d and f Block Test

Result

d and f Block Test - 10

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Question 1
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One or More than One Options Correct Type

Direction (Q. Nos. 1-5) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Which one of the following arrangements represent the correct order of the property stated against it?

A
Ni²⁺ < Co²⁺ < Fe²⁺ < Mn²⁺: ionic size

B
Co³⁺ < Fe³⁺ < Cr³⁺ < Sc³⁺ : stability in aqueous solution

C
Sc < Ti < Cr < Mn : number of oxidation state

D
Option A,B,C are Correct

Solution

Due to the presence of unpaired electrons, transition elements are paramagnetic in nature. Mn²⁺ contains 5 unpaired electrons while Fe²⁺ contains 4 unpaired electrons.
Manganese exhibits all the oxidation states from + 2 to + 7.
Question 2
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The metals present in German silver alloy are

A
Cu

B
Zn

C
Ni

D
Option A,B,C are Correct

Solution

It is a copper alloy with nickel and often zinc. The usual formation is 60% copper, 20% nickel and 20% zinc.
Question 3
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Paramagnetic Curie temperature in Kelvin for iron is equal to :

A
2195

B
495

C
895

D
1095

Solution

Paramagnetic Curie temperature for iron is equal to 1095 Kelvin. Relative permeability is greater than 1 for paramagnetic material.
Question 4
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+8 oxidation state is/are shown by

A
Fe

B
Ru

C
Os

D
Option B,C are Correct

Solution

+8 oxidation state shown by Ru and Os.
Question 5
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Ions having same colour in aqueous solution are

A
Cu²⁺ and Fe²⁺

B
Ni²⁺ and Fe²⁺

C
V⁴⁺ and Cr²⁺

D
Option B,C are Correct

Solution

Ni²⁺ and Fe²⁺ have green colour and V⁴⁺ and Cr²⁺ have blue colour.
Question 6
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Comprehension Type

Direction : This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Transition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.

Q.

Which of the following exhibit colour due to charge transfer phenomenon, but not due to d-d transition?

A

B

C

D
All of these

Solution

In transition metal complexes, a change in electron distribution between the metal and a ligand give rise to charge transfer bonds.
Here, charge transfer may occur from the ligand molecular orbitals to the empty or partially filled metal d-orbitals.
Question 7
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Transition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.

Q.

Which pair of ions are expected to be diamagnetic?

A
Cu⁺ and Cu²⁺

B
Ag⁺ and Au⁺

C
Ag⁺ and Au³⁺

D
Zn²⁺ and Cu²⁺

Solution

Ag⁺ (d¹⁰ ) and Au⁺ (d¹⁰ ) are diamagnetic due to absence of unpaired number of electrons.
Question 8
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Matching List Type

Direction : Choices fo r the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Q.

Match the Column I with Column II and mark the correct option from the given codes.

A

B

C

D

Solution

(i) →(s),(ii) →(p),(iii) →(q) (iv) →(r)
Question 9
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Match the Column I with Column II and mark the correct option from the given codes.

A

B

C

D

Solution

(i) →(s), (ii) →(s), (iii) →(p),(iv) →(q)
Question 10
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Match the Column I with Column II and mark the correct option from the given codes.

A

B

C

D

Solution

Fenton ’s reagent (Fe SO₄ + H₂ O₂ ) is used for oxidising alcohol to aldehyde. Zeigler-Natta catalyst [AI(C₂ H₅ )₃ + TiCI₄ ] is used for manufacture of polythene.
(i) →(Q). (ii) →(r), (iii) →(s), (iv) →(p)
Question 11
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One Integer Value Correct Type

Direction : This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q.

Number of alloys that contain nickel among the following solder, gun metal, German silver, nichrome, monel metal, constanton, bell metal, duralumin, type metal, invar, alnico.

A
6

B
3

C
5

D
1

Solution

German silver (Cu + Zn + Ni), nichrome (Ni 60% + Cr 20% + Fe), monel metal (Cu + Ni 66%), constanton (Cu + Ni), invar (Fe + Ni), alnico (Al + Ni + Co + Cu).
Question 12
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Green vitriol is FeSO₄ .xH₂ O and white vitriol is ZnSO₄ .yH₂ O, Then, the values of x and y are

A
1

B
7

C
5

D
4

Solution

In both, xand y value is 7.
Question 13
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Oxidation state of chromium in CrO₅ is +x. Here, value of x is

A
5

B
4

C
6

D
7

Solution

4 oxygen atoms attached by peroxide linkage. So, their oxidation states are taken as -1.
Now, let the oxidation state of Cr be x.
then x + 4 x (-1) - 2 = 0
x = 6
Question 14
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Number of compounds in which metal has zero oxidation state

WO₃ ,Ni(CO)₄ , MoO₃ , Fe(CO)₅ , Cr(CO)₆ , [Pt(NH₃ )₂ CI₂ ], Co₂ (CO)₈ and Mn₂ (CO)₁₀

A
5

B
3

C
9

D
0

Solution

In metal carbonyls, metal oxidation state is zero.
Question 15
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Statement Type

Direction : This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q.

Statement l : ,Cu₂ O and Ni-DMG complex are coloured.

Statement II : It is due to charge transfer transition.

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

Colours of ,Cu₂ O and Ni-DMG complex are due to charge transfer transition.
(iv) Sodium sulphite is a reducing agent. It reduces acidified K₂ CrO₇ to chromic sulphate which is green in colour.