, 3, 4, 5, 6, 7, 8, 9} and {1, 2, 3, 4, 5, 6, 7, 8, 9}. What is the chance that the sum of the digits selected is 10?
  • Question 7
    1 / -0

    A cubical dice has 3 on three faces, 2 on two faces and 1 on the 6th face .It is tossed twice. The chance that both the tosses show an even number is


    Solution

    Let X denote getting an even number on each dice on throwing twice.

    By only one way it can be done by having 2 in both dice.

    Since 2 occupy two faces of dice.

    So P(getting 2 in 1st dice) = 2/6

    Also P ( getting 2 in 2nd dice) = 2/6

    So P ( getting 2 in both dice dice) = 2/6 × 2/6 = 1/9 [from multiplication theorem of probabilty P(A ∩ B) = P(A)xP(B) for any two non empty sets A, B]

  • Question 8
    1 / -0

    Three fair dice are tossed once. The probability that they show the same numbers  is


    Solution

    When three dice  are rolled, total number of outcomes =n(S)=n=63 =216

    It is given that the numbers on all the three dice are identical

    Hence the favourable outcomes are (1,1,1),(2,2,2),(3,3,3),(4,4,4),(5,5,5),(6,6,6)

    Hence no. of  favourable outcomes=m=6

    Hence required probability=mn=6/216=1/36

  • Question 9
    1 / -0

    Probability of getting a number between 1 and 100, which is divisible by 1 and itself only, is

    Solution

    the numbers which are divisible by 1 and itself are prime numbers

    Prime numbers between 1 and 100 are  2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97  . Total prime numbers 25  out of  98 numbers .

    P(Getting a number divisible by 1 and itself )=favourable out come/total no.of out comes =25/98

  • Question 10
    1 / -0

    Probability of getting a number between 1 and 100, which is divisible by 1 and itself only, is

    Solution

    the numbers which are divisible by 1 and itself are prime numbers

    Prime numbers between 1 and 100 are  2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97  . Total prime numbers 25  out of  98 numbers .

    P(Getting a number divisible by 1 and itself )=favourable out come/total no.of out comes =25/98

  • Question 11
    1 / -0
    The chance that an event E ' occurs' or ' does not occur' is
  • Question 12
    1 / -0
    A coin is tossed 6 times. The probability of getting a head three times is
  • Question 13
    1 / -0
    From a deck of 52 cards, the probability of drawing a court card is
  • Question 14
    1 / -0
    Three letters are written to different persons and addresses on the envelopes are also written. Without looking at the addresses, the letters are put into the envelopes. The probability that the letters go into right envelopes is
  • Question 15
    1 / -0
    From each of the four married couples, one of the parteners is selected at random. The probability that those selected are of the same sex is
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