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Profit, Loss and Discount Test - 9

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Profit, Loss and Discount Test - 9
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  • Question 1
    1 / -0

    100 lemons arebought for ₹ 350 and all of them are sold at the rate of ₹ 48 per dozen. Findthe profit percent or loss percent made.

    Solution

    It is given that

    C.P of one lemon = 350/100 = ₹ 3.50

    S.P of one lemon = 48/12 = ₹ 4

    Gain = 4 – 3.50 = ₹ 0.50

    Gain percent = (gain × 100)/ C.P

    Substituting the values

    = 0.50/3.50 × 100%

    = 14 (2/7) %

  • Question 2
    1 / -0

    The C.P. of 15identical articles is equal to S.P. of 12 articles. Calculatethe profit percent or loss percent made if all the articles bought have beensold.

    Solution

    It is given that

    C.P of 15 articles = S.P of 12 articles

    Consider the C.P of 15 articles = S.P of12 articles = ₹ 300

    C.P of 1 article = 300/15 = ₹ 20

    S.P of 1 article = 300/12 = ₹ 25

    Profit = S.P – C.P

    Substituting the values

    = 25 – 20

    = ₹ 5

    Profit percent = (profit × 100)/ C.P

    Substituting the values

    = (5 × 100)/ 20

    = 25%

  • Question 3
    1 / -0

    A shopkeeper marked a dinner set for ₹ 2,000.He sold it at ₹ 1800. What percentdiscount did he give?

    Solution

    It is given that

    M.P of a dinner set = ₹ 2000

    S.P of a dinner set = ₹ 1800

    So the amount of discount = 2000 – 1800 = ₹ 200

    Discount percent = (Discount × 100)/ M.P

    Substituting the values

    = (200 × 100)/ 2000

    = 10%

  • Question 4
    1 / -0

    A shopkeeper allows 4%discount on the marked price of his articles. Find the marked price of anarticle for which he charges ₹ 288.

    Solution

    Consider M.P of articles = ₹ 100

    Discount on the M.P = 4%

    S.P of articles = 100 – 4 = ₹ 96

    If S.P of articles is ₹ 96 then M.P = ₹ 100

    If S.P of articles is ₹ 288 then M.P = (100 × 288)/ 96 = ₹ 300

  • Question 5
    1 / -0

    An article is marked 20%above the cost price and sold at 10% discount. Find theprofit percent made.

    Solution

    Consider the C.P of an article = ₹ 100

    M.P of an article = 100 + 20 = ₹ 120

    Rate of discount = 10%

    S.P = [M.P (100 – Discount percent)]/ 100

    Substituting the values

    = [120 (100 – 10)]/ 100

    So we get

    = (120 × 90)/ 100

    = ₹ 108

    Profit = S.P – C.P

    Substituting the values

    = 108 – 100

    = ₹ 8

    Profit percent = (profit × 100)/ C.P

    Substituting the values

    = (8 × 100)/ 100

    = 8%

  • Question 6
    1 / -0

    A shopkeeper buys an article for ₹ 500.He increases its price by 20%. Find:the new price(marked price) of the article.

    Solution

    It is given that

    C.P of an article = ₹ 500

    Increase in price = 20%

    M.P = [C.P (100 + increase percent)]/ 100

    Substituting the values

    = [500 (100 + 20)]/ 100

    So we get

    = (500 × 120)/ 100

    = ₹ 600

  • Question 7
    1 / -0

    Abike is marked at ₹ 20000and is sold at a discount of 10%. Find the selling price of the bike.

    Solution

    It is given that

    M.P. = ₹ 20000

    Rate of discount = 10%

    So the amount of discount = 20000 × 10/100 = ₹ 2000

    S.P = M.P – discount

    Substituting the values

    = 20000 – 2000

    = ₹ 18000

  • Question 8
    1 / -0

    Rajeshsells his goods at 20% discount. Find theprice of an article which is sold for ₹ 800.

