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Profit, Loss and Discount Test - 8

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Profit, Loss and Discount Test - 8
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  • Question 1
    1 / -0

    By selling an article for₹ 92, a man gains 15%. Find the cost price of the article.

    Solution

    It is given that

    S.P. = ₹ 92

    Gain percent = 15%

    We know that

    C.P. = (S.P. × 100)/ (100 + gain percent)

    Substituting the values

    = (92 × 100)/ (100 + 15)

    = (92 × 100)/ 115

    So we get

    = ₹ 80.

  • Question 2
    1 / -0

    Find the loss or gain as percent, if the C.P.of 16articles, all of the same kind, is equal to S.P. of 20articles.

    Solution

    Consider C.P of 16 articles = S.P of 20 articles = ₹ 160

    So the C.P of 1 article = 160/16 = ₹ 10

    S.P of 1 article = 160/20 = ₹ 8

    We know that

    Loss = C.P – S.P

    Substituting the values

    = 10 – 8

    = ₹ 2

    Loss percent = (loss × 100)/ C.P

    Substituting the values

    = (2 × 100)/ 10

    = 20%

  • Question 3
    1 / -0

    C.P. = 2400, gain percent = 15%, S.P. = ?

    Solution

    Gain percent = 15%

    S.P. = [C.P. (100 + gain percent)]/ 100

    Substituting the values

    = [2400 (100 + 15)]/ 100

    So we get

    = (2400 × 115)/ 100

    = ₹ 2760

  • Question 4
    1 / -0

    S.P. = 1265, C.P. = 1100, gain % = ?

    Solution

    S.P = ₹ 1265

    We know that

    Gain = S.P – C.P

    Substituting the values

    = 1265 – 1100

    = ₹ 165

    Gain percent = (gain × 100)/ C.P

    Substituting the values

    = (165 × 100)/ 1100

    = 15%

  • Question 5
    1 / -0

    The selling price of an article is 20%of its cost price. Find the loss or the gain as percent on the whole.

    Solution

    Consider C.P = ₹ 100

    S.P = 20% of C.P

    So we get

    = 20/100 × 100

    = ₹ 20

    Loss = 100 – 20 = ₹ 80

    Loss percent = (loss × 100)/ C.P

    Substituting the values

    = 80/100 × 100%

    = 80%

  • Question 6
    1 / -0

    By selling two T.V. for ₹ 6000 each, MK gains 20 percent on one T.V. and loses20 percent on the other.

    Find:C.P. of each t.v.

    Solution

    It is given that

    S.P of first t.v. = ₹ 6000

    Gain percent = 20%

    C.P = (S.P. × 100)/ (100 + gain percent)

    Substituting the values

    = (6000 × 100)/ (100 + 20)

    = (6000 × 100)/ 120

    So we get

    = ₹ 5000

    S.P of the second t.v. = ₹ 6000

    Loss percent = 20%

    So the C.P of the other t.v. = (S.P. × 100)/(100 – loss percent)

    Substituting the values

    = (6000 × 100)/ (100 – 20)

    So we get

    = (6000 × 100)/ 80

    = ₹ 7500

    Hence, C.P of the two t.v.are ₹ 5000 and ₹ 7500.

  • Question 7
    1 / -0

    On selling a fan for ₹ 264, a profit of 10 percent is made.

    Find:cost price of the fan.

    Solution

    It is given that

    S.P. = ₹ 264

    Gain percent = 10%

    (i) C.P. = (S.P. × 100)/ (100 + gain percent)

    Substituting the values

    = (264× 100)/ (100 + 10)

    = (264 × 100)/ 110

    So we get

    = ₹ 240

  • Question 8
    1 / -0

    By selling an article for ₹ 900,a man losses an amount equal to 1/3 of its selling price. Find:the cost priceof the article.

    Solution

    It is given that

    S.P of an article = ₹ 900

    Loss = 1/3 of S.P = 1/3 × 900 = ₹ 300

    C.P = S.P + Loss

    Substituting the values

    = 900 +300

    = ₹ 1200

  • Question 9
    1 / -0

    Mangoes are bought at 4for ₹ 12.If they are sold at a profit of 33 1/3 percent, find:S.P. of 6mangoes.

    Solution

    It is given that

    C.P of 4 mangoes = ₹ 12

    Gain percent = 33 1/3 % = 100/3 %

    S.P of 4 mangoes = [C.P. (100 + gainpercent)]/ 100

    Substituting the values

    = [12 (100 + 100/3)]/ 100

    So we get

    = (12 × 400)/ (100 × 3)

    = ₹ 16

    S.P of one mango = 16/4 = ₹ 4

    S.P of 6 mangoes = 4 × 6 = ₹ 24

  • Question 10
    1 / -0

    Find the loss or gain as percent, if the C.P.of 10articles, all of the same kind, is equal to S.P. of 8articles.

    Solution

    Consider C.P of 10 articles = S.P of 8 articles = ₹ 80

    So the C.P of 1 article = 80/10 = ₹ 8

    S.P of 1 article = 80/8 = ₹ 10

    We know that

    Gain = S.P – C.P

    Substituting the values

    = 10 – 8

    = ₹ 2

    Gain percent = (gain × 100)/ C.P

    Substituting the values

    = (2 × 100)/ 8

    = 25%

  • Question 11
    1 / -0

    The cost price of an article is 20%of its selling price. Find the loss or the gain as percent on the whole.

    Solution

    Consider S.P = ₹ 100

    We know that

    C.P = 20% of S.P

    So we get

    = 20/100 × 100

    = ₹ 20

    Gain = 100 – 20 = ₹ 80

    Gain percent = (gain × 100)/ C.P

    Substituting the values

    = 80/20 × 100%

    = 400%

  • Question 12
    1 / -0

    A T.V. set is sold for ₹ 10000 at a loss of 10%.

    Find:cost price of the T.V. set.

    Solution

    It is given that

    S.P. of the T.V. set = ₹ 10000

    Loss percent = 10%

     C.P. = (S.P. × 100)/ (100 – loss percent)

    Substituting the values

    = (10000 × 100)/ (100 – 10)

    So we get

    = (10000 × 100)/ 90

    = ₹ 11111.11

  • Question 13
    1 / -0

    Lemons are bought at 20 for₹ 60. If they are sold at a profit of 33 1/3 percent, find:selling price ofeach lemon.

    Solution

    It is given that

    C.P of 20 lemons = ₹ 60

    Gain percent = 33 1/3 % = 100/3 %

    S.P of 20 lemons = [C.P. (100 + gain percent)]/ 100

    Substituting the values

    = [60 (100 + 100/3)]/ 100

    So we get

    = (60 × 400)/ (100 × 3)

    = ₹ 80

    S.P of one lemon = 80/20 = ₹ 4

  • Question 14
    1 / -0

    Find the cost price of aframe,which is sold for ₹ 405ata loss of 5%.

    Solution

    It is given that

    S.P = ₹ 405

    Loss percent = 5%

    C.P of the article = (S.P. × 100)/ (100 – loss percent)

    Substituting the values

    = (405 × 100)/ (100 – 5)

    So we get

    = (405 × 100)/ 95

    = ₹ 426.32

  • Question 15
    1 / -0

    C.P. = 8000, gain percentage = 12%, , S.P. = ?

    Solution

    Gain percent = 12%

    We know that

    S.P. = [C.P. (100 + gain percent)]/ 100

    Substituting the values

    = [8000 (100 + 12)]/ 100

    So we get

    = (8000 × 112)/ 100

    = ₹ 8960

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