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Ratio and Proportion Test - 8

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Ratio and Proportion Test - 8
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  • Question 1
    1 / -0

    11:12__ 1:2

    Solution

    Given 11: 12 or 1: 2

    LCM for 12 and 2 is 12

    11: 12 can be written as = 11/12

    And 1:2 can bewritten as = 1/2

    1/2 × (6/6) = 6/12

    And we have 6/12

    Clearly 12 >6

    Therefore 11/12 >1/2

  • Question 2
    1 / -0

    The ratio of income to the expenditure of a family is 2:1. Find the savings if the income is Rs.400.

    Solution

    Given that income =400

    Given the ratio ofincome and expenditure = 2:1

    2x = 400

    Therefore x = 200

    Expenditure = x =Rs.200

    Savings = Income –Expenditure

    = 400 -200

    = Rs.200

  • Question 3
    1 / -0

    7 : 5 =

    Solution

    Given 7 : 5 and can be written as 7/5.

    By multiplying both numerator and denominator by 2 we equivalent-ratios

    7/5×(2/2) = 14/10

  • Question 4
    1 / -0

    An electric pole casts a shadow of length 25 meters at a time when a tree 3 meters high casts a shadowof length 5meters. Find the height of the pole.

    Solution

    Given that lengthelectric pole shadow is 25 m

    Height of the tree:Length of the shadow of tree

    Height of the pole:Length of the shadow of pole

    x: 25 = 3:5

    x = 75/5

    x = 15

    Therefore height of thepole is 15 meters

  • Question 5
    1 / -0

    Find x,

    2: 49 = x: 98

    Solution

    Given 2 : 49 = x : 98

    In proportion weknow that product of extremes = product of means

    2/49 = x/98

    On crossmultiplying

    x = (2 × 98)/49

    x = 2 x 2

    x = 4.

  • Question 6
    1 / -0

    3:1=

    Solution

    Given 3:1 and can be written as 3/1

    By multiplying bothnumerator and denominator by 9 we equivalentratios

    3/1 × (9/9) = 27/9.

  • Question 7
    1 / -0

    4 : 5 =

    Solution

    Given 4 : 5 and can be written as = 4/5

    By multiplying both numerator and denominator by we equivalent ratios

    4/5×(6/6)

    = 24/30

  • Question 8
    1 / -0

    Two numbers are respectively 40% and 10% more than a third number. Theratio of the two numbers is

    Solution

    Let the thirdnumber be z.

    First Number(140/100) x z = 14z/10

    Second Number(110/100) x z = 11z/10

    Ratio =14z/10:11z/10

    14/11.

  • Question 9
    1 / -0

    2/11= x /55, find x

    Solution

    Given 2/11 =x/55

    x = 55 x 2/11

    x = 110/11

    x = 10.

  • Question 10
    1 / -0

    Find x,

    x : 12 = 3 : 144

    Solution

    Given x : 12 = 3 : 144

    In proportion weknow that product of extremes = product of means

    x/12 = 3/144

    On crossmultiplying

    x = (3×12)/144

    x = 1/4

  • Question 11
    1 / -0

    Ifthree numbers in the ratio 1 : 3 : 1 be such that the sum of their squares is200 the middle number will be

    Solution

    Let the numbers be x, 3x and x.

    Then,

    x + 3x + x = 200

    5x = 200

    x = 200/5

    x = 40.

    Middle number = 3x

    = 3 × 40

    = 120

    Therefore, the middle number is 120.

  • Question 12
    1 / -0

    9 : 10 =

    Solution

    Given 9 : 10 and can be written as 9/10.

    By multiplying both numerator and denominator by we equivalent ratios

    9/10×(7/7)

    63/70

  • Question 13
    1 / -0

    12/20 = 9/….

    Solution

    Consider 12/20 =9/….

    Let the unknownvalue be y

    Therefore 12/20 =9/y

    On crossmultiplying we get

    y = 180/12

    Y=15

  • Question 14
    1 / -0

    Find a, if a/ 11= 11/a

    Solution

    Given a/ 11= 11/a

    a × a = 11 ×11

    a × a = 121

    a = √121

    a = 11.

  • Question 15
    1 / -0

    11 : 15 =

    Solution

    Given 11 : 15 and can be written as 11/15.

    By multiplying both numerator and denominator by 2 we equivalent ratios

    11/15×(2/2) = 22/30

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