    Solution

    It is given that

    S.P of an article = ₹800

    Rate of discount = 20%

    Consider M.P of the article = ₹ 100

    S.P = 100 – 20 = ₹ 80

    If S.P of the article is ₹ 80 then M.P = ₹ 100

    If S.P of the article is ₹ 800 then M.P = (100 × 800)/ 80 = ₹ 1000

  • Question 9
    1 / -0

    A dealer buys a T.V. set for ₹ 7000.He marks it at ₹ 10000 and then gives adiscount of 20% on it. Find:the selling price of the T.V.set

    Solution

    It is given that

    C.P of a T.V. set = ₹ 7000

    M.P of a T.V. set = ₹ 10000

    Rate of discount = 20%

    So the total discount = 10000 × 20/100 = ₹ 2000

    S.P of the TV set = 10000 – 2000 = ₹ 8000

  • Question 10
    1 / -0

    20 lemons arebought at 2 for ₹ 25 and all of them aresold at 3for48. Find:C.P. of one lemon.

    Solution

    C.P of 2lemons = ₹ 25

    C.P of 20 lemons = (25 × 20)/ 2 = ₹ 250

    So the C.P of 1 lemon = 250/20 = 25/2 = ₹ 12.50

  • Question 11
    1 / -0

    The C.P. of 4pens is same as S.P. of 5 pens. Calculate theprofit or loss percent made, if all the pens bought are considered to be sold.

    Solution

    Consider C.P of 4 pens = S.P of 5 pens = ₹ 50

    C.P of 1 pen = 50/4 = ₹ 12.50

    S.P of 1 pen =50/5 = ₹ 10

    Loss = C.P – S.P

    Substituting the values

    = 12.50 – 10

    = ₹ 2.50

    Loss percent = (loss × 100)/ C.P

    Substituting the values

    = (2.50 × 100)/ 12.50

    Multiplying both numerator and denominator by 100 × 100

    = (250 × 100 × 100)/ (1250 × 100)

    = 20%

  • Question 12
    1 / -0

    A pair of shoes, marked at ₹ 400, are soldat a discount of 10percent.
    Find:the discount,

    Solution

    It is given that

    M.P of shoes = ₹ 400

    Rate of discount = 10%

    Amount of discount = (400 × 10)/ 100 = ₹ 40

  • Question 13
    1 / -0

    A car is marked at ₹ 100000.The dealer gives 5% discount on first ₹ 40000 and 2% discount onthe remaining ₹ 60000. Find:the totaldiscount.

    Solution

    It is given that

    M.P of a car = ₹ 100000

    Discount at the rate of 5% on first ₹ 40000 = (40000 × 5)/ 100 = ₹ 2000

    Discount at the rate of 2% on remaining ₹ 60000 = (60000 × 2)/ 100 = ₹ 1200

    Total discount = 2000 + 1200

    = ₹ 3200.

  • Question 14
    1 / -0

    Riteshbuysa music playerfor ₹ 250.He marks it at ₹ 320 and then gives adiscount of 10% on it. Find:the profit percent made by the Ritesh.

    Solution

    It is given that

    C.P. = ₹ 250

    M.P. = ₹ 320

    Rate of discount = 10%

    So the total discount = 320 × 10/100 = ₹ 32

    S.P of the TV set = 320 – 32= ₹ 288

    Gain = S.P – C.P

    Substituting the values

    = 288 – 250

    = ₹ 38

    Gain percent = (gain × 100)/ C.P

    Substituting the values

    = (38 × 100)/ 250

    = 76/5

    = 15 1/5 % or 15.2%

  • Question 15
    1 / -0

    A toy, marked at ₹ 500, are sold at a discount of 20percent.

    Find:the selling price of the toy.

    Solution

    It is given that

    M.P. = ₹ 500

    Rate of discount = 20%

    Amount of discount = (500 × 20)/ 100 = ₹ 100

    S.P = M.P – Discount

    Substituting the values

    = 500 100

    = ₹ 400.

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