Coordination Compounds Test

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Coordination Compounds Test - 11

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Question 1
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Direction (Q. Nos. 1-5) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Linkage isomerism is/are shown by

A

B
CN^-

C
SCN^-

D
All are correct

Solution

Linkage isomerism occurs when two or more atoms in a monodentate ligand may function as a donor, i.e. when an ambidentate ligand is present. e.g. , CN^- and SCN^- .
Question 2
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Which is/are correct pair?

A
K [Ag(CN)₂ ] = linkage isomerism

B
[CrCI(NH₃ )₅ ]I₂ = ionisation

C
[PtCI₄ I₂ ] = geometrical

D
All are correct

Solution

K[Ag(CN)₂ ]show linkage isomerism.
[CrCI(NH₃ )₅ ] I₂ show ionisation isomerism.
[PtCI₄ I₂ ] show geometrical isomerism.
Question 3
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Coordination isomerism is/are shown by

A
[Ag(NH₃ )₂ ] [CuCI₂ ]

B
[AI(H₂ O)₆ ] [Co(CN)₆ ]

C
[Pt(NH₃ )₄ (OH)₂ ] SO₄

D
Option A,B are Correct

Solution

This type of isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex.
Question 4
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Which of the following show geometrical isomerism?

A
[Pt(NH₂ CH₂ COO)₂ ]

B
[Pt(NH₃ )(NH₂ OH)(NO₂ )(C₆ H₅ N)]

C
[Pt(NH₃ )₂ CI₂ ]

D
All are correct

Solution

Due to symmetry in the complex [Cu(NH₃ )₄ ]CI₂ , it fails to show geometrical isomerism but all others show.
Question 5
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Which of the following statements is/are correct?

A
Geometrical isomerism is not observed in complexes of CN 4 having tetrahedral geometry

B
Square planar complexes with CN 4 and 6 generally show geometrical isomerism

C
The platinumglycinato complex [Pt(gly)2] show geometrical isomerism

D
Option A,C are Correct

Solution

Geometrical isomerism is not observed in complexes of coordination number 4 having tetrahedral geometry. The platinumglycinato complex [ Pt(gly)2 show geometrical isomerism (cis and trans form).
Question 6
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Comprehension Type

Direction : This section contains a paragraph, describing theory, experiments, data etc. Two questions related to the paragraph have been given. Each has only one correct answer among the four given options (a) ,(b), (c) and (d).

Passage

Consider the following isomers of [Co(NH₃ )₄ Br₂ ]⁺ . The black sphere represents Co, grey sphere represents NH₃ and unshaded sphere represents Br.

Q.

The oxidation state and coordination number of cobalt in the complex [Co(NH₃ )₄ Br₂ ]⁺ are

A
+2 and 6

B
+3 and 6

C
+3 and - 6

D
+1and 6

Solution

For O.S:

X + 0 + 2(-1) = 1

X = 3

Coordination number is the number of molecules linked to the central atom.

Hence B is the correct answer.
Question 7
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Passage

Consider the following isomers of [Co(NH₃ )₄ Br₂ ]⁺ . The black sphere represents Co, grey sphere represents NH₃ and unshaded sphere represents Br.

Q.

Which of the structures is identical?

A
Structure (a) = structure (b) and structure (c) = structure (d)

B
Structure (a) = structure (c) and structure (b) = structure (d)

C
Structure (a) = structure (d) and structure (b) = structure (c)

D
None of the above

Solution

Structure (a) = structure (c) and, structure (b) = structure (d)
Question 8
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Matching List Type

Direction : Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.

Q.

Match the Column ! with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

[Co(NH₃ )₄ CI₂ ]⁺ exhibits geometrical isomerism.
cis-[Co(en)₂ CI₂ ]⁺ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH₃ )₅ (NO₂ )]CI₂ because of the presence of ambidentate (NO₂ ) ligand exhibit linkage isomerism. [Co(NH₃ )₆ ][Cr(CN₎ 6] exhibits coordination isomerism because here, cation and anion both are complex.

(i) →(s), (ii) →(p), (iii) →(t), (iv) →(r)
Question 9
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Match the Column I with Column II and mark the correct option from the codes given below.

A
a

B
b

C
c

D
d

Solution

(i) →(r,s), (ii) →(p,q,t), (iii) →(p,q,t), (iv) →(r,s)
Question 10
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One Integer Value Correct Type

Direction : This section contains 5 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q.

Total number of geometrical isomers for the complex [RhCI(CO)(PPh₃ )(NH₃ )] is

A
3

B
4

C
5

D
6

Solution

For a complex of the type MABCD, three geometrical isomers are possible.
Question 11
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The total number of isomers of [Co(en)₂ CI₂ ]⁺ is

A
0

B
3

C
5

D
9

Solution

The complex has cis and trans isomers. The c/s has non-superimposable mirror images. Hence, total are 3.
Question 12
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The total number of possible isomers for the complex compound [Cu^ll (NH₃ )₄ ][Pt^lI CI₄ ]

A
1

B
5

C
4

D
0

Solution

[Cu(NH₃ )₃ CI][Pt(NH₃ )CI₃ ], [Cu(NH₃ )CI₃ ][Pt(NH₃ )₃ CI]
[Cu(NH₃ )₄ ] [PtCI₄ ], [Pt(NH₃ )₄ ] [CuCI₄ ]
Question 13
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The number of geometrical isomers possible for Cr(NH₃ )₃ CI₃ are

A
0

B
9

C
8

D
2

Solution

This is [Ma₃ b₃ ] type of complex and this has two geometrical isomers called facial (fac isomer) and meridional (mer isomer).
Question 14
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For square planar complex of platinum (II), [Pt(NH₃ )(Br)(CI)py]²⁺ , how many isomeric forms are possible?

A
3

B
9

C
0

D
1

Solution

[Mabcd] type complexes exist in three isomeric forms.
Question 15
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Statement Type

Direction : This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q.

Statement I : Complexes of MX₆ and MX₅ L type do not show geometrical isomerism. Assume that X and L are unidentate.

Statement Il : Geometrical isomerism is not shown by complexes of coordination number 6.

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

MX₆ and MX₅ L type complexes do not exhibit geometrical isomerism, cis [Co(en)₂ CI₂ ]⁺ because of the absence of symmetry elements exhibit optical isomerism.
[Co(NH₃ )₅ (NO₂ )]CI₂ because of the presence of ambidentate (NO₂ ) ligand exhibit linkage isomerism. [CoNH₃ )₆ ][Cr(CN)₆ ] exhibits coordination isomerism because here cation and anion both are complex.