Biomolecules Test

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Biomolecules Test - 6

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Weekly Quiz Competition

Question 1
1 / -0.25

Glucose reacts with acetic anhydride to form:

A
Monoacetate

B
Diacetate

C
Pentaacetate

D
Hexaacetate

Solution

It forms glucose pentaacetate. The acetic anhydride esterifies with all the alcohol groups on the glucose ring.
Question 2
1 / -0.25

What does the following reaction of glucose with HI elucidates about the structure of glucose?

A
Shows the presence of -CHO group

B
Shows the presence of C=O group

C
Shows the presence of six carbons linked linearly

D
Shows the presence of ring structure of glucose

Solution

Reaction of glucose with HI forms hexane. This reaction shows the presence of six carbons linked linearly in glucose.
Question 3
1 / -0.25

The Molisch test is a chemical test that determines the presence of:

A
All carbohydrates

B
Sucrose

C
Fructose

D
Glucose

Solution

The Molisch test uses concentrated sulphuric acid as the dehydrating acid. This acid dehydrates all carbohydrates, so the test is used to distinguish between carbohydrates and non-carbohydrates.
Question 4
1 / -0.25

What does the following reaction shows about the structure of glucose?

A
It shows the presence of carbonyl group in glucose.

B
It shows the presence of primary alcoholic group in glucose.

C
It shows the presence of ring structure in glucose.

D
none

Solution

The correct answer is Option A.

Glucose gets oxidized to cyanohydrin in reaction with HCN . This indicates that the carbonyl group is present as an aldehydic group.
Question 5
1 / -0.25

Which among the following is a non-reducing sugar?

A
Sucrose

B
Maltose

C
Lactose

D
Glucose

Solution

Non-reducing sugars do not have an OH group attached to the anomeric carbon so they cannot reduce other compounds. All monosaccharides such as glucose are reducing sugars. A disaccharide can be a reducing sugar or a non-reducing sugar. Maltose and lactose are reducing sugars, while sucrose is a non-reducing sugar.
Question 6
1 / -0.25

Which of the following carbohydrates is called an invert sugar?

A
Sucrose

B
Fructose

C
Glucose

D
Cellulose

Solution

It is called invert sugar because the angle of the specific rotation of the plain polarized light changes from a positive to a negative value due to the presence of the optical isomers of the mixture of glucose and fructosesugars.
Question 7
1 / -0.25

What is the relation between the following pairs of monosaccharides?

A
Epimers

B
Enatiomers

C
Structural isomers

D
Anomers

Solution

The pairs of optical isomers which differ in configuration around any other C atom other than C₁ atom are called epimers. D-glucose and D-mannose are C₂ epimers.
Question 8
1 / -0.25

Hydrolysis of sucrose is called:

A
Hydration

B
Inversion

C
Esterification

D
Saponification

Solution

Hydrolysis of sucrose to give glucose and fructose is called inversion. hydrolysis of sucrose brings about a change in the sign of rotation, from dextro (+) to laevo (–) and the product is named as invert sugar.
Question 9
1 / -0.25

Which of the following carbohydrate is an example of an oligosaccharide?

A
Cellulose

B
Lactose

C
Mannose

D
Glucose

Solution

Lactose intolerance is the inability to break down a type of natural sugar called lactose. Lactose is commonly found in dairy products, such as milk and yogurt. A person becomes lactose intolerant when his or her small intestine stops making enough of the enzyme lactase to digest and break down the lactose.
Question 10
1 / -0.25

Sucrose is a non-reducing sugar because:

A
The -CHO group of glucose is not involved in glycosidic bond formation.

B
Two monosaccharide units are held together by a glycosidic linkage between C₁ of α-glucose and C₂ of β-fructose.

C
On hydrolysis, sucrose gives dextrorotatory and laevorotatory and the mixture is laevorotatory.

D
Sucrose is dextrorotatory.

Solution

Sucrose is a non-reducing sugar because the two monosaccharide units are held together by a glycosidic linkage between C₁ of α-glucose and C₂ of β-fructose. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a non-reducing sugar.

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Biomolecules Test - 6

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Biomolecules Test - 6

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SHARING IS CARING

Question 1

Monoacetate

Diacetate

Pentaacetate

Hexaacetate

Solution

Question 2

Shows the presence of -CHO group

Shows the presence of C=O group

Shows the presence of six carbons linked linearly

Shows the presence of ring structure of glucose

Solution

Question 3

All carbohydrates

Sucrose

Fructose

Glucose

Solution

Question 4

It shows the presence of carbonyl group in glucose.

It shows the presence of primary alcoholic group in glucose.

It shows the presence of ring structure in glucose.

none

Solution

Question 5

Sucrose

Maltose

Lactose

Glucose

Solution

Question 6

Sucrose

Fructose

Glucose

Cellulose

Solution

Question 7

Epimers

Enatiomers

Structural isomers

Anomers

Solution

Question 8

Hydration

Inversion

Esterification

Saponification

Solution

Question 9

Cellulose

Lactose

Mannose

Glucose

Solution

Question 10

The -CHO group of glucose is not involved in glycosidic bond formation.

Two monosaccharide units are held together by a glycosidic linkage between C1 of α-glucose and C2 of β-fructose.

On hydrolysis, sucrose gives dextrorotatory and laevorotatory and the mixture is laevorotatory.

Sucrose is dextrorotatory.

Solution

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Two monosaccharide units are held together by a glycosidic linkage between C₁ of α-glucose and C₂ of β-fructose.