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Weekly Quiz Competition
  • Question 1
    1 / -0

    In a society of 1250 families, 500 read news paper X, 300 read newspaper Y and 150 read both the newspapers. What is the number of families that read neither of the newspapers?

    Solution

    Let A and B denote the set of families who reads newspaper X and Y respectively.  

    Given, (A) = 500,  (B) = 300 and (A ∩ B) = 150

    Now, (A ∪ B) = (A) + (B) – (A ∩ B)

    ⇒ (A ∪ B) = 500 + 300 – 150 = 650

    ∴ Number of families who read none of the newspapers 

    = 1250 – 650 

    = 600

  • Question 2
    1 / -0

    Two finite sets A and B have x and y elements respectively. The number of elements in the power set of A is 120 more than the number of elements in the power set of B. What are the values of x and y respectively?

    Solution

    Number of elements in the power set of A = 2x

    Number of elements in the power set of B = 2y

    Given: 2x = 2y + 120

    ⇒ 2x − 2= 120

    ⇒ 2y (2x−y − 1) = 2 × 2 × 2 × 3 × 5

    ⇒ 2y (2x−y − 1) = 23 (24 −1)

    ⇒ y = 3 and x − y = 4

    ∴ x = + 4 = 3 + 4 = 7

  • Question 3
    1 / -0

    Use the following information to answer the next question.

    Three sets, AB, and C, are defined as

    A = {x: x = 5n, n ∈ N and n < 6}

    B = {y: y = 3n + 1, n ∈ N, and n ≤ 8}

    C = (z: z = 6n − 2, n ∈ N, and n ≤ 4}

    Which set is equal to the set A − (B ∩ C)?

    Solution

    A = {xx = 5nn ∈ N and n < 6} = {5, 10, 15, 20, 25}

    B = {yy = 3n + 1, n ∈ N, and n ≤ 8} = {4, 7, 10, 13, 16, 19, 22, 25}

    C = (zz = 6n − 2, n ∈ N, and ≤ 4} = {4, 10, 16, 22}

    B ∩ C = {4, 7, 10, 16, 19, 22, 25}∩ {4, 10, 16, 22} = {4, 10, 16, 22}

    Thus, A − (B ∩ C) = {5, 10, 15, 20, 25} − {4, 10, 16, 22} = {5, 15, 20, 25}

  • Question 4
    1 / -0

    Which of the following is not a set?

    Solution

    The collection of all hard working students of a particular school is not well

    defined because the criterion for determining a student as hard working may

    vary from person to person.

    Therefore, this collection is not a set.

  • Question 5
    1 / -0

    Use the following information to answer the next question.

    In a survey of 500 students in a school, 260 students preferred to watch comedy movie, 280 students preferred to watch action movie, and 20 students preferred to watch neither comedy nor action movie.

    How many students preferred to watch both the types of movies?

    Solution

    Let U be the set of all surveyed students in the School, C be the set of students preferring to watch comedy movie, and be the set of students preferring to watch action movie.

    Then, according to the given information,

    n (U) = 500, n (C) = 260, n (A) = 280, (C′ ∩ A′) = 20

    (C ∪ A)′ = 20

    ⇒ (U) − n (C ∪ A) = 20

    ⇒ 500 − n (C ∪ A) = 20

    ⇒ (C ∪ A) = 500 − 20 = 480

    It is known that, (C ∪ A) = (C) + n (A) − n (C ∩ A)

    ∴480 = 260 + 280 − n (C ∩ A)

    ⇒ n (C ∩ A) = 260 + 280 − 480 = 60

    Thus, 60 students prefer to watch both types of movies.

  • Question 6
    1 / -0

    If ∪ B = CA ∩ B = Φ and B ⊂ A then which of the following is true?

    Solution

    Given, A ∪ B = C
    ⇒ C − B = (A ∪ B) − B
    We can write (A ∪ B) − B = (A ∪ B) ∩ B

    = (A ∪ B) ∩ B

    = (A ∩ B′) ∪ (B ∩ B′)

    = (A ∩ B′) ∪ Φ

    A ∩ B

    A − B

    A                 ...(1)        [ ∵A ∩ B = Φ]

    Also, B ⊂ A

    Now, (A − B) ∪ B = (A ∩ B′) ∪ B

    = (∪ B) ∩ (B′ ∪ B)

    = (A ∪ B) ∩ U

    A ∪ B

    A                   ...(2)             [∵B ⊂ A ⇒ A ∪ B = A

    From (1) and (2), we have

    C − B = (A − B) ∪ B

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