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Integers Test - 6

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Integers Test - 6
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  • Question 1
    1 / -0

    Thevalue of 15×(-24)×-18-(27)×(20)is

    Solution

    Asthere are 22 negative numbers in the numerator and 11 in the denominator, theanswer will be negative. 

    Cancellingout the common factors and simplifying we get

    15×(-24)×-18-(27)×(20)=3×8×18-9×4

    =-3×2×2=-12
  • Question 2
    1 / -0

    78×.......=−78 

    Solution

    78*(-1) = -78

    Hence option d is correct.

  • Question 3
    1 / -0

    Simplifythe following:-
    (−441)÷ (21) =?

    Solution

    -44121=-21

    Hence option b is correct.

  • Question 4
    1 / -0

    Multiply:

    (−5) × 8 and 3 × (−2)

    Solution

    (−5) × 8 = −40

    3 × (−2) = − 6

    Hence, −5) × 8) × (3 × (−2 = −40 × −6 = 240

  • Question 5
    1 / -0

    −42 × x = 336, −28 × y = −84

    What is the value of x and y respectively?

    Solution

    Given, 42 × x = 336 and 28 × y = 84

    Thusx = 336-42=-8

    and y = -84-28=3

  • Question 6
    1 / -0

    32 × x = 160, 23 × y = 115

    What is the value of x ÷ y?

    Solution

    Given,-32×x=160,-23×y=-115We have x=160-32

    andy= -115-23=11523

    Thusxy=160×23-32×115=-32×2332×23=-1

  • Question 7
    1 / -0

    (−1)11value is

    Solution

    We know that if the power n of any negative integer x iseven then the resulting integer will always be positive and if the power n ofany negative integer x is odd then the resulting integer will always benegative. For example, if the negative integer is x =−2, then

    Odd power:

    (−2)3 = −2 × −2 × −2 = −8 = which is a negativeinteger.

    Even power:

    (−2)2 = −2 ×− 2 = 4 which is a positive integer.

    Similarly, (−1)11= −1 because −1 is a negativeinteger and 11 is an odd number, so the result will be a negative integer.

    Hence, (−1)11 = −1

  • Question 8
    1 / -0

    Which of the following pairs of integers have 19 as adifference?

    Solution

    Thedifference between 29, 10 is |29−10|= 19, also the difference between −29,−10is |−29−(−10)|= 19.

    Again the difference between 29, −10 is |29−(−10)|= 19.

    So option (a) and (b) are true.

  • Question 9
    1 / -0

    Solve−132÷11

    Solution

    Wecan write −132 ÷ 11 as -132×111

    Or, -13211=(-12)

    So option D is the correct answer.

  • Question 10
    1 / -0

    Multiplicationof a negative integer for even times gives a _____result

    Solution

    Multiplication 2 times: (−2) × (−2)=4

    Multiplication 4 times: (−3) × (−3) × (−3) × (−3)=9 × 9=81

    Multiplication 6 times: (−1)×(−1)×(−1)×(−1)×(−1)×(−1)=1×1×1=1

    Hence, when a negative integer is multiplied even number oftimes, the result is a positive integer.

  • Question 11
    1 / -0

    Findthe value of x in this equation: 392x=-196

    Solution

    392x=-196

    392-196=x

    x=-2

  • Question 12
    1 / -0

    Thetemperature at Bar Harbor, Maine, was −2o F. It then dropped duringthe night to be 5 times as cold. What was the temperature then?

    Solution

    Since the temperature is 5 times as cold.

    Temperature then was 5 × −2 = 10oF

  • Question 13
    1 / -0

    Themultiplicative inverse of 2−4 is

    Solution

    A reciprocal is a number obtained by interchanging numeratorand denominator. Multiplicative inverse means the same thing as reciprocal.

    The product of a number and its multiplicative inverse is 1.

    And, we have 2−4× 24 = 24−4= 1

    Thus, multiplicative inverse of 2−4 is24

  • Question 14
    1 / -0

    Whatvalue should come in place of question mark (?) in the questions given below?

    43 × 5 =?

    Solution

    43× 5 = 215

  • Question 15
    1 / -0

    (-12)× (-3) × (+4) × (-6) =

    Solution

    There are 3 negative signs. So, the resultant of 3multiplications would be negative.

    (−12) × (−3) × (+4)× (−6)= 36 × 4 × (−6)

    144 × (6) = 864

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