d and f Block Test

Result

d and f Block Test - 4

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Question 1
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One or More than One Options Correct Type

Direction (Q. Nos. 1 - 5) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Identify the pairs in which one covalent radii of elements are almost similar.

A
Nb and Ta

B
Mo and W

C
La and Lu

D
Sc and Y

Solution

Due to lanthanide contraction.
Question 2
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Which one is of the following is the lightest transition element?

A
Ti

B
Sc

C
Fe

D
Hg

Solution

The correct answer is Option B.

Sc has the lowest density (3.1 g cm −3). It is the lightest transition element.
Question 3
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Which of the following have pseudo noble gas configuration?

A
Cu²⁺

B
Zn²⁺

C
Ag⁺

D
Au³⁺

Solution

An element with pseudo noble gas configuration has 18 electrons in the highest energy level instead of 8.
Zn²⁺ (28) = 3s² , 3p⁶ , 3d¹⁰
Ag⁺ (46) = 4s² 4p⁶ 4d¹⁰
Question 4
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Which one of the following is a diamagnetic ion?

A
CO²⁺

B
Cu²⁺

C
Mn²⁺

D
Sc³⁺

Solution

The correct answer is option A,D.
About two –thirds of all metals crystallize in closest-packed arrays with coordination numbers of 12. Metals that crystallize in an HCP structure include Cd, Co, Li, Mg, Na, and Zn, and metals that crystallize in a CCP structure include Ag, Al, Ca, Cu, Ni, Pb, and Pt.
Question 5
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The pair of ions that have same electronic configuration

A
Fe²⁺ and Mn²⁺

B
Fe²⁺ and Co³⁺

C
Fe³⁺ and Co³⁺

D
V²⁺ and Cr³⁺

Solution

Both Fe²⁺ and Co³⁺ have [Ar] 3d⁶ configuration while V²⁺ and Cr³⁺ have [Ar] 3d³ .
Question 6
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Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.

Q.

Which pair of elements has nearly same atomic siz e?

A
Sc and Y

B
V and Zr

C
Zr and Hf

D
La and Y

Solution

Due to lanthanide contraction.
Question 7
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Passage

The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.

Q.

The metal with high melting point in 3d series is

A
Cu

B
Zn

C
Cr

D
Fe

Solution

The high melting point of Cr metal is attributed to the involvement of greater number of electrons from (n - 1) d in addition to ns electrons in the interatomic metallic bonding.
Question 8
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Matching List Type

Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Q.

Match the Column I with Column II and mark the correct option from codes given below.

A

B

C

D

Solution

(i) →(s), (ii) →(r), (iii) →(q), (iv) →(p)
Question 9
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Which one of the following ions exhibits colour in aqueous solution

A
Sc³⁺

B
Ni²⁺

C
Ti⁴⁺

D
Zn²⁺

Solution
Question 10
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One Integer Value Correct Type

Direction (Q. Nos. 10 - 15) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q.

The number of elements that do not have completely filled d subshell among the elements Ni, Pd, Pt, Cu, Ag, Au, Zn, Cd and Hg are

A
2

B
3

C
5

D
1

Solution

Ni has 3d⁸ 4s² and Pt has 5d⁹ 6s¹ .
Question 11
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Total spin of the electrons in a chromium atom is

A
1

B
2

C
3

D
4

Solution

Chromium has 6 unpaired electrons and hence, its spin value is - 3 or +3. Cr,

There are 6 unpaired electrons in chromium.
Question 12
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Number of electrons with l = 2 and s = 1/2 in zinc atom are

A
1

B
2

C
3

D
5

Solution

l = 2 means d-subshell. Zinc has 10 electrons ind-subshell in which 5 electrons are + 1/2 spin and 5 electrons are - 1/2.
Question 13
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Number of elements that generally do not show variable valencies Cu, Zn Au, Cd, Sc, La, Pt, Co.

A
1

B
4

C
2

D
3

Solution

Zn, Cd, Sc and La do not show variable valencies.
Question 14
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During the process of electrolytic refining of copper, some metals present as impurity settle as ‘anode mud ’These are

A
Sn and Ag

B
Pb and Zn

C
Ag and Au

D
Fe and Ni

Solution

The correct answer is option C
In Electrolytic refining, the impure metal is made to act as an anode. A strip of the same metal in pure form is used as a cathode.
They are put in a suitable electrolytic bath containing a soluble salt of the same metal.
The more basic metal remains in the solution and the less basic ones go to the anode mud.
Copper is refined using an electrolytic method.
Impurities from the blister copper deposit as anode mud which contains antimony, selenium, tellurium, silver, gold, and platinum; recovery of these elements may meet the cost of refining.
Question 15
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Statement Type

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q.

Statement I : The highest oxidation state of osmium is +8.

Statement II : Osmium is a 5-d block element.

A
Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

Osmium has the electronic configuration 5de⁶ s² . As 5d and 6s are close in energy, all the 8 electron can participate in bonding. highest oxidation state of osmium is +8 due to its ability to expand their octet by using its all 8 electrons (2 from 6s and 6 from 5d).