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Integers Test - 8

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Integers Test - 8
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  • Question 1
    1 / -0

    Evaluate:144 ÷ −12

    Solution

    The positive integer 144 can be divided by a negativeinteger −12 as follows:

    144 ÷ −12 = 14412=-12

    Hence, 144 ÷ −12 = −12

  • Question 2
    1 / -0

    Thevalue of 

    -18×53×(-10)is
    Solution

    As there is 1 negative number in the numerator and 1 in thedenominator, the answer will be positive.

    Cancelling out the common factors and simplifying we get
    -18×53×-10=3

  • Question 3
    1 / -0

    (-144)÷ (-16)

    Solution
    -144-16=9
  • Question 4
    1 / -0

    Oneinteger is greater than the other by +4. If one number is -16 then the other is_____.

    Solution

    Let the two integers be x and y. One of the integers isgiven, that is −16. So let y = −16

    Also, it is given that one integer is greater than the otherby +4. Therefore, we have:

    x – y = +4

    x− (−16) = 4

    x + 16 = 4

    x = 4 – 16

    x = −12

    Hence, the other integer is −12.

  • Question 5
    1 / -0

    Ifthe dividend s positive and divisor is with negative signs then the quotientwill be _____

    Solution

    If the dividend and divisor have unlike signs then thequotient will be Negative.

    Division of Integers is similar to the division of wholenumbers (both positive) except the sign of the quotient needs to be determined.

    If both the dividend and divisor are positive,the quotient will be positive.

    (+16) ÷ (+4) = +4

    If both the dividend and divisor are negative, the quotientwill be positive.

    (-16) ÷ (-4) = +4

    If only one of the dividend or divisor is negative, thequotient will be negative.

    (+16) ÷ (-4) = -4    or      (-16) ÷ (+4) = -4

    In other words, if the signs are the same the quotient willbe positive, if they are different, the quotient will be negative

    Hence Option B

  • Question 6
    1 / -0

    Simplify: 3 ×(−1)

    Solution

    3 ×1 = -3

  • Question 7
    1 / -0

    Theproduct of any number and "0" is ___

    Solution

    The product of any number and zero is zero.

    Theorem: 0 × a = 0 for any integer a.

    So option B is the correct answer.

  • Question 8
    1 / -0

    (148)÷(−4)=

    Solution

    (148)÷(−4)=−148÷4=−37

  • Question 9
    1 / -0

    Divide96 × (−25) by (−75) × (−16)

    Solution

    96 × (−25) ÷ (−75) × (−16)

    = − 2400 ÷ 1200

    = −2

  • Question 10
    1 / -0

    Whatvalue should come in place of question mark (?) in the questions given below?

    7290 + 290 =?

    Solution

    7290+ 290 = 7580

  • Question 11
    1 / -0

    Productof two integers is −48. If one of the integers is −6 then the other is

    Solution

    Let the other integer be x. One of the integers is giventhat is −6.

    Also, it is given that the product of the twointegers is −48. Therefore, we have:

    x×(-6)=-48
    -6x=-48
    6x=48
    x=486
    x = 08

    Hence, the other integer is +8.

  • Question 12
    1 / -0

    Solve(−9855÷27)

    Solution

    When you divide a negative number by a positive number thenthe quotient is negative. When you divide a positive number by a negativenumber then the quotient is also negative. So, in this case,

    -9855/27 = -365

    So option C is the correct answer.

  • Question 13
    1 / -0

    Ifthe dividend is positive and divisor is with negative signs then the quotientwill be_____.

    Solution

    Ifthe dividend and divisor have same signs then the quotient will be positive.

    Fore.g.- 13212=11 and -132-12=11

  • Question 14
    1 / -0

    Theproduct of two variables A and B with unlike signs is...........

    Solution

    Let 2 and -3 be the two factors.

    Clearly, 2 × -3 = −6, which is negative.

    Hence, Option B is correct.

  • Question 15
    1 / -0

    Whatis the sign of the product if we together multiply 3 negative integers and 4positive integers?

    Solution

    Multiplication of 2 negative integers results into positiveinteger.

    If we multiply 3 negative integers, then the result will benegative integer

    Now if we multiply 4 positive numbers with 3 negativeintegers we will get a negative integer because multiplication of negative andpositive integer will always result in negative integer.

    Hence option A is correct.

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