Aldehydes and Ketones Test

Result

Aldehydes and Ketones Test - 3

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Weekly Quiz Competition

Question 1
1 / -0.25

Give the name of the following compound:

A
cinnamaldehyde

B
vanillin

C
salicylaldehyde

D
None of these

Solution

The correct answer is option D(None of the above)
The given compound is 4-Bromo-3methylheptanal
Question 2
1 / -0.25

Arrange the following alcohols, hydrocarbon and ether in order of their increasing boiling points Pentan –1 –ol, n –butane, pentanal, ethoxyethane.

A
n –Butane, ethoxyethane, pentanal and pentan –1 –ol.

B
pentanal and pentan –1 –ol, n –Butane, ethoxyethane

C
ethoxyethane, pentanal and pentan –1 –ol, n –Butane

D
pentan –1 –ol , n –Butane, ethoxyethane, pentanal

Solution

Alcohols have higher boiling points than aldehydes.
Question 3
1 / -0.25

The compound formed as a result of oxidation of ethyl benzene by KMnO₄ is

A
Benzophenone

B
Benzyl alcohol

C
Benzoic acid

D
Acetophenone

Solution
Question 4
1 / -0.25

Give IUPAC names of the following compound:

A
1 –Phenylpropan –1 –one

B
Phenylpropan –1 –one

C
Both A and B

D
None of these

Solution

This is 1-phenyl propan-1-one.
Question 5
1 / -0.25

The reagents to bring about the change from but –2 –ene to ethanal

A
PCC

B

C
DIBAL –H

D
None of these

Solution

Reductive Ozonolysis of alkene forms aldehyde or ketone.
Question 6
1 / -0.25

Which of the following is correct?

A
Any aldehyde gives secondary alcohol on reduction

B
Reaction of vegetable oil with H₂ SO₄ gives glycerine

C
C₂ H₅ OH, iodine with NaOH gives iodoform

D
Sucrose on reaction with NaCl give invert sugar

Solution

C₂ H₅ OH get oxidizes to CH₃ CHO and –COCH₃ group is important for iodoform.
Question 7
1 / -0.25

A strong base can abstract an α–hydrogen from

A
Alkane.

B
Amine

C
Ketone

D
Alkene

Solution

Because conjugate base that form will be stable in case of Ketone.
Question 8
1 / -0.25

Which of the following reagents can be used to convert a carboxylic acid directly into its corresponding acid chloride derivative?

A
HCl

B
NaOCl

C
CH₃ COCl

D
(COCl)₂

Solution
Question 9
1 / -0.25

The appropriate reagent for the transformation:

A
NaBH₄

B
NH₂ NH₂ , OH^-

C
Zn(Hg), HCl

D
H₂ , Ni

Solution

In this reaction, a CO group is converted to CH₂ group.
This can be achieved by Wolff-Kishner reduction which uses reagent NH₂ NH₂ , OH⁻ (hydrazine in alkaline medium).

Clemmensen reduction (Zn(Hg)/HCl) cannot be used as in presence of HCl, the alcohol may undergo dehydration.
Question 10
1 / -0.25

What compound is produced when cyclohexene is treated with concentrated KMnO₄ ?

A
adipic acid

B
succinic acid

C
hexanoic acid

D
cyclohexanecarboxylic acid

Solution

Conc KMnO₄ will cause oxidation and ring opening forming adipic acid.

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Aldehydes and Ketones Test - 3

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Aldehydes and Ketones Test - 3

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Question 1

cinnamaldehyde

vanillin

salicylaldehyde

None of these

Solution

Question 2

n –Butane, ethoxyethane, pentanal and pentan –1 –ol.

pentanal and pentan –1 –ol, n –Butane, ethoxyethane

ethoxyethane, pentanal and pentan –1 –ol, n –Butane

pentan –1 –ol , n –Butane, ethoxyethane, pentanal

Solution

Question 3

Benzophenone

Benzyl alcohol

Benzoic acid

Acetophenone

Solution

Question 4

1 –Phenylpropan –1 –one

Phenylpropan –1 –one

Both A and B

None of these

Solution

Question 5

PCC

DIBAL –H

None of these

Solution

Question 6

Any aldehyde gives secondary alcohol on reduction

Reaction of vegetable oil with H2 SO4 gives glycerine

C2 H5 OH, iodine with NaOH gives iodoform

Sucrose on reaction with NaCl give invert sugar

Solution

Question 7

Alkane.

Amine

Ketone

Alkene

Solution

Question 8

HCl

NaOCl

CH3 COCl

(COCl)2

Solution

Question 9

NaBH4

NH2 NH2 , OH-

Zn(Hg), HCl

H2 , Ni

Solution

Question 10

adipic acid

succinic acid

hexanoic acid

cyclohexanecarboxylic acid

Solution

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Reaction of vegetable oil with H₂ SO₄ gives glycerine

C₂ H₅ OH, iodine with NaOH gives iodoform

CH₃ COCl

(COCl)₂

NaBH₄

NH₂ NH₂ , OH^-

H₂ , Ni