Self Studies

Alcohols Test - 8

Result Self Studies

Alcohols Test - 8
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0.25

     

    Consider the following reaction sequence,

    R  —OH    R —I   R —NO2  Blue

    Hence, R —OH could be

     

    Solution

     

     

    Both primary and secondary alcohols form blue solution in Victor Meyer test due to the formation of respectively nitrolic acid and pseudonitrol. Tertiary alcohols form neither, hence no blue colouration is observed.

     

     

  • Question 2
    1 / -0.25

     

    Consider the following reaction,

    The correct statement(s) concerning X and Y is/are

     

    Solution

     

     


    X neither oxidised by chromic acid nor gives iodoform.

     

     

  • Question 3
    1 / -0.25

     

    Comprehension Type

    Direction : This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

    Passage

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    The structure of X is

     

    Solution

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.

     

     

  • Question 4
    1 / -0.25

     

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    If X is treated with HCI in the presence of ZnCI2 , the major product would be

     

    Solution

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.
     

     

     

  • Question 5
    1 / -0.25

     

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    An isomer of X, Y was also found to be optically active. It showed the same reactions as X except (vi). Hence, Y is

     

    Solution

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.

    does not give iodoform test but gives all other reaction similar to X.

     

     

  • Question 6
    1 / -0.25

     

    One Integer Value Correct Type

    Direction : This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

    An organic compound X (C5 H12 O) is chiral. Also

    Q.

    How many primary hydrogens are present in X?

     

    Solution

     

     

    X is a primary alcohol as indic ated by Victor Meyer test as well as it has a chiral carbon, hence

     

     

  • Question 7
    1 / -0.25

     

    An alcohol X (C7 H16 O) gives immediate turbidity with HCI/ZnCI2 and can be resolved into enantiomers. Also X has a tertiary hydrogen. How many CH3 —groups are present in X?

     

    Solution

     

     

    Compound X satisfying the given criteria is

     

     

  • Question 8
    1 / -0.25

     

    An alcohol X (C4 H10 O3 ) is chiral and absorbs two moles of HIO4 per mole of X. How many stereoisomers exist for X?

     

    Solution

     

     

    X satisfying the given criteria is

    Hence, X has four optically active isomers.

     

     

  • Question 9
    1 / -0.25

     

    An organic compound X (C7 H16 O) gives effervescence with Na. X has both enantiomers and diastereomers. X gives yellow precipitate with alkaline iodine solution. With CrO3 - H2 SO4 , X is converted into C7 H14 O  (Y) which has enantiom ers but not diastereom ers. X on refluxing with H2 SO4 isomerises to Z which neither gives yellow precipitate with alkaline iodine nor changes colour of CrO3 - H2 SO4 . What is the minim um number of carbons that can be present in the parent chain of X ?

     

    Solution

     

     

    From the give condition, structure of X is derived to be

     

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now