Biomolecules Test

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Biomolecules Test - 4

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Weekly Quiz Competition

Question 1
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Which of the following B group vitamins can be stored in our body?

A
Vitamin B₁

B
Vitamin B₂

C
Vitamin B₆

D
Vitamin B₁₂

Solution

The correct answer is option D
Vitamin B₁₂
The body has a limited capacity to store most of the B-group vitamins except B₁₂ and folate, which are stored in the liver.
Question 2
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Which one of the following bases is not present in DNA?

A
Adenine

B
Thymine

C
Cytosine

D
Quinoline

Solution

Quinoline is an alkaloid, it is not present in DNA. DNA has four nitrogen bases in adenine, guanine, cytosine and thymine
Question 3
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Three cyclic structures of monosaccharides are given below which of these are anomers.

A
I and II

B
II and III

C
I and III

D
III is anomer of I and II

Solution

Structures (I and II) differ only in the position of OH at C₂ and hence are anomers.
Question 4
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Which of the following reactions of glucose can be explained only by its cyclic structure?

A
Glucose forms pentaacetate.

B
Glucose reacts with hydroxylamine to form an oxime.

C
Pentaacetate of glucose does not react with hydroxylamine.

D
Glucose is oxidised by nitric acid to gluconic acid.

Solution

Due to absence of free OH group at C₂ cyclic structure of glucose pentacetate cannot revert to open chain aldehydic form and hence cannot form an oxime.
Question 5
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Optical rotations of some compounds along with their structures are given below which of them have D configuration.

A
I, II, III

B
II, III

C
I, II

D
III

Solution

The correct answer is Option A.

I, II and III structures have D configuration with -OH group on the lowest asymmetric carbon is on the right side which is comparable to (+) glyceraldehyde.
Question 6
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Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.

A
‘a ’carbon of glucose and ‘a ’carbon of fructose.

B
‘a ’carbon of glucose and ‘e ’carbon of fructose.

C
‘a ’carbon of glucose and ‘b ’carbon of fructose.

D
‘f ’carbon of glucose and ‘f ’carbon of fructose.

Solution

The correct answer is option C
'a 'carbon of glucose and 'b 'carbon of fructose
Carbon adjacent to the oxygen atom in the cyclic structure of glucose or fructose is known as anomeric carbon. As shown in the structure above ‘a ’and ‘b ’are present adjacent to an oxygen atom. Both carbons differ in configurations of the hydroxyl group.
Question 7
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Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between C1 and C4 and which linkages are between C1 and C6?

A
(A) is between C1 and C4, (B) and (C) are between C1 and C6

B
(A) and (B) are between C1 and C4, (C) is between C1 and C6

C
(A) and (C) are between C1 and C4, (B) is between C1 and C6

D
(A) and (C) are between C1 and C6, (B) is between C1 and C4

Solution

The correct answer is Option C.

(i) The first structure is lactose, the linkage is (A) C₁ −C₄ glycosidic linkage.
(ii) The 2_nd structure has C₁ −C₆ linkages.
(iii) The 3_rd structure has C₁ −C₄ linkages.
Question 8
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Carbohydrates are classified on the basis of their behaviour on hydrolysis and also as reducing or non-reducing sugar. Sucrose is a __________.

A
monosaccharide

B
disaccharide

C
non-reducing sugar

D
Both b and c

Solution

The correct answer is D. Both b and c.
One of the common disaccharides is sucrose which on hydrolysis gives an equimolar mixture of D −(+)−glucose and D −(−) fructose. These two monosaccharides are held together by a glycosidic linkage between Cl of α- glucose and C2 of β- fructose. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a non-reducing sugar.
Question 9
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Proteins can be classified into two types on the basis of their molecular shape i.e., fibrous proteins and globular proteins. Examples of globular proteins are :
(Multiple Answer Correct)

A
Insulin & Albumin

B
Myosin

C
Keratin

D
None of these

Solution

The correct answer is A .
The structure of protein which results when the chain of polypeptides coil around to give a spherical shape are known as globular protein. These proteins are soluble in water, e.g., insulin and albumin are globular protein.
Question 10
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Which of the following carbohydrates are branched polymer of glucose?

A
Amylose

B
Amylopectin and Glycogen

C
Cellulose

D
None of these

Solution

The correct answer is option B.
Amylopectin is insoluble in water and constitutes about 80 −85% of starch. It is a branched-chain polymer of −D −glucose units in which chain is formed by C1 −C4 glycosidic linkage whereas branching occurs by C1 −C6 glycosidic linkage. Glycogen: The carbohydrates are stored in the animal body as glycogen. It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.
Question 11
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Which of the following monosaccharides are present as five membered cyclic structure (furanose structure)?

A
Ribose

B
Glucose

C
Fructose

D
Both A and C

Solution

The correct answer is option D.
It also exists in two cyclic forms which are obtained by the addition of −OH at C5 to the group. The ring, thus formed is a five-membered ring and is named as furanose with an analogy to the compound furan. Furan is a five-membered cyclic compound with one oxygen and four carbon atoms.
Question 12
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In fibrous proteins, polypeptide chains are held together by ___________.

A
van der Waals forces

B
disulphide linkage & hydrogen bonds

C
electrostatic forces of attraction

D
None of these

Solution

The correct answer are options B.
In fibrous proteins, polypeptide chains are held together by hydrogen and disulphide bonds, in parallel manner. Due to which fibre-like structure is obtained. Such proteins are generally known as fibrous proteins. These proteins are generally insoluble in water e.g., keratin, myosin.
Question 13
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Which of the following are purine bases?

A
Guanine

B
Uracil

C
Thymine

D
None of these

Solution

Correct answer is A. Guanine
Question 14
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Which of the following terms are correct about enzyme?

A
Proteins

B
Dinucleotides

C
carbohydrates

D
None of these

Solution

The correct answer is option A
Life is possible due to the coordination of various chemical reactions in living organisms. This occurs with the help of certain biocatalysts called enzymes. Almost all the enzymes are globular protein.
Question 15
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A
α-Amino acid and Basic amino acid

B
β-Amino acid

C
Amino acid synthesised in body

D
None of these

Solution

Options A is correct.
In lysine,the amino group is attached to alpha carbon which makes it alpha amino acid and it has more amino groups as compared to -COOH groups, thus basic.